[PHP-DB] problem in connecting to mysql from php
Hello everyone,
I am in the process of learning php and I was trying to connect to a mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
Re: [PHP-DB] problem in connecting to mysql from php
Okay. I tried using that too. If I run this:
?php
$link = mysql_connect('localhost', 'root',
'Password123');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
echo 'Connected successfully';
mysql_close($link);
?
I get the error: *Fatal error*: Call to undefined function mysql_connect()
in *C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on
line *2
*I think there is something wrong with my configuration.
On Mon, Jun 13, 2011 at 6:00 PM, mrfroasty mrfroa...@gmail.com wrote:
Your error message is about class not found.That means there is no class
named MySQLi.Please use a textbook with online manual
http://www.php.net/manual/en/ref.mysql.php
On 06/13/2011 02:08 PM, C0mf0rtably Numb wrote:
Hello everyone,
I am in the process of learning php and I was trying to connect to a
mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
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Re: [PHP-DB] problem in connecting to mysql from php
On 13 June 2011 13:26, C0mf0rtably Numb 08.kus...@gmail.com wrote:
Okay. I tried using that too. If I run this:
?php
$link = mysql_connect('localhost', 'root',
'Password123');
if (!$link) {
die('Could not connect: ' . mysql_error());
}
echo 'Connected successfully';
mysql_close($link);
?
I get the error: *Fatal error*: Call to undefined function mysql_connect()
in *C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on
line *2
*I think there is something wrong with my configuration.
On Mon, Jun 13, 2011 at 6:00 PM, mrfroasty mrfroa...@gmail.com wrote:
Your error message is about class not found.That means there is no class
named MySQLi.Please use a textbook with online manual
http://www.php.net/manual/en/ref.mysql.php
On 06/13/2011 02:08 PM, C0mf0rtably Numb wrote:
Hello everyone,
I am in the process of learning php and I was trying to connect to a
mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
--
Extra details:
OSS:Gentoo Linux
profile:x86
Hardware:msi geforce 8600GT asus p5k-se
location:/home/muhsin
language(s):C/C++,PHP,SQL,HTML
Typo:40WPM
url:http://www.mzalendo.net
url:http://www.zanbytes.com
Copying the files to windows\system ... what files? Where were you
told to do this?
Normally the extension files you need for PHP are in C:\PHP5\ext (or PHPx).
I've never copied a single file into my Windows folder for PHP.
--
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Twitter : EE : Zend : PHPDoc
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY : bit.ly/lFnVea
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[PHP-DB] Re: problem in connecting to mysql from php
Any help?
On Mon, Jun 13, 2011 at 5:38 PM, C0mf0rtably Numb 08.kus...@gmail.comwrote:
Hello everyone,
I am in the process of learning php and I was trying to connect to a mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
Re: [PHP-DB] Re: problem in connecting to mysql from php
On 13 June 2011 14:12, C0mf0rtably Numb 08.kus...@gmail.com wrote:
Any help?
On Mon, Jun 13, 2011 at 5:38 PM, C0mf0rtably Numb 08.kus...@gmail.comwrote:
Hello everyone,
I am in the process of learning php and I was trying to connect to a mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
If you are able to reset your system and then read through the manual
Windows installation documentation at
http://uk.php.net/manual/en/install.windows.manual.php
Personally, I'd change the path to C:\PHP5,x,y, where the x and y are
the complete version numbers (PHP5.3.6) , but that's me. I then use
Junction to create C:\PHP5 which maps to C:\PHP5.3.6.
Junction is like a link at least in terms of how I use it.
I'd also take a good look at
http://uk.php.net/manual/en/install.windows.commandline.php and
http://uk.php.net/manual/en/install.windows.apache2.php
One covers making better use of PHP from the command line and the
other deals with getting things working with Apache.
And an issue. Please make sure you use the right version of PHP for
the version of Apache you are using. If you are using a VC9 build
Apache (say from ApacheLounge or something like that), then you can
use a VC9 build of PHP.
If you are using an VC6 build, then you must use a VC6 build of PHP
and that limits you to PHP5.2 (PHP5.2.17 is the latest there). I use
IIS with FastCGI so I use a NTS (non thread safe) build. I don't know
which sort of threading model you need for Apache (hopefully it is
mentioned in one of the Apache related pages).
And with regard to the php.ini file, you can make it available by many
different means.
I use the registry. This is documented at
http://uk.php.net/manual/en/configuration.file.php
Look at ...
As of PHP 5.2.0, the location of the php.ini file can be set for
different versions of PHP. The following registry keys are examined in
order: [HKEY_LOCAL_MACHINE\SOFTWARE\PHP\x.y.z],
[HKEY_LOCAL_MACHINE\SOFTWARE\PHP\x.y] and
[HKEY_LOCAL_MACHINE\SOFTWARE\PHP\x], where x, y and z mean the PHP
major, minor and release versions. If there is a value for IniFilePath
in these keys, then the first one found will be used as the location
of the php.ini (Windows only).
[HKEY_LOCAL_MACHINE\SOFTWARE\PHP], value of IniFilePath (Windows only).
And, I think finally, if you need different php.ini files for apache
and the command line, ...
If php-SAPI.ini exists (where SAPI is used SAPI, so the filename is
e.g. php-cli.ini or php-apache.ini), it's used instead of php.ini.
SAPI name can be determined by php_sapi_name().
Richard.
--
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Twitter : EE : Zend : PHPDoc
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY : bit.ly/lFnVea
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Re: [PHP-DB] Re: problem in connecting to mysql from php
On 13 June 2011 15:28, C0mf0rtably Numb 08.kus...@gmail.com wrote:
My php and apache are working fine together. I was doing good with php and
apache until I decided to work with mysql. I will have a look at all the
links you provided and see if gives me a solution. Thanks.
On Mon, Jun 13, 2011 at 7:36 PM, Richard Quadling rquadl...@gmail.com
wrote:
On 13 June 2011 14:12, C0mf0rtably Numb 08.kus...@gmail.com wrote:
Any help?
On Mon, Jun 13, 2011 at 5:38 PM, C0mf0rtably Numb
08.kus...@gmail.comwrote:
Hello everyone,
I am in the process of learning php and I was trying to connect to a
mysql
database on my own computer(localhost). I have done the following as
prerequisites:
copied the dll files in system32
removed the semicolon(;) from extension=php_mysqli.dll
In spite of doing the above when I try to run the following :
?php
$db = new MySQLi('localhost', 'root', 'Password123', 'test');
$sql = 'SELECT * FROM a123';
$result = $db-query($sql);
while($row = $result-fetch_object()) {
echo 'div' . $row-name . '/div';
}
$db-close();
?
I get the error: *Fatal error*: Class 'MySQLi' not found in *C:\Program
Files\Apache Software Foundation\Apache2.2\htdocs\a.php* on line *2
*Please guide me as to how can I get rid of this error?
Regards,
Kushal
If you are able to reset your system and then read through the manual
Windows installation documentation at
http://uk.php.net/manual/en/install.windows.manual.php
Personally, I'd change the path to C:\PHP5,x,y, where the x and y are
the complete version numbers (PHP5.3.6) , but that's me. I then use
Junction to create C:\PHP5 which maps to C:\PHP5.3.6.
Junction is like a link at least in terms of how I use it.
I'd also take a good look at
http://uk.php.net/manual/en/install.windows.commandline.php and
http://uk.php.net/manual/en/install.windows.apache2.php
One covers making better use of PHP from the command line and the
other deals with getting things working with Apache.
And an issue. Please make sure you use the right version of PHP for
the version of Apache you are using. If you are using a VC9 build
Apache (say from ApacheLounge or something like that), then you can
use a VC9 build of PHP.
If you are using an VC6 build, then you must use a VC6 build of PHP
and that limits you to PHP5.2 (PHP5.2.17 is the latest there). I use
IIS with FastCGI so I use a NTS (non thread safe) build. I don't know
which sort of threading model you need for Apache (hopefully it is
mentioned in one of the Apache related pages).
And with regard to the php.ini file, you can make it available by many
different means.
I use the registry. This is documented at
http://uk.php.net/manual/en/configuration.file.php
Look at ...
As of PHP 5.2.0, the location of the php.ini file can be set for
different versions of PHP. The following registry keys are examined in
order: [HKEY_LOCAL_MACHINE\SOFTWARE\PHP\x.y.z],
[HKEY_LOCAL_MACHINE\SOFTWARE\PHP\x.y] and
[HKEY_LOCAL_MACHINE\SOFTWARE\PHP\x], where x, y and z mean the PHP
major, minor and release versions. If there is a value for IniFilePath
in these keys, then the first one found will be used as the location
of the php.ini (Windows only).
[HKEY_LOCAL_MACHINE\SOFTWARE\PHP], value of IniFilePath (Windows only).
And, I think finally, if you need different php.ini files for apache
and the command line, ...
If php-SAPI.ini exists (where SAPI is used SAPI, so the filename is
e.g. php-cli.ini or php-apache.ini), it's used instead of php.ini.
SAPI name can be determined by php_sapi_name().
Richard.
--
Richard Quadling
Twitter : EE : Zend : PHPDoc
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY : bit.ly/lFnVea
If you have PHP working, then create the following file and save it as
info.php in the docroot of your website.
?php
phpinfo();
?
When you load this, you'll see a list of settings being reported. The
important one in this instance is the value for the loaded
configuration file near the top of the page.
That's the INI file you are needing to edit.
Open it in your favourite text editor and look for the lines starting with ...
extension=
You need to choose which mysql driver you need - there are several.
mysql
myslqi
pdo_mysql
If you are using a modern mysql, then mysqli is the one to use. So,
add a line to the INI file that looks like ...
extension=php_mysqli.dll
It may already exist with a ; in front of it. Remove the ;
Save the ini.
Restart Apache.
You MAY need to reboot Windows.
Now load up the phpinfo() page again.
Do you see mysqli content?
If you do, then at that stage, the mysqli extension is loaded and you
can start using it : http://uk.php.net/manual/en/book.mysqli.php
--
Richard Quadling
Twitter : EE : Zend : PHPDoc
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY : bit.ly/lFnVea
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[PHP-DB] Help with AVG()
Hi Everyone I am trying to figure out how to write a SELECT query that will give me the average of `bible_anagrams`.`views` starting on the date specified in `bible_anagrams_rss_feed`.`rss_feed_date` and the previous 6 calendar days (for a total of 7 days). What I am trying to figure out is the average of how many times the anagrams RSS Feed were accessed between June 1st and 7th, June 2nd and 8th, June 3rd and 9th, etc. - There is 1 row for each date in the table bible_anagrams_rss_feed. I tried the following syntax, but it is giving me an overall average, not by the date ranges: SELECT AVG(`bible_anagrams`.`views`) AS average_views FROM `bible_anagrams` INNER JOIN `bible_anagrams_rss_feed` ON `bible_anagrams`.`reference` = `bible_anagrams_rss_feed`.`bible_anagrams_reference` ORDER BY `bible_anagrams_rss_feed`.`rss_feed_date` DESC LIMIT 7 I am wanting the query I am asking help for to be included as one of the mySQL results, where I have indicated “AVERAGE VIEWS QUERY HERE” (although if there is a better way I am opening to learning it): SELECT `bible_anagrams_rss_feed`.`rss_feed_date` , `bible_anagrams`.`reference`, `bible_anagrams`.`bible_anagram_word` , `bible_anagrams`.`views` , ( AVERAGE VIEWS QUERY HERE ) AS average_views FROM `bible_anagrams_rss_feed` INNER JOIN `bible_anagrams` ON `bible_anagrams`.`reference` = `bible_anagrams_rss_feed`.`bible_anagrams_reference` ORDER BY `bible_anagrams_rss_feed`.`rss_feed_date` DESC Thanks for helping me, Ron The Verse of the Day “Encouragement from God’s Word” http://www.TheVerseOfTheDay.info
[PHP-DB] Re: Help with AVG()
you have no WHERE clause in your query. Ron Piggott ron.pigg...@actsministries.org wrote in message news:F6C4EF096B4446CA8AECD201C1E86C39@RonPiggottPC... Hi Everyone I am trying to figure out how to write a SELECT query that will give me the average of `bible_anagrams`.`views` starting on the date specified in `bible_anagrams_rss_feed`.`rss_feed_date` and the previous 6 calendar days (for a total of 7 days). What I am trying to figure out is the average of how many times the anagrams RSS Feed were accessed between June 1st and 7th, June 2nd and 8th, June 3rd and 9th, etc. - There is 1 row for each date in the table bible_anagrams_rss_feed. I tried the following syntax, but it is giving me an overall average, not by the date ranges: SELECT AVG(`bible_anagrams`.`views`) AS average_views FROM `bible_anagrams` INNER JOIN `bible_anagrams_rss_feed` ON `bible_anagrams`.`reference` = `bible_anagrams_rss_feed`.`bible_anagrams_reference` ORDER BY `bible_anagrams_rss_feed`.`rss_feed_date` DESC LIMIT 7 I am wanting the query I am asking help for to be included as one of the mySQL results, where I have indicated AVERAGE VIEWS QUERY HERE (although if there is a better way I am opening to learning it): SELECT `bible_anagrams_rss_feed`.`rss_feed_date` , `bible_anagrams`.`reference`, `bible_anagrams`.`bible_anagram_word` , `bible_anagrams`.`views` , ( AVERAGE VIEWS QUERY HERE ) AS average_views FROM `bible_anagrams_rss_feed` INNER JOIN `bible_anagrams` ON `bible_anagrams`.`reference` = `bible_anagrams_rss_feed`.`bible_anagrams_reference` ORDER BY `bible_anagrams_rss_feed`.`rss_feed_date` DESC Thanks for helping me, Ron The Verse of the Day Encouragement from God's Word http://www.TheVerseOfTheDay.info -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] delete message function
I created the below delete function, but it doesn't seem to be working
correctly. When I enter the correct password it get my echo Incorrect
Password Did not Delete! When I leave the password blank the message
will delete from mysql table.
Am I missing something??
Thanks in advance,
Chris
function delete_message($msg) {
extract($msg, EXTR_PREFIX_ALL, 'row');
$result = mysql_query(SELECT ID FROM mbmsgs WHERE Parent = $row_ID;);
while ($row = mysql_fetch_array($result)) {
delete_message($row);
}
mysql_query(DELETE FROM mbmsgs WHERE ID = $row_ID;);
}
$result = mysql_query(SELECT Title, Password FROM mbmsgs WHERE ID
= {$_REQUEST['Msg']};);
if (!$result) exit;
if (!mysql_num_rows($result)) exit;
extract(mysql_fetch_array($result), EXTR_PREFIX_ALL, 'msg');
if (isset($_POST['Password'])) {
if (sha1($_POST['Password']) != $msg_Password) {
echo Incorrect password did not delete!;
exit;
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[PHP-DB] Re: delete message function
On Tue, Jun 14, 2011 at 12:31 AM, Chris Stinemetz
chrisstinem...@gmail.com wrote:
I created the below delete function, but it doesn't seem to be working
correctly. When I enter the correct password it get my echo Incorrect
Password Did not Delete! When I leave the password blank the message
will delete from mysql table.
Am I missing something??
Thanks in advance,
Chris
Sorry. I left out the call to the function. Below is the whole snippit
for the function and call.
function delete_message($msg) {
extract($msg, EXTR_PREFIX_ALL, 'row');
$result = mysql_query(SELECT ID FROM mbmsgs WHERE Parent = $row_ID;);
while ($row = mysql_fetch_array($result)) {
delete_message($row);
}
mysql_query(DELETE FROM mbmsgs WHERE ID = $row_ID;);
}
$result = mysql_query(SELECT Title, Password FROM mbmsgs WHERE ID
= {$_REQUEST['Msg']};);
if (!$result) exit;
if (!mysql_num_rows($result)) exit;
extract(mysql_fetch_array($result), EXTR_PREFIX_ALL, 'msg');
if (isset($_POST['Password'])) {
if (sha1($_POST['Password']) != $msg_Password) {
echo Incorrect password did not delete!;
exit;
}
$result = mysql_query(SELECT ID FROM mbmsgs WHERE Parent =
{$_POST['Msg']};);
while ($row = mysql_fetch_array($result)) {
delete_message($row);
}
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