Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Allowee
Hi,

Where do you get $info2 from?
I only see $info in this function.

.: Allowee

 function scan_dir($dir)
 {
 $info = New mphp3(2);

 $handle = @opendir($dir);
 while ($file = @readdir ($handle))
 {
 if (eregi(^\.{1,2}$,$file))
 {
 continue;
 }

 if(is_dir($dir.$file))
 {
 scan_dir($dir.$file./);
 }
 else
 {
 $info-load(/.$dir.$file);

 $query =insert into mp3 (
   file,
   path,
   artist,
   title,
   album)
 values (
  '$info2-filename',
  '$dir',
  '$info2-v2_artist',
  '$info2-v2_title',
  '$info2-v2_album');;

 mysql_query($query);
 }
 }
 @closedir($handle);
 }
 scan_dir(mp3/);
 ?

 but all it does is to put the path ($dir) into the database. everything
 else is ignored. an error does not occur. since the simple demo works
 fine i think its a problem with the validity of variables.
 i'm new to php, so could anybody give me a hint on what mightbe wrong
 with my code please?

 thanx a lot


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Re: [PHP-DB] ?? php and mysql database question ??

2003-06-07 Thread Allowee
 I already have installed a PHP program that I can
 run/test PHP scripts and thought I'd ask here if
 anyone knew of a mysql one.  (I thought since a PHP
 program is available on Windows OS maybe a mysql one
 was too?)

There is...

http://www.mysql.com/ for more info

.: Allowee


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Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Allowee
hmmm,
maybe this code..

$info-load(/.$dir.$file);

if $dir = mp3s and $file = test.mp3
then it will load '/mp3s/test.mp3'

you got that directory?
I've seen the class and you are hiding the fopen error message, which could be 
the problem.

.: Allowee

On Saturday 07 June 2003 11:11, Ole Hornauer wrote:
 hi allowee,

 sorry, this was not meant to be. $info2 is supposed to be $info. my
 fault. but that is not the actual problem.

  Hi,
 
  Where do you get $info2 from?
  I only see $info in this function.
 
  .: Allowee
 
   function scan_dir($dir)
   {
   $info = New mphp3(2);
  
   $handle = @opendir($dir);
   while ($file = @readdir ($handle))
   {
   if (eregi(^\.{1,2}$,$file))
   {
   continue;
   }
  
   if(is_dir($dir.$file))
   {
   scan_dir($dir.$file./);
   }
   else
   {
   $info-load(/.$dir.$file);
  
   $query =insert into mp3 (
 file,
 path,
 artist,
 title,
 album)
   values (
'$info2-filename',
'$dir',
'$info2-v2_artist',
'$info2-v2_title',
'$info2-v2_album');;
  
   mysql_query($query);
   }
   }
   @closedir($handle);
   }
   scan_dir(mp3/);
   ?
  
   but all it does is to put the path ($dir) into the database. everything
   else is ignored. an error does not occur. since the simple demo works


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Re: [PHP-DB] mysql, php, mp3 - a variable problem

2003-06-07 Thread Allowee
On Saturday 07 June 2003 11:20, Allowee wrote:
 hmmm,
 maybe this code..

 $info-load(/.$dir.$file);

 if $dir = mp3s and $file = test.mp3
 then it will load '/mp3s/test.mp3'

 you got that directory?
 I've seen the class and you are hiding the fopen error message, which could
 be the problem.

 .: Allowee


hmmm.
that won't work..

you can try
$info-load(./.$dir./.$file);

or simple..
$info-load($dir./.$file);

.: Allowee

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