Re: [PHP-DB] mysql, php, mp3 - a variable problem
Hi, Where do you get $info2 from? I only see $info in this function. .: Allowee function scan_dir($dir) { $info = New mphp3(2); $handle = @opendir($dir); while ($file = @readdir ($handle)) { if (eregi(^\.{1,2}$,$file)) { continue; } if(is_dir($dir.$file)) { scan_dir($dir.$file./); } else { $info-load(/.$dir.$file); $query =insert into mp3 ( file, path, artist, title, album) values ( '$info2-filename', '$dir', '$info2-v2_artist', '$info2-v2_title', '$info2-v2_album');; mysql_query($query); } } @closedir($handle); } scan_dir(mp3/); ? but all it does is to put the path ($dir) into the database. everything else is ignored. an error does not occur. since the simple demo works fine i think its a problem with the validity of variables. i'm new to php, so could anybody give me a hint on what mightbe wrong with my code please? thanx a lot -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] ?? php and mysql database question ??
I already have installed a PHP program that I can run/test PHP scripts and thought I'd ask here if anyone knew of a mysql one. (I thought since a PHP program is available on Windows OS maybe a mysql one was too?) There is... http://www.mysql.com/ for more info .: Allowee -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] mysql, php, mp3 - a variable problem
hmmm, maybe this code.. $info-load(/.$dir.$file); if $dir = mp3s and $file = test.mp3 then it will load '/mp3s/test.mp3' you got that directory? I've seen the class and you are hiding the fopen error message, which could be the problem. .: Allowee On Saturday 07 June 2003 11:11, Ole Hornauer wrote: hi allowee, sorry, this was not meant to be. $info2 is supposed to be $info. my fault. but that is not the actual problem. Hi, Where do you get $info2 from? I only see $info in this function. .: Allowee function scan_dir($dir) { $info = New mphp3(2); $handle = @opendir($dir); while ($file = @readdir ($handle)) { if (eregi(^\.{1,2}$,$file)) { continue; } if(is_dir($dir.$file)) { scan_dir($dir.$file./); } else { $info-load(/.$dir.$file); $query =insert into mp3 ( file, path, artist, title, album) values ( '$info2-filename', '$dir', '$info2-v2_artist', '$info2-v2_title', '$info2-v2_album');; mysql_query($query); } } @closedir($handle); } scan_dir(mp3/); ? but all it does is to put the path ($dir) into the database. everything else is ignored. an error does not occur. since the simple demo works -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] mysql, php, mp3 - a variable problem
On Saturday 07 June 2003 11:20, Allowee wrote: hmmm, maybe this code.. $info-load(/.$dir.$file); if $dir = mp3s and $file = test.mp3 then it will load '/mp3s/test.mp3' you got that directory? I've seen the class and you are hiding the fopen error message, which could be the problem. .: Allowee hmmm. that won't work.. you can try $info-load(./.$dir./.$file); or simple.. $info-load($dir./.$file); .: Allowee -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php