Re: [PHP-DB] Require VB Usergroup

2005-01-15 Thread Rinku
Thanks for your co-operation !!!
 
But I need user group for VB 6.0 for client based programme and not for VB.NET.
 
Regards,
Rinku
 
 
 
 
 
 
 
 
 
 
Joseph Crawford <[EMAIL PROTECTED]> wrote:
you could try the Vermont .NET user group, there are several VB guru's there

i think it's http://www.vtdotnet.org


-- 
Joseph Crawford Jr.
Codebowl Solutions
[EMAIL PROTECTED]


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[PHP-DB] Require VB Usergroup

2005-01-14 Thread Rinku
Dear all,
 
Can any of you suggest me any usergroup For VB just same as this usergroup ?
I know this is very different question from this group, but I had tried a lot 
to search for that. So all of your's comments and views will be highly 
apreciated ...
 
Regards,
Rinku


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Re: [PHP-DB] Validate value

2004-07-13 Thread Rinku
Thank you, Very much !!!
 
 
It worked fine.
 
Regards,
Rinku

"Jensen, Kimberlee" <[EMAIL PROTECTED]> wrote:
1. You have to allow for a space in your pattern - you can do so by hitting the space 
bar or using \s. Here are some options

$pattern="/^[a-zA-Z ]+$/";
if(preg_match($pattern,$_POST['name']))
{


$pattern="/^[a-zA-Z\s]+$/";
if(preg_match($pattern,$_POST['name']))
{



$pattern="/^[a-zA-Z]+[\s]?[a-zA-Z]*$/";
if(preg_match($pattern,$_POST['name']))
{


2. Do you want other characters besides numbers in the phone, such as 333-333-?
Otherwise, this should do it:



$pattern="/^[\d]{10}$/";
if(preg_match($pattern,$_POST['phone']))
{






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Re: [PHP-DB] Re: Validate Value

2004-07-11 Thread Rinku
I have used this code.
 
  $pattern="/^\s+[a-zA-Z]+$/";
if(preg_match($pattern,$_POST['name']))
 {

  Statements;
  }
 
But here still system not supporting for space.
 
Rinku
Tim Van Wassenhove <[EMAIL PROTECTED]> wrote:
In article <[EMAIL PROTECTED]>, Rinku wrote:

>> That's correct behaviour. The alphabet doesn't know what a space is ;)
>> Thus append the other allowed characters to your a-zA-Z interval.

> Can you pls tell me how to add space in name ?

If you reply under what is already written (and cut the irrelevant
things out) , things stay clear for everybody. 

As i mentionned before, use your regular expressions manual.
There you will find what \s and \w mean. 

-- 
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Re: [PHP-DB] Re: Validate Value

2004-07-11 Thread Rinku
Can you pls tell me how to add space in name ?
 
Regards,
Rinku

Tim Van Wassenhove <[EMAIL PROTECTED]> wrote:
In article <[EMAIL PROTECTED]>, Rinku wrote:
> --0-775821546-1089528419=:27331
> Content-Type: text/plain; charset=us-ascii
> 
> Pls guide on following.
> 1) I want to validate name for a alphabetic value, But if I give space between 2 
> words then its not supporting..

That's correct behaviour. The alphabet doesn't know what a space is ;)
Thus append the other allowed characters to your a-zA-Z interval.

> 2)I want to validate a phone no for 10 digits. But in this value if I enter "+" or 
> "-" in begining then even 
> the system will accept it. So can you pls suggest me what to do to solve the problem 
> ?

In this case you only want to allow characters in the interval 0-9. I
think \d is a shortcut for that. And to limit it to only 10 occurences,
i believe you can use {0,10} so you end up with \d{0,10} if i'm not
mistaken (consult a regular expressions manual to be sure)



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[PHP-DB] Validate Value

2004-07-10 Thread Rinku
Pls guide on following.
1) I want to validate name for a alphabetic value, But if I give space between 2 words 
then its not supporting..
As example: Name = "PHP Guide"
Then the system says name must be in alphabetic value. Pls find the codd No 1 for more 
Details :
 
2)I want to validate a phone no for 10 digits. But in this value if I enter "+" or "-" 
in begining then even 
the system will accept it. So can you pls suggest me what to do to solve the problem ?
As Example : Phone = -984524561. Here "-" will be accepted by the system
Pls find the codd no 2 for more details :
 
COdd no 1 :
function Name_validate()
{
if($_POST['name']!="")
{
$pattern="/^[a-zA-Z]+$/";
if(preg_match($pattern,$_POST['name']))
 {
   Statements;
 }
else
{
?>

alert("Name must be in Alphabetic Characters");



alert("Pls Enter Name");



alert("Phone No must be in Numeric Characters");

 10)
{
?>

alert("Phone No Can't be more than 10 digits");



alert("Pls Enter Phone No");

http://mail.yahoo.com 

[PHP-DB] Validation Form require.

2004-07-03 Thread Rinku
Dear All,
 
Can any of you send me one of your validated form for "Numeric value checking" & 
"Alphabetic Value Checking" I have done it but still not succeed.
 
Your answer wd be highly appriciated.
 
Regards,
Rinku

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[PHP-DB] How to take Backup ?

2004-07-01 Thread Rinku
I want to take backup for Mysql database.
 
Can any of you tell me how to take Backup and how to Restore it ?
 
Rinku

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Re: [PHP-DB] Call to undefined function mysql_connect()

2004-06-29 Thread Rinku
if ($text != "") You had used this.
 
Pls use this so that you can access the value for the variable
if($_POST['text']!="")
 
I hope this will help you.

Leandro de Oliveira <[EMAIL PROTECTED]> wrote:

I don´t know how to see if mysq is enabled

but i tested this, it is like i have no php

file: form.php








if ($text != "")
echo "You wrote \"$text\" 

";
?>


 [input] 


 [input] 


echo $HTTP_USER_AGENT;
?>




submit dont works, echo $HTTP_USER_AGENT too, but phpinfo() worked!

what is going on?




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Re: [PHP-DB] How to define array variable while accessing it ???

2004-06-29 Thread Rinku
Actually I want to know how to access the variable
after defining it.
Like :
$query="delete from feedback where id=$delete[$i]";
$deleteresult=mysql_query($query) or
die("Unable to delete");

But here I am not getting any value in
"$delete[$i]"-(here $i is 0,1,2,3)

So what to do to access it ?
I cant access the value even by $_POST['$delete[$i]']

Can any of you suggest me the sollution ?

Rinku
--- Torsten Roehr <[EMAIL PROTECTED]> wrote:
> "Matt M." <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
> > >type="checkbox" name=" printf("chk_arr[%d]",$i); ?>" value=""
> >
> >
> > setup your checkbox something like this:
> >
> >  value="
> >
> > php will treat this as an array
> 
> The closing php tag and quote of the value attribute
> was missing:
> 
> 
> 
> Regards, Torsten Roehr
> 
> -- 
> PHP Database Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
> 
> 




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[PHP-DB] How to define array variable while accessing it ???

2004-06-28 Thread Rinku
While we want to access any variable value we can write 
Print $_POST['VariableName']
 
But it we want to access value for an array variable then what we should write ?
Like for $chk_arr[$i]
How to access this value in some particular function ?
 
Pls read the code if you are not able to get my point .
 
 
 
if(isset($_POST['action'])&&$_POST['action']=="Check Feedback")
{
$query="select * from feedback";
$result=mysql_query($query)
 or die("Could not execute Query");
   $total=mysql_numrows($result);
?>
   >
 0)
{
 print $total;
 ?>
 
 
 Check it
 Comment 
Type
 Comment On
 Comment
 Name
 E-mail
 Phone
 
 
 
 
  " value="" >
 
 
 
 
 
 
 
 
";
  ?>
   



   

  
  
  

Re: [PHP-DB] Call to undefined function mysql_connect()

2004-06-28 Thread Rinku
And If you need any documentation for Apache, PHP,
Mysql and PhpMyAdmin Installation on WinXP or for
WinNt then pls do write me I'll send it to you.

Rinku
--- "Larry E. Ullman" <[EMAIL PROTECTED]>
wrote:
> > But i received "Call to undefined function
> mysql_connect() on line 5"
> >
> > Can anyone help me?
> 
> Your PHP installation apparently does not support
> MySQL. You can 
> confirm this by running a phpinfo() script. You may
> need to 
> reinstall/recompile PHP.
> 
> Larry
> 
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> To unsubscribe, visit: http://www.php.net/unsub.php
> 
> 




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Re: [PHP-DB] Auto increament

2004-06-28 Thread Rinku
Thank you.
It worked.

Rinku
--- Jonathan Haddad <[EMAIL PROTECTED]> wrote:
> I believe the data type needs to be int - unless
> mysql interprets 
> auto_increment as a int automatically.
> 
> Here's an example from mysql.com
> 
> 
> CREATE TABLE animals (
>   id MEDIUMINT NOT NULL AUTO_INCREMENT,
>   name CHAR(30) NOT NULL,
>   PRIMARY KEY (id)
>   );
> Enjoy.
> 
> Jon
> 
> On Jun 27, 2004, at 8:25 AM, Daniel Clark wrote:
> 
> > Yes there is an auto increment field in mySQL and
> most other databases.
> >
> >>> Can any of you guide me how to do auto
> increament in a field?
> >>> I think there is one datatype for auto
> increament.
> >>> But I dont know how to do it ?
> >>>
> >>> Rinku
> >
> > -- 
> > PHP Database Mailing List (http://www.php.net/)
> > To unsubscribe, visit:
> http://www.php.net/unsub.php
> >
> >
> >
> 




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[PHP-DB] Auto increament

2004-06-27 Thread Rinku
Can any of you guide me how to do auto increament in a field?
I think there is one datatype for auto increament.
But I dont know how to do it ?
 
Rinku


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[PHP-DB] Validate Value

2004-06-26 Thread Rinku
I am trying to check the variable for validation. I have written this code, but still 
I am not getting expected output. Can any of you suggest me what is missing in this ?
 
Expected Output 
1)If the variable is set and value is not alphabatic then system should say 
"Alphabatic value require" for the field named "txtname'. And cursor should focus on 
txtname.
 
2)If the variable is set and value is not Numeric then system should say "Numeric 
value require" for the field named "txtph_no'. And cursor should focus on txtname. 
 


function check_validata()
 {
 if($_POST['txtname']=='')
 {
 if (!is_alpha($_POST['txtname']))
 {
  ?>
  
   alert("Input alphabatic value !!!");
online_form.txtname.focus();
  


  alert("Input Name !!!");
  online_form.txtname.focus();

 
  
   alert("Input numeric value !!!");
online_form.txtph_no.focus();
  


  alert("Input Phone No");
  online_form.txtph_no.focus();

 http://mail.yahoo.com 

[PHP-DB] Javascript help require

2004-06-26 Thread Rinku
I need Javascript help for this

1)I want to validate a variable called "name"
If variable's value is not set then system should say
"Value require".
If its not alphabatic then system should say
"Alphabatic value require". And curser's focus should
come on textbox named "name".
2)I want to validate a variable called "Phone_no"
If variable's value is not set then system should say
"Value require".
If its not numeric then system should say "Numeric
value require". And curser's focus should come on
textbox named "Phone_no".

Pls answer if you can. I have tried but not 100%
succeed.

Regards
Rinku



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[PHP-DB] Outlook Express

2004-06-26 Thread Rinku
Hi ,


I know this is not PHP DB question, But if you answer
for this then I wd be thankful to you.

The question is "How to configure Outlook Express for
yahoo ID ?"

Regards,
Rinku

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[PHP-DB] require function detail with example

2004-06-26 Thread Rinku
1)I need to check a variable weather it is numeric or
character. Could any of you answer for the query ?
2)I want to set the focus of one particular textbox.
So could you pls answer how to setfocus ?



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Re: [PHP-DB] SSL with MySQL 4.0

2004-06-25 Thread Rinku
I dont know much abt SSL .
But pls check the URL, I hope it wd be useful to you.
 
http://support.microsoft.com/?kbid=314864

Edgar Hassler <[EMAIL PROTECTED]> wrote:
Does PHP support SSL connections to MySQL? If no, does anyone have an idea
how to make an SSL conncetion to MySQL using PHP?
Thanks,
Edgar Hassler

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Re: [PHP-DB] value error in PHP form

2004-06-24 Thread Rinku
Thanks Zak,
 
Its really amazing.
It worked Properly.
 
Thanks once again.
Rinku

Zachary Krakov <[EMAIL PROTECTED]> wrote:
Hi Rinku,
The statement syntax that I believe will work you is the following:

If (($VARIABLE1 !== '') && ($VARIABLE2 !== '')) {
print "Rinku";
}

Let me know if this works.
Hope this helps.
Best,
-Zak

From: Rinku 
Date: Thu, 24 Jun 2004 03:07:12 -0700 (PDT)
To: Zachary Krakov 
Cc: 

Subject: Re: [PHP-DB] value error in PHP form

Hi Zak,

Thanks for your suggestion.
It really worked.
Now pls answer for the query described below :

I had written the code :
if(isset($_POST['Variable1'])&&isset($_POST['Variable2']))
{
Print "Rinku";
}
Here, even if variables are not set then even I am getting Output as
"Rinku".

Could you pls answer for the query.
Thanks,
Rinku

Zachary Krakov wrote:
Hi Rinku,
One problem I see is that the HTML tags appear to be off... Your HTML is
improperly formatted, which could be causing rendering anomalies to occur,
in addition to the register globals issue which I'll mention shortly. Please
correct your HTML code to read:






HTML_BODY_HERE



Two, Like Kenny said, change the "register_globals = Off" directive in your
PHP.ini file to " register_globals = On" so that variables are carried from
your form values into your post-processing PHP print functions.

Hope this helps,
Best,
-Zak


On 6/20/04 4:34 AM, "Kenny" wrote:

> This could be due to register globals on/off
> 
> Use
> print $_POST['action'];
> print $_POST['Name'];
> 
> Kenny
> 
> -Original Message-
> From: Rinku [mailto:[EMAIL PROTECTED]
> Sent: 20 June 2004 12:23
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] value error in PHP form
> 
> Dear All,
> 
> I have installed PHP on WinXp. I am using MySql as Backend on Apache
> server.
> Now the problem is..
> I am writing this code :
> 
> 
> 
> 
> 
> 
> 
> 
> 
> [input] 
> [input] 
> > print $action;
> print $Name;
> ?>
> 
> 
> 
> Here I should get output as LoginRinku
> But I am getting nothing.
> 
> Can any of you guide me on this?
> 
> Regards,
> Rinku
> 
> 
> 
> 
> 
> 
> -
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Re: [PHP-DB] value error in PHP form

2004-06-24 Thread Rinku
Hi Zak,
 
Thanks for your suggestion.
It really worked.
Now pls answer for the query described below :
 
I had written the code :
if(isset($_POST['Variable1'])&&isset($_POST['Variable2']))
{
  Print "Rinku";
}
  Here, even if variables are not set then even I am getting Output as "Rinku".
 
Could you  pls answer for the query.
Thanks,
Rinku

Zachary Krakov <[EMAIL PROTECTED]> wrote:
Hi Rinku,
One problem I see is that the HTML tags appear to be off... Your HTML is
improperly formatted, which could be causing rendering anomalies to occur,
in addition to the register globals issue which I'll mention shortly. Please
correct your HTML code to read:






HTML_BODY_HERE



Two, Like Kenny said, change the "register_globals = Off" directive in your
PHP.ini file to " register_globals = On" so that variables are carried from
your form values into your post-processing PHP print functions.

Hope this helps,
Best,
-Zak


On 6/20/04 4:34 AM, "Kenny" wrote:

> This could be due to register globals on/off
> 
> Use
> print $_POST['action'];
> print $_POST['Name'];
> 
> Kenny
> 
> -Original Message-
> From: Rinku [mailto:[EMAIL PROTECTED]
> Sent: 20 June 2004 12:23
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] value error in PHP form
> 
> Dear All,
> 
> I have installed PHP on WinXp. I am using MySql as Backend on Apache
> server.
> Now the problem is..
> I am writing this code :
> 
> 
> 
> 
> 
> 
> 
> 
> 
>  [input] 
>  [input] 
> > print $action;
> print $Name;
> ?>
> 
> 
> 
> Here I should get output as LoginRinku
> But I am getting nothing.
> 
> Can any of you guide me on this?
> 
> Regards,
> Rinku
> 
> 
> 
> 
> 
> 
> -
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[PHP-DB] Value Error in execution

2004-06-23 Thread Rinku
Dear all,
 
Can you aswer for the Query as follow :
 
if(isset(_POST['VARIABLE1']$$(_POST['VARIABLE2'])
{
print "testing";
STATEMENTS;
}
 
 Here, even I havent set the value for the variables then even I am getting the output 
like "testing".
 
Can any of you suggest me the sollution for the query ?
 
Thanks,
Rinku


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Re: [PHP-DB] value error in PHP form

2004-06-20 Thread Rinku
Thank you very much Kim, Its really very much useful to me. I was trying to fing the 
sollution from a long time. At last you had answered me.
Thanks Once Again.
 
Regards,
Rinku

Kim Steinhaug <[EMAIL PROTECTED]> wrote:
Or
$_GET["action"];
$_GET["Name"];

Do yourself a HUGE favour and start using _GET and _POST
right away on all queries. Also look into the well known problems
with addslashes with globals on while your at it. On php.net there
are good explernations and examples, look into the reslash() and
deslash() example.

One of theese days youll wake up and globals are off by default.
(Well, isnt PHP5 off?) The problem is, your are used to program
with globals on... If you have like 50 clients who wakes up with
globals off you are inn for a bad day (or week... )

When I first started with PHP I loved the globals, but the last year
they have really pissed me off mostly.

The best thing you can do is be sure your software works with
globals off, and then take it for a test drive with globals on.

It may sound trivial and annoying to read, but this is one of the
major "buggers" of programming PHP - so do it now, :) You wont
regret it I promise you.

--
--
Kim Steinhaug
--
There are 10 types of people when it comes to binary numbers:
those who understand them, and those who don't.
--
www.steinhaug.com - www.easywebshop.no - www.webkitpro.com
--


"Kenny" wrote in message
news:[EMAIL PROTECTED]
> This could be due to register globals on/off
>
> Use
> print $_POST['action'];
> print $_POST['Name'];
>
> Kenny
>
> -Original Message-
> From: Rinku [mailto:[EMAIL PROTECTED]
> Sent: 20 June 2004 12:23
> To: [EMAIL PROTECTED]
> Subject: [PHP-DB] value error in PHP form
>
> Dear All,
>
> I have installed PHP on WinXp. I am using MySql as Backend on Apache
> server.
> Now the problem is..
> I am writing this code :
> 
> 
> 
>
> 
>
>
> 
> 
>  [input] 
>  [input] 
> > print $action;
> print $Name;
> ?>
> 
> 
> 
> Here I should get output as LoginRinku
> But I am getting nothing.
>
> Can any of you guide me on this?
>
> Regards,
> Rinku
>
>
>
>
>
>
> -
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Re: [PHP-DB] value error in PHP form

2004-06-20 Thread Rinku
Actually I want to use the function like
 if($action="Login")
{
Statements;
}
But here I am not getting any value in $action even I click on it.
When I was using Linux at that time I had not this kind of problem.

Rinku
Marvin Hechanova <[EMAIL PROTECTED]> wrote:
You have to assign values to your name and action
e.g.

 [input] " value=Rinku>
 [input] " type=submit value="Submit Query" 
value="Login">

but why would you want to print the results?


On Sun, 20 Jun 2004 04:22:59 -0700 (PDT), Rinku wrote:
> 
> Dear All,
> 
> I have installed PHP on WinXp. I am using MySql as Backend on Apache server.
> Now the problem is..
> I am writing this code :
> 
> 
> 
> 
> 
> 
> 
> 
>  [input] 
>  [input] 
> > print $action;
> print $Name;
> ?>
> 
> 
> 
> Here I should get output as LoginRinku
> But I am getting nothing.
> 
> Can any of you guide me on this?
> 
> Regards,
> Rinku
> 
> 
> -
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[PHP-DB] value error in PHP form

2004-06-20 Thread Rinku
Dear All,
 
I have installed PHP on WinXp. I am using MySql as Backend on Apache server.
Now the problem is..
I am writing this code :







 









Here I should get output as LoginRinku
But I am getting nothing.
 
Can any of you guide me on this?
 
Regards,
Rinku


 
 


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