[PHP-DB] PHP and table/view names with '$'
Hi, I am trying to access some of the v$ views using php on iis, with admin privileges. However, using: $stmt = OCIParse($conn, "SELECT * FROM v$sql"); gives me this error: PHP Notice: undefined variable: sql . . . Is there a way around this? Thanks Mark -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP-DB] PHP and table/view names with '$'
I find that using single quotes rather than double quotes prevents variable substitution. I don't know if this is an undocumented feature, as the documentation says that both have the same functionality. Regards, Neil -Original Message- From: Mark Casson [mailto:confu...@icube.co.uk] Sent: 23 April 2009 11:04 To: php-db@lists.php.net Subject: [PHP-DB] PHP and table/view names with '$' Hi, I am trying to access some of the v$ views using php on iis, with admin privileges. However, using: $stmt = OCIParse($conn, "SELECT * FROM v$sql"); gives me this error: PHP Notice: undefined variable: sql . . . Is there a way around this? Thanks Mark -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PHP and table/view names with '$'
What if you use back-quotes `` around the table/view name? $stmt = OCIParse($conn, "SELECT * FROM `v$sql`"); - Original Message - From: To: "Mark Casson" ; Sent: Thursday, April 23, 2009 5:25 AM Subject: RE: [PHP-DB] PHP and table/view names with '$' I find that using single quotes rather than double quotes prevents variable substitution. I don't know if this is an undocumented feature, as the documentation says that both have the same functionality. Regards, Neil -Original Message- From: Mark Casson [mailto:confu...@icube.co.uk] Sent: 23 April 2009 11:04 To: php-db@lists.php.net Subject: [PHP-DB] PHP and table/view names with '$' Hi, I am trying to access some of the v$ views using php on iis, with admin privileges. However, using: $stmt = OCIParse($conn, "SELECT * FROM v$sql"); gives me this error: PHP Notice: undefined variable: sql . . . Is there a way around this? Thanks Mark -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PHP and table/view names with '$'
Hi, For reference, this didn't work, but just using single quotes instead of double quotes did. Mark ""Yves Sucaet"" wrote in message news:006201c9c3ff$4896f7e0$0402a...@rincewind... > What if you use back-quotes `` around the table/view name? > $stmt = OCIParse($conn, "SELECT * FROM `v$sql`"); > > > - Original Message - > From: > To: "Mark Casson" ; > Sent: Thursday, April 23, 2009 5:25 AM > Subject: RE: [PHP-DB] PHP and table/view names with '$' > > > I find that using single quotes rather than double quotes prevents > variable substitution. > > I don't know if this is an undocumented feature, as the documentation > says that both have the same functionality. > > Regards, Neil > > -Original Message----- > From: Mark Casson [mailto:confu...@icube.co.uk] Sent: 23 April 2009 11:04 > To: php-db@lists.php.net > Subject: [PHP-DB] PHP and table/view names with '$' > > Hi, > > I am trying to access some of the v$ views using php on iis, with admin > privileges. > > However, using: > > $stmt = OCIParse($conn, "SELECT * FROM v$sql"); > > gives me this error: > > PHP Notice: undefined variable: sql . . . > > Is there a way around this? > > Thanks > > Mark > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] PHP and table/view names with '$'
Sorry Mark, It's early in the morning... Neil is right. It's a PHP error you're getting after all, not a SQL Server error. And yes, this is by design: double quotes allow for variable insertion/substitution " ". Single quotes don't ' '. However, if you don't want the $ to be interpreted within the double quotes, you should be able to prevent this by using the backslash \ character. So, we get: $name = "Yves"; $name2 = "$name Sucaet";// "Yves Sucaet" $name3 = '$name Sucaet';// "$name Sucaet" $name4 = "\$name Sucaet";// "$name Sucaet" hth, Yves ----- Original Message - From: To: "Mark Casson" ; Sent: Thursday, April 23, 2009 5:25 AM Subject: RE: [PHP-DB] PHP and table/view names with '$' I find that using single quotes rather than double quotes prevents variable substitution. I don't know if this is an undocumented feature, as the documentation says that both have the same functionality. Regards, Neil -----Original Message----- From: Mark Casson [mailto:confu...@icube.co.uk] Sent: 23 April 2009 11:04 To: php-db@lists.php.net Subject: [PHP-DB] PHP and table/view names with '$' Hi, I am trying to access some of the v$ views using php on iis, with admin privileges. However, using: $stmt = OCIParse($conn, "SELECT * FROM v$sql"); gives me this error: PHP Notice: undefined variable: sql . . . Is there a way around this? Thanks Mark -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
