Hi all,

Well, I played about abit more and discivered that I as overcomplicating
things by specifying the tablename in field to be displayed. Once I set it
to just display the fieldname it worked swimmingly.

Now I can really get going.

George
----- Original Message -----
From: George Pitcher <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, August 20, 2001 1:57 PM
Subject: displaying related data from MySQL


> Hi all,
>
> This sounds to me like a common question but I haven't found quite what I
> want anywaher (maybe I've been looking in the wrong place). So apologies
> from a complete newbie.
>
> I have built a database with 6 tables. The Master table contains keys to
the
> other 5 tables. I want to be able to display related data when I display
> search results.
>
> This is the code I've been using (trial and error) but although I get a
row
> for each fount record, I get an error in every table cell.
>
>
> $result=mysql_query ("select * from MASTER,ACFTREF
>       where MASTER.MFR_MDL_CODE=ACFTREF.CODE
>       AND MASTER.N_NUMBER LIKE '$Serial%'
>       AND MASTER.SERIAL_NUMBER LIKE '$Con%'
>       ORDER BY MASTER.N_NUMBER"
> );
> ?>
> <table width=100% tr valign=top>
> <td colwidth=15%>Serial
> <td colwidth=35% align=right>Maufacturer
> <td colwidth=35% align=left>Model
> <td colwidth=15%>Con
> </td></tr>
> <?php
> if ($row = mysql_fetch_array($result)) {
> do {
>  print ("<TR valign=top><TD bgcolor=yellow>N");
>  print $row['MASTER.N_NUMBER'];
>  print ("<td>");
>  print $row['ACFTREF.MFR_NAME'];
>  print ("<td>");
>  print $row['ACFTREF.TYPE_ACFT'];
>  print ("<td>");
>  print $row['MASTER.SERIAL_NUMBER'];
>     print ("<p></TD></TR>");
> } while ($row = mysql_fetch_array($result)) ;
> } else {print "Sorry, no results found!";}
> }
> ?>
>
> Just for info, the Master db holds 340,000+ records.
>
> MTIA
>
> George in Edinburgh
>


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