This should work as well (newer syntax) ?:
SELECT F.question, F.answer
FROMFaqsAS F
LEFT JOIN FaqsRelatedToProducts AS FP ON F.faqid = FP.faqid
WHERE fgnumber = '$yourfgnumber'
Use:
SELECT DISTINCT ...
when your FaqsRelatedToProducts table includes identical "fgnumber-faqid"
rows.
:)
Hynek
-Original Message-
From: Ignatius Reilly [mailto:[EMAIL PROTECTED]]
Sent: 10. prosince 2002 23:42
To: [EMAIL PROTECTED]; Michael Knauf/Niles
Subject: Re: [PHP-DB] Select Query Help...
Try:
SELECT DISTINCT F.question, F.answer
FROM Faqs AS F, FaqsRelatedToProducts Table AS FP
WHERE F.faqid = FP.faqid
DTH?
Ignatius
- Original Message -
From: "Michael Knauf/Niles" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, December 10, 2002 8:53 PM
Subject: [PHP-DB] Select Query Help...
>
> select query question
>
> OK, I have 3 tables
>
> Products Table
> prodid
> fgnumber
> name
> description
>
> Faqs Table
> faqid
> question
> answer
>
> FaqsRelatedToProducts Table
> fpid
> fgnumber
> faqid
>
> I want to select all the faq question and answer pairs that relate to an
> fgnumber so I need to use both the Faqs table and the
FaqsRelatedToProducts
> table, how do I make that work?
>
> Michael
>
>
>
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