Re: [PHP-DB] Storing iterated results into various variables
finally i got it to work in this manner. $i=1; while ($image_row = mysql_fetch_array($result_images)){ $image="image".$i; $caption="caption".$i; $$image = $image_row["image1"]; if ($$image == ""){ $$image = $folder."logo.jpg"; } $$caption = $image_row["caption"]; $i++; } great so thanks Adams. GD "Geckodeep" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > thanks i m going to test ride it and let you know. > tks again to adam & jason. > > "Adam Voigt" <[EMAIL PROTECTED]> wrote in message > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > $counter = 1; > $query = mysql_query("SELECT image,caption FROM tablename ORDER BY id;"); > > while($row = mysql_fetch_array($query)) > { > > $imagevar = "image" . $counter; > $captionvar = "caption" . $counter; > > $$imagevar = $row[image]; > $$captionvar = $row[caption]; > > $counter++; > > } > > Change the query to match what you need, and that should work, if > your interested, check out the manual page on "Variable Variables" at: > > http://www.php.net/manual/en/language.variables.variable.php > > Enjoy. > > On Tue, 2003-02-04 at 07:02, Geckodeep wrote: > May be some one could help me here, I am trying to retrieve results from a > table that gives 9 rows, from each row I am trying to pull out two fields > and assign the two values of those column fields to a variable $image1 and > $caption1, and now I want to go to the next row and pick up the values of > the corresponding fields and store it in the next variable $image2 and > $caption2 and to continue until I reach 9 rows. > > The reason for this technique is I am trying to inject the dynamic data > inside a page which is already formatted with HTMLs (kind of template) and > by means of Php tags I can echo these variables where needed. > > > > Thanks for your time and help in advance I'd appreciate it. > > > > GD > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- > Adam Voigt ([EMAIL PROTECTED]) > The Cryptocomm Group > My GPG Key: http://64.238.252.49:8080/adam_at_cryptocomm.asc > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Storing iterated results into various variables
thanks i m going to test ride it and let you know. tks again to adam & jason. "Adam Voigt" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... $counter = 1; $query = mysql_query("SELECT image,caption FROM tablename ORDER BY id;"); while($row = mysql_fetch_array($query)) { $imagevar = "image" . $counter; $captionvar = "caption" . $counter; $$imagevar = $row[image]; $$captionvar = $row[caption]; $counter++; } Change the query to match what you need, and that should work, if your interested, check out the manual page on "Variable Variables" at: http://www.php.net/manual/en/language.variables.variable.php Enjoy. On Tue, 2003-02-04 at 07:02, Geckodeep wrote: May be some one could help me here, I am trying to retrieve results from a table that gives 9 rows, from each row I am trying to pull out two fields and assign the two values of those column fields to a variable $image1 and $caption1, and now I want to go to the next row and pick up the values of the corresponding fields and store it in the next variable $image2 and $caption2 and to continue until I reach 9 rows. The reason for this technique is I am trying to inject the dynamic data inside a page which is already formatted with HTMLs (kind of template) and by means of Php tags I can echo these variables where needed. Thanks for your time and help in advance I'd appreciate it. GD -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Adam Voigt ([EMAIL PROTECTED]) The Cryptocomm Group My GPG Key: http://64.238.252.49:8080/adam_at_cryptocomm.asc -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Storing iterated results into various variables
$counter = 1; $query = mysql_query("SELECT image,caption FROM tablename ORDER BY id;"); while($row = mysql_fetch_array($query)) { $imagevar = "image" . $counter; $captionvar = "caption" . $counter; $$imagevar = $row[image]; $$captionvar = $row[caption]; $counter++; } Change the query to match what you need, and that should work, if your interested, check out the manual page on "Variable Variables" at: http://www.php.net/manual/en/language.variables.variable.php Enjoy. On Tue, 2003-02-04 at 07:02, Geckodeep wrote: May be some one could help me here, I am trying to retrieve results from a table that gives 9 rows, from each row I am trying to pull out two fields and assign the two values of those column fields to a variable $image1 and $caption1, and now I want to go to the next row and pick up the values of the corresponding fields and store it in the next variable $image2 and $caption2 and to continue until I reach 9 rows. The reason for this technique is I am trying to inject the dynamic data inside a page which is already formatted with HTMLs (kind of template) and by means of Php tags I can echo these variables where needed. Thanks for your time and help in advance I'd appreciate it. GD -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- Adam Voigt ([EMAIL PROTECTED]) The Cryptocomm Group My GPG Key: http://64.238.252.49:8080/adam_at_cryptocomm.asc signature.asc Description: This is a digitally signed message part
Re: [PHP-DB] Storing iterated results into various variables
Here is a part of my code: while ($image_row = mysql_fetch_array($result_images)){ $image1 = $image_row[0]["image1"]; if ($image1 == ""){ $image1 = $folder."logo.jpg";// it places a log when there are no images } $caption1 = $image_row[0]["caption"]; } This loop fetches the row and assigns the two variables $image1 and $caption1 with its associated value from the fields in the 1st row. How can I get the loop to fetch in the same way as above but from the 2nd row and assigns the values to the new variable $image2 and $caption2 until it reaches the 9th row with $image9 and $caption9? thanks again "Jason Wong" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > On Tuesday 04 February 2003 20:02, Geckodeep wrote: > > May be some one could help me here, I am trying to retrieve results from a > > table that gives 9 rows, from each row I am trying to pull out two fields > > and assign the two values of those column fields to a variable $image1 and > > $caption1, and now I want to go to the next row and pick up the values of > > the corresponding fields and store it in the next variable $image2 and > > $caption2 and to continue until I reach 9 rows. > > > > The reason for this technique is I am trying to inject the dynamic data > > inside a page which is already formatted with HTMLs (kind of template) and > > by means of Php tags I can echo these variables where needed. > > What exactly are you having problems with? What is your code so far? > > -- > Jason Wong -> Gremlins Associates -> www.gremlins.biz > Open Source Software Systems Integrators > * Web Design & Hosting * Internet & Intranet Applications Development * > -- > Search the list archives before you post > http://marc.theaimsgroup.com/?l=php-db > -- > /* > Ah, sweet Springtime, when a young man lightly turns his fancy over! > */ > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Storing iterated results into various variables
On Tuesday 04 February 2003 20:02, Geckodeep wrote: > May be some one could help me here, I am trying to retrieve results from a > table that gives 9 rows, from each row I am trying to pull out two fields > and assign the two values of those column fields to a variable $image1 and > $caption1, and now I want to go to the next row and pick up the values of > the corresponding fields and store it in the next variable $image2 and > $caption2 and to continue until I reach 9 rows. > > The reason for this technique is I am trying to inject the dynamic data > inside a page which is already formatted with HTMLs (kind of template) and > by means of Php tags I can echo these variables where needed. What exactly are you having problems with? What is your code so far? -- Jason Wong -> Gremlins Associates -> www.gremlins.biz Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-db -- /* Ah, sweet Springtime, when a young man lightly turns his fancy over! */ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Storing iterated results into various variables
May be some one could help me here, I am trying to retrieve results from a table that gives 9 rows, from each row I am trying to pull out two fields and assign the two values of those column fields to a variable $image1 and $caption1, and now I want to go to the next row and pick up the values of the corresponding fields and store it in the next variable $image2 and $caption2 and to continue until I reach 9 rows. The reason for this technique is I am trying to inject the dynamic data inside a page which is already formatted with HTMLs (kind of template) and by means of Php tags I can echo these variables where needed. Thanks for your time and help in advance I'd appreciate it. GD -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php