Re: [PHP-DB] picture into mysql (file address)
One comment is to be sure the destination folder has write privileges
for world.
My typical usage is:
2) // datafile is field name for image/file upload browser
$img_dir = ../photos; // must be 777 access
if($datafile_name != ) {
if ($datafile_name != none) {
$newFileName = $datafile_name;
if (!(copy($datafile, $img_dir/$newFileName))) {
$errmsg = bcopying $newFileName failed/bbr;
} else {
$errmsg = bcopying $newFileName succeeded/bbr;
}
}
}
On Wednesday, December 18, 2002, at 02:20 PM, Seabird wrote:
exec(cp $_POST[picture]
//localhost/seabird.jmtech.ca/OTF.com/images/$_POST[picture_name]);
Re: [PHP-DB] picture into mysql (file address)
since this is a local folder (testing on local server) I have complete
access everywhere. I judge from your sample that register_globals are ON and
mine are turned off (for several reasons.
Do I have a typo somewhere? where does my full path start etc.
the actual folder is in: c:\apache\htdocs\seabird.jmtech.ca\otf.com\images
pls help me.
Jacco
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Terry Romine [EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
One comment is to be sure the destination folder has write privileges
for world.
My typical usage is:
2) // datafile is field name for image/file upload browser
$img_dir = ../photos; // must be 777 access
if($datafile_name != ) {
if ($datafile_name != none) {
$newFileName = $datafile_name;
if (!(copy($datafile, $img_dir/$newFileName))) {
$errmsg = bcopying $newFileName failed/bbr;
} else {
$errmsg = bcopying $newFileName succeeded/bbr;
}
}
}
On Wednesday, December 18, 2002, at 02:20 PM, Seabird wrote:
exec(cp $_POST[picture]
//localhost/seabird.jmtech.ca/OTF.com/images/$_POST[picture_name]);
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[PHP-DB] picture into mysql (file address)
Hi everyone, I have been struggeling with this for some time know and don't
know where it goes wrong. I want to upload pictures into a folder AND store
their path into MySQL. I used a joe's auto tutorial but can't get it to
work. All the information is put in correctly but not the picture.
Please help me, here's my code: (ps globals are off)
if ($_POST[submit]) {
$link = mysql_pconnect(localhost,myusername,mypassword);
$db = test;
mysql_select_db($db,$link);
$query = INSERT INTO inventory
(registration,type,total_time,price,description,picture_name)
VALUES
('$_POST[registration]','$_POST[type]','$_POST[total_time]','$_POST[price]',
'$_POST[description]','$_POST[picture]');
exec(cp $_POST[picture]
//localhost/seabird.jmtech.ca/OTF.com/images/$_POST[picture_name]);
mysql_query( $query, $link);
print 'Thank youbrYou have submitted the following information:br';
echo Registration: $_POST[registration]br\n;
echo Type: $_POST[type]br\n;
echo Total Time: $_POST[total_time]br\n;
echo Price: $_POST[price]br\n;
echo Description: $_POST[description]br\n;
echo temp file: $_POST[picture]br\n;
echo file name: $_POST[picture_name]br\n;
echo file size: $_POST[picture_size]br\n;
echo file type: $_POST[picture_type]br\n;
echo br\n;
echo img src=images/$picture_namebr\n;
}
else { ?
form enctype=multipart/form-data method=post
action=?php echo $PHP_SELF ?
pRegistrationbr
input type=Text name=registration size=25 value=N
br
typebr
input type=Text name=type size=25
br
total timebr
input type=Text name=total_time size=25
br
pricebr
input type=Text name=price size=25
br
Descriptionbr
textarea name=description/textarea
br
picturebr
input type=file name=picture size=25
input type=submit name=submit value=Upload
/p
/form
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Attitude is Everything!
But Remember, Attitudes are Contagious!
Is Yours worth Catching
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