Building off of one of John Holmes's posts from yesterday:
$f_date = date('n/d/Y',strtotime($yourDBdate));
should do the trick.
Hope this helps.
Rich
-Original Message-
From: Steve B. [mailto:[EMAIL PROTECTED]
Sent: Wednesday, June 11, 2003 2:53 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] simple date formatting?
Hi I'm looking to format a date but all I find is this date()
function and it appears to be for
current date?
My variable $dbrec[ListDate] is printing:
4/30/2003 0:00:00
It needs to print
4/30/2003
Am I on the right track to try to do a (with right parameters)
$formatted_date = date(M D Y,$dbrec[ListDate]);
or
$formatted_date = date_format(M D Y,$dbrec[ListDate]);
Thanks
Current code just chops it off:
print tdfont
color='white'b.substr($dbrec[ListDate],0,9)./td;
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