Ah, the join function...I see implode() will also perform the same task.
That was what I needed to do.
Thanks!
Zach
-Original Message-
From: matt stewart [mailto:[EMAIL PROTECTED]]
Sent: Friday, November 16, 2001 9:06 AM
To: 'Zach Curtis'; [EMAIL PROTECTED]
Subject: RE: [PHP-DB] Converting Date Form Fields
put them into an array
$date_stuff[0] = $date_year;
$date_stuff[1] = $date_month;
$date_stuff[2] = "01";
$date_to_enter = join('-',$date_stuff);
then whack $date_to_enter into your database - obviously if the input to
$date_month is "Jan", you need a case statement, or something like that to
make sure you change it to "01".
Hope it helps ;)
Matt
-Original Message-
From: Zach Curtis [mailto:[EMAIL PROTECTED]]
Sent: 16 November 2001 16:02
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Converting Date Form Fields
I have two HTML form fields birthMonth (e.g., Jan=1, Feb=2...) and birthYear
(e.g., 2001=2001, 1999=1999...). How can take these two individual form
fields, then add in a default value of "1" for the birthDay (this is not
asked in the form), and put this data into a MySQL table field birthDate
with field type DATE (-MM-DD)? The part I do not know how to accomplish
is taking these form fields and then combining them into a date
field/format.
Thank you.
Zach Curtis
POPULUS
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