RE: [PHP-DB] Please help me! :(

[Howard Picken]

Can I ask why you're not using autoincrement for your
id field? If you used this you would never have the problem
your having.

Everytime a record is added it will increment the id field
by one, so you don't have to use all the code your using.

Howard

-Original Message-
From: Leif K-Brooks [mailto:[EMAIL PROTECTED]]
Sent: Sunday, 24 March 2002 3:42 PM
To: [EMAIL PROTECTED]
Subject: [PHP-DB] Please help me! :(


I have a site where things in the database have ids.  When something new is
added, it gets an id one higher than the highest existing id.  I use code
something like this:

$gethighestid = mysql_fetch_array(mysql_query(select id from table order by
id desc limit 1));
$tobeid = $gethighestid[id]+1;
mysql_query(insert into table(id,othercolumn,othercolumn2)
values('$tobeid','something','something'));

The thing is, I just got two rows with duplicate ids.  Aparantley, two
people must of added two things at just the right times to make the same id.
Is there any way that will reduce, or eliminate, the time gap between
getting id and inserting?

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Re: [PHP-DB] Please Help Me! thanks!!

[Denny Suvanto]

Try using fsockopen() function :
$file = fsockopen (www.yahoo.com, 80, $err_num,
$err_msg, 30);

You can find more informations about this fuction in
http://www.php.net/manual/en/function.fsockopen.php

May it help you.

Andy
www.mediahostnet.com

--- G [EMAIL PROTECTED] wrote:  Hello! i
would like to useing fopen() fuction to
 open the other Url,
 but i am using a shared server now. When i useing
 fopen() or file()
 fuctions, always have a error message:
 
 Warning: php_hostconnect: connect failed in
 /usr/xxx/xxx/xxx/html/test.php
 on line 3
 
 Warning: file(http://www.yahoo.com;) - Bad file
 descriptor in
 /usr/xxx/xxx/xxx/html/test.php on line 3
 
 How can i do?have any other fuctions can do that?
 Thank You Very Much!!
 
 
 
 
 
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__
Do You Yahoo!?
Everything you'll ever need on one web page from News and Sport to Email and Music 
Charts
http://uk.my.yahoo.com

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RE: [PHP-DB] Please help me with this script...

[Mark Roedel]

 -Original Message-
 From: Slider [mailto:[EMAIL PROTECTED]]
 Sent: Monday, April 02, 2001 9:27 AM
 To: [EMAIL PROTECTED]
 Subject: [PHP-DB] Please help me with this script...
 
 
 Hello,
 
 I've been working on this script all day, but I'm getting the 
 same failure
 report each time:
 
 Warning: Supplied argument is not a valid MySQL result resource in
 c:\program files\apache 
 group\apache\htdocs\motoerit\toon_alles.php on line 23
 
 What could be wrong? This is the code I have:

This usually means there was a problem with your query.  For more info,
including some useable sample code that should help you troubleshoot
exactly what went wrong, see

http://www.php.net/FAQ.php#7.12

---
Mark Roedel ([EMAIL PROTECTED])  ||  "There cannot be a crisis next week.
Systems Programmer / WebMaster  ||   My schedule is already full."
 LeTourneau University  ||-- Henry Kissinger


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