[PHP-DEV] DOCUMENT_ROOT with Zend API

2002-12-11 Thread Krzysztof Socki
Hello!
I'm writing a new function to PHP using the Zend API. I need to know the
DOCUMENT_ROOT value of the running script. I've read through the lxr.php.net
and I still have no idea how to do that. Is it possible with the Zend API,
at all? Does anybody know the way?

Krzysiek Socki
[EMAIL PROTECTED]



-- 
PHP Development Mailing List http://www.php.net/
To unsubscribe, visit: http://www.php.net/unsub.php




[PHP-DEV] Odp: 'include' function

2002-12-10 Thread Krzysztof Socki
Finally I've managed to modify the parser. It was a good lesson.

KS.



-- 
PHP Development Mailing List http://www.php.net/
To unsubscribe, visit: http://www.php.net/unsub.php




Odp: [PHP-DEV] 'include' function

2002-12-09 Thread Krzysztof Socki
 function ala() {
include file.php;
 }

I want neither to explicitly include any file nor to define any function in
my script. My point is to give access to the source to the user but to hide
the script's real functionality. Do you have any experience with modifying
PHP parser, specifically adding new language constructs? Thanks.

KS.



-- 
PHP Development Mailing List http://www.php.net/
To unsubscribe, visit: http://www.php.net/unsub.php




[PHP-DEV] 'include' function

2002-12-06 Thread Krzysztof Socki
Hello!
Can anyone tell me if it's possible to extent PHP with a function that
includes other PHP file? I know that 'include' is not a function, is it
possible to work it around? I need a function that includes a file
respective to the location of the running script. Maybe I could extend the
parser to use an alias of 'include' with a constant file path? I'd be
grateful for your help. Thanks in advance.

Krzysiek Socki
[EMAIL PROTECTED]



-- 
PHP Development Mailing List http://www.php.net/
To unsubscribe, visit: http://www.php.net/unsub.php




Odp: [PHP-DEV] 'include' function

2002-12-06 Thread Krzysztof Socki

U¿ytkownik Hartmut Holzgraefe [EMAIL PROTECTED] w wiadomooci do grup
dyskusyjnych napisa³:[EMAIL PROTECTED]
 Krzysztof Socki wrote:
  Hello!
  Can anyone tell me if it's possible to extent PHP with a function that
  includes other PHP file? I know that 'include' is not a function, is it
  possible to work it around? I need a function that includes a file
  respective to the location of the running script. Maybe I could extend
the
  parser to use an alias of 'include' with a constant file path? I'd be
  grateful for your help. Thanks in advance.

 function include_me($path) {
include $path;
 }

 should do the trick?

I need a function that includes a file, but doesn't show that something is
included. I would like to be able to do something like this:

ala();  //  include some file - the name of the included file is
constant respective to the script location
ela(); ola(); // use functions defined at the included file

Can you help?

KS.



-- 
PHP Development Mailing List http://www.php.net/
To unsubscribe, visit: http://www.php.net/unsub.php