[PHP-DEV] Bug #10967 Updated: $x .= someFunction();
ID: 10967
Updated by: jeroen
Reported By: [EMAIL PROTECTED]
Old Status: Open
Status: Bogus
Bug Type: Scripting Engine problem
Operating System: win2k
PHP Version: 4.0.5
New Comment:
This is nonsense, what do you expect of $x .=
somefunction()? that the second part of $x gets referenced?
Previous Comments:
[2001-06-12 15:36:34] [EMAIL PROTECTED]
well your playing with references where they are not needed.. expect to get your
fingers burnt.
[2001-05-22 16:50:28] [EMAIL PROTECTED]
uhm, well, the thing with the $temp var is useless. i see now that i cannot reference
something into *a part* of something else.
but the silent loss of br\n is still a problem, imo.
fab
[2001-05-18 23:41:12] [EMAIL PROTECTED]
code i would like to use:
---cut---
function someShit() {
return 'foo';
}
$out = '';
for ($i = 1; $i = 3; $i++) {
$out .= someShit() . br\n;
}
echo $out;
---cut---
problem:
parse error on line
$out .= someShit() . br\n;
because .= and don't work together.
so the workaround would be:
$temp = someShit() . br\n;
$out .= $temp;
problem here:
it prints out 'foofoofoo' and not
'foobr\nfoobr\nfoobr\n'
so the code finally looks like:
---cut---
function someShit() {
return 'foo';
}
$out = '';
for ($i = 1; $i = 3; $i++) {
$temp = someShit();
$out .= $temp . br\n;
}
echo $out;
---cut---
is this the normal behavior?
fab
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[PHP-DEV] Bug #10967 Updated: $x .= someFunction();
ID: 10967
Updated by: jmoore
Reported By: [EMAIL PROTECTED]
Status: Open
Bug Type: Scripting Engine problem
Operating system:
PHP Version: 4.0.5
Assigned To:
Comments:
well your playing with references where they are not needed.. expect to get your
fingers burnt.
Previous Comments:
---
[2001-05-22 16:50:28] [EMAIL PROTECTED]
uhm, well, the thing with the $temp var is useless. i see now that i cannot reference
something into *a part* of something else.
but the silent loss of brn is still a problem, imo.
fab
---
[2001-05-18 23:41:12] [EMAIL PROTECTED]
code i would like to use:
---cut---
function someShit() {
return 'foo';
}
$out = '';
for ($i = 1; $i = 3; $i++) {
$out .= someShit() . brn;
}
echo $out;
---cut---
problem:
parse error on line
$out .= someShit() . brn;
because .= and don't work together.
so the workaround would be:
$temp = someShit() . brn;
$out .= $temp;
problem here:
it prints out 'foofoofoo' and not
'foobrnfoobrnfoobrn'
so the code finally looks like:
---cut---
function someShit() {
return 'foo';
}
$out = '';
for ($i = 1; $i = 3; $i++) {
$temp = someShit();
$out .= $temp . brn;
}
echo $out;
---cut---
is this the normal behavior?
fab
---
ATTENTION! Do NOT reply to this email!
To reply, use the web interface found at http://bugs.php.net/?id=10967edit=2
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To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
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[PHP-DEV] Bug #10967 Updated: $x .= someFunction();
ID: 10967
User Update by: [EMAIL PROTECTED]
Status: Open
Bug Type: Scripting Engine problem
Operating system: win2k
PHP Version: 4.0.5
Description: $x .= someFunction();
uhm, well, the thing with the $temp var is useless. i see now that i cannot reference
something into *a part* of something else.
but the silent loss of br\n is still a problem, imo.
fab
Previous Comments:
---
[2001-05-18 23:41:12] [EMAIL PROTECTED]
code i would like to use:
---cut---
function someShit() {
return 'foo';
}
$out = '';
for ($i = 1; $i = 3; $i++) {
$out .= someShit() . brn;
}
echo $out;
---cut---
problem:
parse error on line
$out .= someShit() . brn;
because .= and don't work together.
so the workaround would be:
$temp = someShit() . brn;
$out .= $temp;
problem here:
it prints out 'foofoofoo' and not
'foobrnfoobrnfoobrn'
so the code finally looks like:
---cut---
function someShit() {
return 'foo';
}
$out = '';
for ($i = 1; $i = 3; $i++) {
$temp = someShit();
$out .= $temp . brn;
}
echo $out;
---cut---
is this the normal behavior?
fab
---
Full Bug description available at: http://bugs.php.net/?id=10967
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