Re: [PHP] inline_C installation

[Rory Browne]

Not really answering the question(considering that I'm not really sure
if the last reply answered it or not) at hand, but inline_c is infact
a pear package. It is written in Pure PHP. It works by writing the C
Code into a file, using standard php stream functions, and then using
the program exectution functions to compile it using the  standard
system compiler, before calling dl() to load it as a module. Needless
to say you need to have a compiler(usually gcc) installed for this to
work. I think you need to have make installed as well.

 I'm assuming that you're doing this on *nix. If you're using an RPM
based Linux distro, then make sure you install the php-devel package.
This I believe is php-dev on debian based, but I'm not too sure.

The best thing is probably to install PHP by from source. Then you're
(almost) sure to have whatever you need.

Regards
Rory

On Thu, 11 Nov 2004 15:47:01 -0600, Ryan King <[EMAIL PROTECTED]> wrote:
> On Nov 11, 2004, at 12:50 PM, Rayan Lahoud wrote:
> 
> > Does anybody knows how to install a pear package. i have the inline_C
> > package that i want to install and use. And can i have some sample
> > functions using this package?
> >
> 
> I believe the inline_c package is actually a pecl package
> [pecl.php.net], however it is still installed with the pear installer
> (I hope that makes sense).  Ok, first try typing
> 
> pear -v
> 
> on the command line. If this doesn't work (it returns "command not
> found"), try http://pear.php.net/manual/en/installation.php. If that
> succedes, you have a pear package manager installed. Now type:
> 
> pear install inline_c
> 
> this should install the package for you. You'll probably have to add
> the module to your php.ini script and restart apache.
> 
> -ryan
> 
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> 
>

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Re: [PHP] Evaluate String as Object

[Curt Zirzow]

* Thus wrote bubba:
> Hi,
> 
> Is it possible to evaluate a string passed to a script as an object?

no.

Also, when asking a question, please dont simply reply to a message
and change the subject; Create a new message with subject and ask
your question.


Curt
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Re: [PHP] displaying repetitive results

[Curt Zirzow]

* Thus wrote Greg Donald:
> On Wed, 10 Nov 2004 09:04:27 -0900, Chris Lott <[EMAIL PROTECTED]> wrote:
> > Given a database query thats returns results from a linking (or xref)
> > table which includes repetition because of the joins:
> > 
> > ++--+--+
> > | id | title| subject  |
> > ++--+--+
> > |  1 | Collected Poems of Keats | poetry   |
> > |  2 | Spy High | suspense |
> > |  3 | Sci Fi Spies | suspense |
> > |  3 | Sci Fi Spies | sci-fi   |
> > ++--+--+
> > 
> > What is the best way to go about displaying this for the user so that
> > the record looks "complete":
> > 
> > ID: 3
> > title: Sci Fi Spies
> > Subjects: suspense, scifi
> 
> You might normalize the data a bit.

agreed!



Curt
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Re: [PHP] Array to $_GET variable

[Curt Zirzow]

* Thus wrote Mike Smith:
> I am trying to cache a database recordset so users can sort, etc
> without hitting the database everytime. I'm using ADODB to access a
> MSSQL database.

I wouldn't even bother with this.

No matter what you do your going to have to retreive the data
somewhere, aka sessions, and thus move the load over to the
filesystem. A hit to the database isn't much of a concern.

> 
> echo "Link\n";

If the data doesn't change very frequently, you might want to
create a script that does this when the data is actually changes,
and simply include() it when needed.



Curt
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Re: [PHP] Re: Multiple session_start()s / Is it a problem??

[Curt Zirzow]

* Thus wrote elixon:
> I guess that session_id() method will return null if session is not 
> started (not tested) so theoreticaly you can use:
> 
> if (!session_id()) session_start();

This is the best method.  relying that $_SESSION is set could
falsify your reliance that the session has been started. For
example, some code may be trying to clear all session data prior to
this with:

  $_SESSION = array(); 

Even though it is really set it doesn't mean that the session has
truely started.


Curt
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Re: [PHP] Re: php mail() error

[Curt Zirzow]

* Thus wrote Manuel Lemos:
> Hello,
> 
> On 11/10/2004 10:36 AM, Garth Hapgood - Strickland wrote:
> >Im using the php mail() function to try send an email to a user that has
> >just registered.
> >
> >mail($HTTP_POST_VARS['emailaddress1'], 'Matchmakers Website Registration' ,
> >'Welcome');
> >
> >But when I get the following error back.:
> >  Warning: mail(): SMTP server response: 550 5.7.1 Unable to relay for
> >[EMAIL PROTECTED]
> >
> >Can someone help me out, by telling me what it means or what Im doing 
> >wrong?
> 
> (Thank you Jason for the introduction! :-)
> 
> That means your SMTP server requires authentication to relay messages. 
> The mail function does not support SMTP authentication.

for the record.. and to not mislead several people.. 550 simply
means the message was not accepted. There are several other reasons
why this will happen. The text after the 550 usually signifies what
exactly the problem is.

> [snip spam]

Curt
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Re: [PHP] php mail() error

[Curt Zirzow]

* Thus wrote Jason Wong:
> On Wednesday 10 November 2004 12:36, Garth Hapgood - Strickland wrote:
> > But when I get the following error back.:
> >   Warning: mail(): SMTP server response: 550 5.7.1 Unable to relay for
> > [EMAIL PROTECTED]
> >
> >...
> 
> This is a VERY FAQ.
> 
> googling the error message will tell you what it means. Searching the 
> archives> will give you some solutions.
> 
> Or you can wait for Manuel Lemos' reply :) 

for some reason I find that very funny :)

Curt
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RE: [PHP] Display an image

[nate]

You'll need to create a separate php page called image.php or something and
retrieve the $mydata2->photo and output it to the browser.





image.php
---
$sql = "select where id = '$id'";
echo $mydata2->photo;



Nate

-Original Message-
From: John Taylor-Johnston [mailto:[EMAIL PROTECTED] 
Sent: Friday, November 12, 2004 9:29 PM
To: [EMAIL PROTECTED]
Cc: John Taylor-Johnston
Subject: [PHP] Display an image

I have a longblob with a jpeg loaded in it. But how do I display it?

  `photo` longblob NOT NULL,

This doesn't work :) I need header information, etc. So what does?

  echo "\n";

I don't have an example to work with.

John

--snip-
$sql2 = "select * from ".$db.".".$table";

$news2 = mysql_query($sql2);

  echo "\n";
  echo "$mydata2->Rank $mydata2->Name\n";
  echo "$mydata2->biography\n";
  }

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[PHP] Display an image

[John Taylor-Johnston]

I have a longblob with a jpeg loaded in it. But how do I display it?

  `photo` longblob NOT NULL,

This doesn't work :) I need header information, etc. So what does?

  echo "\n";

I don't have an example to work with.

John

--snip-
$sql2 = "select * from ".$db.".".$table";

$news2 = mysql_query($sql2);

  echo "\n";
  echo "$mydata2->Rank $mydata2->Name\n";
  echo "$mydata2->biography\n";
  }

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[PHP] Re: Globally accessible objects without using 'global $obj;'

[Greg Beaver]

Chris W. Parker wrote:
What I'd ultimately like to do is be able to return more than just a
true/false from a function regarding it's end state. For example, a
function could fail for multiple reasons and just returning a plain
false for all situations does not suffice.
You could either return an object like PEAR_Error 
(http://pear.php.net/manual/en/core.pear.pear-error.php) or use a more 
customizable solution like PEAR_ErrorStack 
(http://pear.php.net/manual/en/core.pear.pear-errorstack.php).  Also, 
don't forget about built-in options like trigger_error and Exceptions in 
php5.

More important than what you use is planning for future growth.  Your 
applications will get larger.  It may seem like a time-saver to do a 
quickie fix that requires less initial typing, but I guarantee you will 
run into a brick wall when you do have to change things and be forced to 
rewrite everything - not exactly a timesaver, unless you simply give up 
on making your code better :)

Greg
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[PHP] Re: Globally accessible objects without using 'global $obj;'

[Red Wingate]

Hi Chris,
Something that worked out very well for me was using a function that
would take care of the error handling ... kind of

define ( 'ERR_TYPE_ERROR' , 1 ) ;
define ( 'ERR_TYPE_WARNING' , 2 ) ;
class Error {
// error handling code here
}
function _handleError ( $msg , $type ) {
   static $errClass ;
   if ( is_class ( $errClass ) === FALSE ) {
  $errClass = new Error();
   }
   // hand $msg to $errClass here ...
}
function raiseError ( $msg ) {
   return _handleError ( $msg , ERR_TYPE_ERROR ) ;
}
function raiseWarning ( $msg ) {
   return _handleError ( $msg , ERR_TYPE_WARNING ) ;
}
?>
But today i prefer using PHPs build-in Error-Handling functions
using the 2 Errorlevels ( E_USER_NOTICE, E_USER_WARNING
and E_USER_ERROR ) for my debugging and error-handling.
But looking at PHP5's try-throw-catch constructs makes me think
about rewritting large parts of my current project :-/
 -- red
Chris W. Parker wrote:
Hello,
Ok so I'm trying to write an error reporting class and I'm just sort of
experimenting at this point (comments outside the scope of this email
are welcome btw) with how to best implement it. One idea I had (which
isn't working out as well as I'd hoped thus far) is to create an
instance of my error class (incidentally called 'Error') at the start of
each page and then reference that instance from within all other objects
and functions.
Maybe this would be best explained with some code:

$e = new Error();
function my_function()
{
// do stuff
if($this == $that)
{
$e->RaiseError();
}
}
?>
Of course, that doesn't work because my_function() doesn't know anything
about $e unless I put a special statement into my_function().

function my_function()
{
// here's the new line
global $e;
// do stuff
...
}
?>
I already don't like the idea of having to put 'global $e;' within each
and every function/method I write. Should I abandon this idea and try
something else? If so, what?
Here is my first idea just fyi.

function my_function()
{
$e = new Error();
// do stuff
if($this == $that)
{
$e->RaiseError();
}
else
{
// continue like normal
}
// get ready to return a response
if($e->error_count > 0)
{
return $e;
}
else
{
// return something else
}
}
?>
Now to use my_function() within a page I have to always assign the
result to a variable so that I can determine whether or not any errors
occured within the function.

$result = my_function();
if($result->error_count > 0)
{
// an error occurred
$result->DisplayErrors();
}
?>
But that also seems like a hassle (but maybe it's a completely necessary
hassle?). I've looked around the internets for a while but have not
found any REALLY useful documents on managing errors (could be that I've
not found the write article yet) and such so any
comments/pointers/links/etc. are very welcome.
What I'd ultimately like to do is be able to return more than just a
true/false from a function regarding it's end state. For example, a
function could fail for multiple reasons and just returning a plain
false for all situations does not suffice.
Thank you for making it this far.
Chris.
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RE: [PHP] probably stupid, but...

[Chris W. Parker]

-{ Rene Brehmer }- 
on Friday, November 12, 2004 3:53 PM said:

> At 21:32 12-11-2004, Chris W. Parker wrote:
>> also you need to wrap your array values in { } when an array is
>> referenced within a string. i.e.
>> 
>> // normal
>> $value = $_GET['something'];
>> 
>> // with { }
>> $value = "Here is some data: {$_GET['something']}";
> 
> Is that actually in the manual ??? If it is, where ?

Yes.

http://us2.php.net/manual/en/language.types.array.php

Search for "More examples to demonstrate this fact" then go down near
the bottom of that box and you'll see it.



Chris.

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RE: [PHP] probably stupid, but...

[-{ Rene Brehmer }-]

At 21:32 12-11-2004, Chris W. Parker wrote:
also you need to wrap your array values in { } when an array is
referenced within a string. i.e.
// normal
$value = $_GET['something'];
// with { }
$value = "Here is some data: {$_GET['something']}";
Is that actually in the manual ??? If it is, where ?
I've been learning PHP for a little over 2 years now, and I've kept jumping 
in and out of strings because I couldn't figure out how to make the darn 
thing replace array values within it.

The syntax section does not mention this that I've been able to find, nor 
does the variable section, and if it's in the array section then it's very 
well buried. I seriously think the basic syntax section needs to cover a 
bit more ground ... it would also solve our problem with recurring 
questions about very basic things.

I'm not saying that the manual should be a complete "teach-it-yourself" 
guide, but basic stuff that you need to use like all the time ought to be 
in there.

Rene
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[PHP] Re: MySQL > Excel

[Manuel Lemos]

Hello,
On 11/12/2004 07:44 PM, Sam Smith wrote:
I've got it working writing out a file (fopen) to CSV (comma delimited) and
the "header('Content-Disposition: attachment; filename="myFile.csv"')"
method but it's clumsy for the user to figure out how to use the file.
Is there some totally slick way of spitting out a file that Excel can open
right up?
This class does exactly what you want just using 
fopen("xlsfile:/path/to/spreadsheet.xls","w") and then you use fwrite to 
send your rows of cells as serialized arrays:

http://www.phpclasses.org/xlsstream
--
Regards,
Manuel Lemos
PHP Classes - Free ready to use OOP components written in PHP
http://www.phpclasses.org/
PHP Reviews - Reviews of PHP books and other products
http://www.phpclasses.org/reviews/
Metastorage - Data object relational mapping layer generator
http://www.meta-language.net/metastorage.html
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[PHP] Globally accessible objects without using 'global $obj;'

[Chris W. Parker]

Hello,

Ok so I'm trying to write an error reporting class and I'm just sort of
experimenting at this point (comments outside the scope of this email
are welcome btw) with how to best implement it. One idea I had (which
isn't working out as well as I'd hoped thus far) is to create an
instance of my error class (incidentally called 'Error') at the start of
each page and then reference that instance from within all other objects
and functions.

Maybe this would be best explained with some code:

RaiseError();
}
}

?>

Of course, that doesn't work because my_function() doesn't know anything
about $e unless I put a special statement into my_function().



I already don't like the idea of having to put 'global $e;' within each
and every function/method I write. Should I abandon this idea and try
something else? If so, what?

Here is my first idea just fyi.

RaiseError();
}
else
{
// continue like normal
}

// get ready to return a response
if($e->error_count > 0)
{
return $e;
}
else
{
// return something else
}
}

?>

Now to use my_function() within a page I have to always assign the
result to a variable so that I can determine whether or not any errors
occured within the function.

error_count > 0)
{
// an error occurred
$result->DisplayErrors();
}

?>

But that also seems like a hassle (but maybe it's a completely necessary
hassle?). I've looked around the internets for a while but have not
found any REALLY useful documents on managing errors (could be that I've
not found the write article yet) and such so any
comments/pointers/links/etc. are very welcome.

What I'd ultimately like to do is be able to return more than just a
true/false from a function regarding it's end state. For example, a
function could fail for multiple reasons and just returning a plain
false for all situations does not suffice.


Thank you for making it this far.
Chris.

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[PHP] Re: PHP File Upload Problem

[Mike Walsh]

"Mike Walsh" <[EMAIL PROTECTED]> wrote in message news:0%ald.9258

[ ... snipped ... ]
>
> ; Maximum allowed size for uploaded files.
> upload_max_filesize = 1G
>

[ ... snipped ... ]

It turns out that 1G is not a valid value for this directive.  Not sure why
I haven't run into this problem previously but setting it to a "megabyte"
value solves my problem.

Mike

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[PHP] PHP File Upload Problem

[Mike Walsh]

I have a problem uploading files with PHP which has me stumped!  I am unable
to successfully upload files.  My simple test script is as follows:

File successfully upload." ;
print "Try again?" ;
}
else
{
 print <<< __RAWHTML__


Filename:  


__RAWHTML__;
 print "Try again?" ;
}

?>


When I run it I get the following back:

array(1) { ["toProcess"]=> array(5) { ["name"]=> string(12) "100_2038.JPG"
["type"]=> string(0) "" ["tmp_name"]=> string(0) "" ["error"]=> int(1)
["size"]=> int(0) } }

Obviously I have some sort of error as my "tmp_name" key is null and the
"error" key is 1.

Any ideas or suggestions?  I am running IIS with PHP 4.3.4.  I checked my
php.ini file and the settings for uploading files look good to me:


; File Uploads ;


; Whether to allow HTTP file uploads.
file_uploads = On

; Temporary directory for HTTP uploaded files (will use system default if
not
; specified).
upload_tmp_dir = c:\windows\temp

; Maximum allowed size for uploaded files.
upload_max_filesize = 1G

Thanks for any help or suggestions.

Mike


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Re: [PHP] MySQL > Excel

[Jennifer Goodie]

 -- Original message --
From: Sam Smith <[EMAIL PROTECTED]>
> 
> I've got it working writing out a file (fopen) to CSV (comma delimited) and
> the "header('Content-Disposition: attachment; filename="myFile.csv"')"
> method but it's clumsy for the user to figure out how to use the file.
> 
> Is there some totally slick way of spitting out a file that Excel can open
> right up?

Instead of opening a file and writing to it, just push excel headers and then 
just print like you would nomally do when generating a web page.  If you output 
an html table excel will render it like a spreadsheet.  I don't think I phrased 
that very well, so here's an example
";
$begin = "";
$end = "\n";
print "";
} else{
header("Content-Type: text/plain");
header("Content-Disposition: attachment; filename=report.csv");
$joiner = ",";
$begin = "";
$end = "\n";
}

print $begin .implode($joiner, $aDisplayColumns).$end;  //prints out a 
header row with column name (stored in $aDisplayColumns with row name as key 
and display value as value)
while ($row = $dbObj->fetch_array($rs)){
unset ($push);
$push = array();
foreach ($aDisplayColumns as $key => $val)  { 
if ($sExport=='xls'){
$push[] = $row[$key];
}else{
$push[] = addslases($row[$key]);
}
}
print $begin .implode($joiner, $push).$end;
}
if ($sExport=='xls'){
print "";
}
exit;
}

Hope that helps and is not too confusing.

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RE: [PHP] Re: probably stupid, but...

[Mike Johnson]

From: Robert Sossomon [mailto:[EMAIL PROTECTED] 

> OK, I took out the extra ' that I had at the beginning, and 
> then I changed everything around to:
> 
> if (!empty($_POST['book_title_'.$i]))
> {
>$addtocart = "INSERT INTO `curriculum` VALUES 
> ('',$_POST['book_title_'.$i],$_POST['book_level_'.$i],$_POST['
> level_grades_'.$i],$_POST['book_section_'.$i],$_POST['chapter_
> '.$i],$_POST['chapter_title_'.$i],$_POST['lesson_title_'.$i],$
> _POST['skill_'.$i],$_POST['life_skill_'.$i],$_POST['success_in
> dicator_'.$i],$_POST['ncscos_'.$i],$_POST['subject_'.$i],$_POS
> T['pages_'.$i],$_POST['c_kit_'.$i])";
>echo "$addtocart";
>mysql_query($addtocart);
> 
> And it still is producing an empty page (not even echoing out 
> the $addtocart variable) when I run it.

If this is just a snippet and you do close that if clause with a curly
brace later in the code, my guess is that the parser doesn't like the
$_POST['book_title_'.$i] syntax.

Try changing them all like this, if you're looking to eliminate that
possibility:

$_POST["book_title_{$i}"]

Wish I had time to test my theory, but I'm strapped at the moment.   :)


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Web Developerwww.smarterliving.com
[EMAIL PROTECTED]   (617) 886-5539

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[PHP] MySQL > Excel

[Sam Smith]

I've got it working writing out a file (fopen) to CSV (comma delimited) and
the "header('Content-Disposition: attachment; filename="myFile.csv"')"
method but it's clumsy for the user to figure out how to use the file.

Is there some totally slick way of spitting out a file that Excel can open
right up?

thanks

sam

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Re: [PHP] HTML->PDF

[Robert Sossomon]

Amanda Hemmerich is quoted as saying on 11/12/2004 4:01 PM:
Is there a fairly straightforward way to generate a PDF out of a .php file
that's made up of includes and the includes are contructed dynamically
using data from mysql?  This page normally displays the info based on
parameters passed through the url or through a form.  I've been looking

Here's what I used to use, and i know that there are better ways to do it now,
but it works for me:
a form to pass the data from, and then some includes

include_once('/home/fpdf/fpdf/html2pdf.php');
//connect to database
include 'db.php';
include 'salesinfo.php';
$order_id = $_POST[order_id];
$faxnumber = $_POST[faxnum];
$html = "";
$time = "-";
$time .= date("mdY-His");
$outtie = "/saved_quotes/$user";
$title = "Quote for $acct $uFname $uLname on $today";
$subject = "Quote for $acct $uFname $uLname on $today";
$author = "$uFname $uLname";
$outtie .= "-";
$html .= "\n\n";
$html .= $title;
$html .= "\n\n\n";
include 'order_header.php';
$html .= $header_block;
include 'views_order_head.php';
$html .= $view_head_block;
include 'views_order_body.php';
$html .= $display_block;
$html .= "\n\n";
$outtie .= $num;
$outtie .= $time;
$tempfilename = $outtie;
$outps = $outtie;
$outps .= ".ps";
$tempfilename .= ".html";
$outtie .= ".pdf";
$out_url = "/saved_quotes/$user-$num$time.pdf";
$tempfile = fopen($tempfilename,'w');
fwrite($tempfile, $html);
fclose($tempfile);
$last_line = system("/usr/local/bin/html2ps $tempfilename > $outps", $retval);
$last_line = system("/usr/bin/ps2pdf $outps $outtie", $retval);
$last_line = system("/usr/bin/sendfax -n -d $faxnumber $outtie", $retval);
$ps_line = system("/bin/rm -f $outps", $retval);
//header("Location: $out_url");
//exit;
HTH,
Robert
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4-H Youth Development Department
200 Ricks Hall, Campus Box 7606
N.C. State University
Raleigh NC 27695-7606
Phone: 919/515-8474
Fax:   919/515-7812
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Re: [PHP] Re: probably stupid, but...

[Robert Sossomon]

Ben Ramsey is quoted as saying on 11/12/2004 3:41 PM:
You've got some parsing errors going on. Nothing particularly wrong with 
the logic...

OK, I took out the extra ' that I had at the beginning, and then I changed 
everything around to:

if (!empty($_POST['book_title_'.$i]))
   {
  $addtocart = "INSERT INTO `curriculum` VALUES 
('',$_POST['book_title_'.$i],$_POST['book_level_'.$i],$_POST['level_grades_'.$i],$_POST['book_section_'.$i],$_POST['chapter_'.$i],$_POST['chapter_title_'.$i],$_POST['lesson_title_'.$i],$_POST['skill_'.$i],$_POST['life_skill_'.$i],$_POST['success_indicator_'.$i],$_POST['ncscos_'.$i],$_POST['subject_'.$i],$_POST['pages_'.$i],$_POST['c_kit_'.$i])";
  echo "$addtocart";
  mysql_query($addtocart);

And it still is producing an empty page (not even echoing out the $addtocart 
variable) when I run it.

Unfortunately my server admins went AWOL, so I can get the exact error message, 
but I know it has to be some stupid that I just haven't put my finger on yet.

I could have had this done already doing it one line @ a time, however I want to 
be able to change either form at any time and have only 2 pieces of code to change.

Thanks for the help so far guys.
Robert
--
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4-H Youth Development Department
200 Ricks Hall, Campus Box 7606
N.C. State University
Raleigh NC 27695-7606
Phone: 919/515-8474
Fax:   919/515-7812
[EMAIL PROTECTED]
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[PHP] PDO __construct question (mysql)

[M. Sokolewicz]

hi,
currently I'm experimenting with PDO a bit. I run a local mysql server, 
version 4.1.4, so I tried connecting to that.

Here is my code at this point:
try {
$link = new PDO('mysql:dbname=mydb;host=localhost', 'me', 
'pw', array(PDO_ATTR_AUTOCOMMIT => 0, PDO_ATTR_PERSISTENT=>0));
} catch(PDOException $e) {
echo 'Connection Error: 
'.$e->getMessage()."\n".$e->getTraceAsString();
exit;
}

Now, it doesn't matter if the server is turned on or off, I am recieving:
Connection Error: [2017] Can't open named pipe to host: . pipe: MySQL (2)
At first, I thought that this was due to me writing the DSN incorrectly. 
 But after reading trough various documents, including Wez's Powerpoint 
Presentation at PHPWorks, I think the DSN I'm using IS correctly (or at 
least syntactically). After that, I figured it might be because 
PDO_mysql officially doesn't support mysql 4.1+, but when the server is 
turned OFF (the mysql server), it still reports EXACTLY the same error.

Does anyone have an idea what is wrong EXACTLY here? To me the message 
seems pretty strange, and I don't understand what it means.

Thanks,
- Tul
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RE: [PHP] What am I doing wrong - PHP

[Mike Johnson]

From: Stuart Felenstein [mailto:[EMAIL PROTECTED] 

> Ok, hopefully I can explain this clearly, even though
> I think I might be an idiot since Ive been going on
> about this for a few days.
> 
> I have a table that holds values and labels 
> i.e. 1 = New York
>  2 = Boston
>  3 = Kansas City
>  4 = Amsterdam
> 
> I want to put this table into a multiple selection
> list, that a user can choose from in a form
> My code is drawing a blank though:
> 
> //This is my call to the table "staindtypes"
>  mysql_select_db($database_lokale, $lokale);
> $indque1 = "SELECT * FROM staindtypes";
> $inds = mysql_query($indque1, $lokale) or
> die(mysql_error());
> $row_inds = mysql_fetch_assoc($inds);
> $totalRows_inds = mysql_num_rows($inds);
> $row = mysql_fetch_row;
> ?>
> 
> 
> //Here is the element and the php to loop it
> 
>id="Ind">
>   Please Select
>  do {  
> ?>
>  $row_$result['CareerCategories']?>


---^
I think your error is right here. Don't you want
$rows['CareerCategories']?

Aside from that, I'm not certain the code is exactly what you want, but
this should at least solve the blank page problem. I think PHP's barfing
on that but errors aren't being written to the browser.

Good luck!


-- 
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Web Developerwww.smarterliving.com
[EMAIL PROTECTED]   (617) 886-5539

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RE: [PHP] What am I doing wrong - PHP

[Chris W. Parker]

Stuart Felenstein 
on Friday, November 12, 2004 12:54 PM said:

> //This is my call to the table "staindtypes"
>  mysql_select_db($database_lokale, $lokale);
> $indque1 = "SELECT * FROM staindtypes";
> $inds = mysql_query($indque1, $lokale) or
> die(mysql_error());
> $row_inds = mysql_fetch_assoc($inds);
> $totalRows_inds = mysql_num_rows($inds);
> $row = mysql_fetch_row;

>   $rows = mysql_num_rows($inds);
>   if($rows > 0) {
>   mysql_data_seek($inds, 0);
> $rows = mysql_fetch_assoc($inds);
>   }
>> 
> 
> When I load the page it is blank.
> 
> Any help would be appreciated.

Well your code is a bit hard to follow (imo) but I notice that you have:

$row_inds = mysql_fetch_assoc($inds);

but then never refer to $row_inds again.

I would do the following:

\n";
if($row_inds_cnt > 0)
{
  for($i = 0; $i < $row_inds_cnt; $i++)
  {
echo " ...\n";
  }
}
else
{
  echo " empty\n";
}
echo "\n";

?>



hth,
Chris.

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[PHP] Re: What am I doing wrong - PHP

[M. Sokolewicz]

Stuart Felenstein wrote:
Ok, hopefully I can explain this clearly, even though
I think I might be an idiot since Ive been going on
about this for a few days.
I have a table that holds values and labels 
i.e. 1 = New York
 2 = Boston
 3 = Kansas City
 4 = Amsterdam

I want to put this table into a multiple selection
list, that a user can choose from in a form
My code is drawing a blank though:
//This is my call to the table "staindtypes"
why are you doing this?
$totalRows_inds = mysql_num_rows($inds);
$row = mysql_fetch_row;
that's supposed to be a function... no? But then... why is it used here?
?>
//Here is the element and the php to loop it

  
id="Ind">
  Please Select

do {  
why are you using do..while? It's far easier to just use while
?>

 0) {
  mysql_data_seek($inds, 0);
  $rows = mysql_fetch_assoc($inds);
  }
 ?>
When I load the page it is blank.
Any help would be appreciated.
Stuart
I would suggest writing it like this:

mysql_select_db($database_lokale, $lokale);
$inds = mysql_query("SELECT * FROM staindtypes", $lokale) or 
die(mysql_error());
?>


Please Select

while($ind = mysql_fetch_array($inds, MYSQL_ASSOC)) {
   echo ''.$inds['CareerCategories'].'';
}
echo '';
mysql_free_result($inds);	// just in case
?>

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Re: [PHP] Re: Which PHP for MySQL 4.1

[Sebastian Mendel]

Mario Bittencourt wrote:
I could not compile php 5.0.2 with the latest mysql 4.1.7.
I've installed the rpms (server,max,client,devel,shared) from mysql.com.
./configure --with-mnogosearch --with-xml  --with-mysql=/usr
--with-mysqli=/usr/bin/mysql_config --with-apxs2 --enable-soap
When I compile I get tons of messages like this
/usr/lib/mysql/libmysqlclient.a(net.o)(.text+0x250): first defined here
/usr/lib/mysql/libmysqlclient.a(net.o)(.text+0x330): In function
`net_write_command':
I have even tried only with mysqli or mysql and got the same result.
Any ideias ?
try one mysql-extension as shared:
--with-mysql=/usr,shared --with-mysqli=/usr/bin/mysql_config
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[PHP] HTML->PDF

[Amanda Hemmerich]

Is there a fairly straightforward way to generate a PDF out of a .php file
that's made up of includes and the includes are contructed dynamically
using data from mysql?  This page normally displays the info based on
parameters passed through the url or through a form.  I've been looking
for something I could download and just pass it the url, but if I had to
build something myself, I could, but I don't know if there are any php
modules to support it.  ANy tips?

Thanks.

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RE: [PHP] probably stupid, but...

[Danny Brow]

On Fri, 2004-11-12 at 14:35 -0600, Jay Blanchard wrote:
> [snip]
> Did that and it fixed only that piece (saw it right after I sent the
> email out 
> to the group).  I am thinking that it is still somewhat of the
> iterations that 
> are causing problems.  I am waiting on the server guy to get back with
> me as to 
> what the new error message looks like.
> [/snip]
> 
> Have you echo'd the query out to see what it looks like?
> 

It's probably a good idea to get the part of a reply that tells everyone
who your replying too. Not sure if it was me or Chris P.

Chris has a way better answer then I. So I assume your replying to mine.

Dan.

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[PHP] What am I doing wrong - PHP

[Stuart Felenstein]

Ok, hopefully I can explain this clearly, even though
I think I might be an idiot since Ive been going on
about this for a few days.

I have a table that holds values and labels 
i.e. 1 = New York
 2 = Boston
 3 = Kansas City
 4 = Amsterdam

I want to put this table into a multiple selection
list, that a user can choose from in a form
My code is drawing a blank though:

//This is my call to the table "staindtypes"



//Here is the element and the php to loop it

  
  Please Select


 0) {
  mysql_data_seek($inds, 0);
  $rows = mysql_fetch_assoc($inds);
  }
 ?>

When I load the page it is blank.

Any help would be appreciated.

Stuart

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RE: [PHP] Sending Data with Ascii data

[Dev]

Actually yes I have.  Many times as a matter of fact.
What was happing was that the 0xC1 was being translated into it dec form of 28.
Thankfully i was able to resolve the issue by using:
pack("C",28)
But thanks Jay for the help!
At 03:29 PM 11/12/2004, Jay Blanchard wrote:
[snip]
I am working on a Socket script that needs to send a binary 0x1C to
another
applicaiton that is connected to the socket.  Any way in PHP to do this
so
that I do not have to go and learn C++ over the weekend
Does anyone have a clue what needs to be done to make this work?
[/snip]
Are we to assume that you have RTFM http://www.php.net/sockets ?

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[PHP] Re: probably stupid, but...

[Ben Ramsey]

You've got some parsing errors going on. Nothing particularly wrong with 
the logic...

$i=1;
while ($i<20)
{
 if ($_POST[book_title_$i]' != "")
change the if statement to:
if ($_POST["book_title_$i"] != "")
The problem you have is that the $_POST var you're referencing, first of 
all, isn't included in quotation marks, so the code probably thinks it's 
a constant that's not defined. Second of all, because it's not included 
in quotation marks, it's having problems with adding the $i var to the 
end of the POST var name. You could also do: $_POST['book_title_' . $i] 
and achieve the same effect. Lastly, what's that single quotation mark 
doing in there? Get rid of it.

 {
  INSERT INTO `curriculum` VALUES 
('','$_POST[book_title_$i]','$_POST[book_level_$i]','$_POST[level_grades_$i]','$_POST[book_section_$i]','$_POST[chapter_$i]','$_POST[chapter_title_$i]','$_POST[lesson_title_$i]','$_POST[skill_$i]','$_POST[life_skill_$i]','$_POST[success_indicator_$i]','$_POST[ncscos_$i]','$_POST[subject_$i]','$_POST[pages_$i]','$_POST[c_kit_$i]'); 
First of all, you're trying to execute a SQL statement, but you're not 
saving it to a variable, nor are you executing it against any kind of 
database. So, it's doing nothing. Save it to a variable by doing:

$sql = "INSERT INTO ...
The next thing you need to worry about is how to get your $_POST 
variables into the SQL statement. This problem is similar to what you 
have above. It should look something like this:

$sql = "INSERT INTO `curriculum` VALUES ('','" . $_POST['book_title_' . 
$i] . "','" . $_POST['book_level_' . $i] . "','" . and so on

Lastly, you'll need to execute the statement against a database. Turn to 
the PHP manual for this help: 

I would suggest you read up on how variables get processed, as well. 



  $message .= "The entry  $i was entered
";
 $i++;
 }
 else
{  $i++; }
}
But I get THIS error in the log:
 [12-Nov-2004 14:59:19] PHP Parse error:  parse error, unexpected  
T_VARIABLE, expecting ']' in  
/home/public/html/depts/fourh/curriculum_form_post.php on line 19

-
How can I go about iterating through the script?  or do I just need to 
write 20 if/else statements and separate inserts?

--
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Zend Certified Engineer
http://benramsey.com
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RE: [PHP] probably stupid, but...

[Jay Blanchard]

[snip]
Did that and it fixed only that piece (saw it right after I sent the
email out 
to the group).  I am thinking that it is still somewhat of the
iterations that 
are causing problems.  I am waiting on the server guy to get back with
me as to 
what the new error message looks like.
[/snip]

Have you echo'd the query out to see what it looks like?

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RE: [PHP] probably stupid, but...

[Chris W. Parker]

Robert Sossomon 
on Friday, November 12, 2004 12:09 PM said:

> I have a form that sends 20 rows of data into a script, instead of
> having to write 20 separate add functions, I wrote this piece of
> code...

you've actually got quite a few mistakes.

>   if ($_POST[book_title_$i]' != "")

notice --^

there is an extra '. the line should really look like:

if (!empty($_POST['book_title_'.$i])
{
  ...

>   {
>INSERT INTO `curriculum` VALUES
>
('','$_POST[book_title_$i]','$_POST[book_level_$i]','$_POST[level_grades
_$i]','$_POST[book_section_$i]','$_POST[chapter_$i]','$_POST[chapter_tit
le_$i]','$_POST[lesson_title_$i]','$_POST[skill_$i]','$_POST[life_skill_
$i]','$_POST[success_indicator_$i]','$_POST[ncscos_$i]','$_POST[subject_
$i]','$_POST[pages_$i]','$_POST[c_kit_$i]');

and then here you don't even assign that sql statement to anything. PHP
doesn't know what to do with it.

also you need to wrap your array values in { } when an array is
referenced within a string. i.e.

// normal
$value = $_GET['something'];

// with { }
$value = "Here is some data: {$_GET['something']}";


hth,
chris.

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Re: [PHP] probably stupid, but...

[Robert Sossomon]

Jay Blanchard is quoted as saying on 11/12/2004 3:28 PM:
> [snip]
Did that and it fixed only that piece (saw it right after I sent the email out 
to the group).  I am thinking that it is still somewhat of the iterations that 
are causing problems.  I am waiting on the server guy to get back with me as to 
what the new error message looks like.

Robert
--
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4-H Youth Development Department
200 Ricks Hall, Campus Box 7606
N.C. State University
Raleigh NC 27695-7606
Phone: 919/515-8474
Fax:   919/515-7812
[EMAIL PROTECTED]
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Re: [PHP] probably stupid, but...

[Danny Brow]

On Fri, 2004-11-12 at 15:08 -0500, Robert Sossomon wrote:
> I have a form that sends 20 rows of data into a script, instead of having to 
> write 20 separate add functions, I wrote this piece of code...
> 
> $i=1;
> while ($i<20)
> {
>   if ($_POST[book_title_$i]' != "") 
// One problem maybe the quote you have at the end of your $_POST
request.

>   {
>INSERT INTO `curriculum` VALUES 

// You could probably simplify this with a while or for loop. But I'm no
PHP expert. Perhaps you could use an array to clean this up.

> ('','$_POST[book_title_$i]','$_POST[book_level_$i]','$_POST[level_grades_$i]','$_POST[book_section_$i]','$_POST[chapter_$i]','$_POST[chapter_title_$i]','$_POST[lesson_title_$i]','$_POST[skill_$i]','$_POST[life_skill_$i]','$_POST[success_indicator_$i]','$_POST[ncscos_$i]','$_POST[subject_$i]','$_POST[pages_$i]','$_POST[c_kit_$i]');
> 
>$message .= "The entry  $i was entered
> ";
>   $i++;
>   }
>   else
> {  $i++; }
> }
> 

Sorry if I missed anything else :->

Dan.


> But I get THIS error in the log:
>   [12-Nov-2004 14:59:19] PHP Parse error:  parse error, unexpected  
> T_VARIABLE, 
> expecting ']' in  /home/public/html/depts/fourh/curriculum_form_post.php on 
> line 19
> 
> -
> 
> How can I go about iterating through the script?  or do I just need to write 
> 20 
> if/else statements and separate inserts?
> 
> Thanks,
> Robert
> 
> -- 
> Robert Sossomon, Business and Technology Application Technician
> 4-H Youth Development Department
> 200 Ricks Hall, Campus Box 7606
> N.C. State University
> Raleigh NC 27695-7606
> Phone: 919/515-8474
> Fax:   919/515-7812
> [EMAIL PROTECTED]
> 

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RE: [PHP] Sending Data with Ascii data

[Jay Blanchard]

[snip]
I am working on a Socket script that needs to send a binary 0x1C to
another 
applicaiton that is connected to the socket.  Any way in PHP to do this
so 
that I do not have to go and learn C++ over the weekend

Does anyone have a clue what needs to be done to make this work?
[/snip]

Are we to assume that you have RTFM http://www.php.net/sockets ?

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RE: [PHP] probably stupid, but...

[Jay Blanchard]

[snip]
$i=1;
while ($i<20)
{
  if ($_POST[book_title_$i]' != "")
  {
   INSERT INTO `curriculum` VALUES 
('','$_POST[book_title_$i]','$_POST[book_level_$i]','$_POST[level_grades
_$i]','$_POST[book_section_$i]','$_POST[chapter_$i]','$_POST[chapter_tit
le_$i]','$_POST[lesson_title_$i]','$_POST[skill_$i]','$_POST[life_skill_
$i]','$_POST[success_indicator_$i]','$_POST[ncscos_$i]','$_POST[subject_
$i]','$_POST[pages_$i]','$_POST[c_kit_$i]');

   $message .= "The entry  $i was entered";
  $i++;
  }
  else
{  $i++; }
}

But I get THIS error in the log:
  [12-Nov-2004 14:59:19] PHP Parse error:  parse error, unexpected
T_VARIABLE, 
expecting ']' in  /home/public/html/depts/fourh/curriculum_form_post.php
on line 19
[/snip]

Where is line 19? Is this it?

if ($_POST[book_title_$i]' != "")

If so, remove the apostrophe after the ]

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[PHP] Sending Data with Ascii data

[Dev]

Hello,
I am working on a Socket script that needs to send a binary 0x1C to another 
applicaiton that is connected to the socket.  Any way in PHP to do this so 
that I do not have to go and learn C++ over the weekend

Does anyone have a clue what needs to be done to make this work?
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[PHP] probably stupid, but...

[Robert Sossomon]

I have a form that sends 20 rows of data into a script, instead of having to 
write 20 separate add functions, I wrote this piece of code...

$i=1;
while ($i<20)
{
 if ($_POST[book_title_$i]' != "")
 {
  INSERT INTO `curriculum` VALUES 
('','$_POST[book_title_$i]','$_POST[book_level_$i]','$_POST[level_grades_$i]','$_POST[book_section_$i]','$_POST[chapter_$i]','$_POST[chapter_title_$i]','$_POST[lesson_title_$i]','$_POST[skill_$i]','$_POST[life_skill_$i]','$_POST[success_indicator_$i]','$_POST[ncscos_$i]','$_POST[subject_$i]','$_POST[pages_$i]','$_POST[c_kit_$i]');

  $message .= "The entry  $i was entered
";
 $i++;
 }
 else
{  $i++; }
}
But I get THIS error in the log:
 [12-Nov-2004 14:59:19] PHP Parse error:  parse error, unexpected  T_VARIABLE, 
expecting ']' in  /home/public/html/depts/fourh/curriculum_form_post.php on line 19

-
How can I go about iterating through the script?  or do I just need to write 20 
if/else statements and separate inserts?

Thanks,
Robert
--
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4-H Youth Development Department
200 Ricks Hall, Campus Box 7606
N.C. State University
Raleigh NC 27695-7606
Phone: 919/515-8474
Fax:   919/515-7812
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RE: [PHP] PHP / LDAP with Windows logon

[Christopher . Wood]

I found this on the php site after some searching. I haven't been able to
test it yet since the PHP guy works nights:

 http://us2.php.net/manual/en/ref.ldap.php

If anyone else has tried this, or could the original author (Jon) comment
please?

Thanks!
Chris

jon dot caplinger at broadwing dot com
08-Nov-2002 10:44 
Here is an example of searching active directory in w2k. Active directory
requires a user account that has permissions to search the tree.

/* The following values are used for the example:
  1.  Domain =  microsoft.com
  2.  Server =  unstable
  3.  User = bgates
  4.  Password = iloveopensource
*/

// Get name value to search for from submitted form.

if (isset($HTTP_GET_VARS["name"])) {
 $name = $HTTP_GET_VARS["name"];
}

$ldap_server = "ldap://unstable.microsoft.com";;
$auth_user = "[EMAIL PROTECTED]";
$auth_pass = "iloveopensource";

// Set the base dn to search the entire microsoft.com directory.

$base_dn = "DC=microsoft, DC=com";

/* filter the search for all people in the microsoft.com tree that have a
name that matches any one of the following attributes name, displayname, or
cn. */
 
$filter = "(&(objectClass=user)(objectCategory=person)
(|(name=$name*)(displayname=$name*)(cn=$name*)))";

// connect to server

if (!([EMAIL PROTECTED]($ldap))) {
 die("Could not connect to ldap server");
}

// bind to server

if (!([EMAIL PROTECTED]($connect, $auth_user, $auth_pass))) {
 die("Unable to bind to server");  
}

// search active directory

if (!([EMAIL PROTECTED]($connect, $base_dn, $filter))) {
 die("Unable to search ldap server"); 
}

$number_returned = ldap_count_entries($connect,$search);
$info = ldap_get_entries($connect, $search);

echo "The number of entries returned is ". $number_returned;

for ($i=0; $i<$info["count"]; $i++) {
   echo "Name is: ". $info[$i]["name"];
   echo "Display name is: ". $info[$i]["displayname"][0];
   echo "Email is: ". $info[$i]["mail"][0];
   echo "Telephone number is: ". $info[$i]["telephonenumber"][0];
} 

-Original Message-
From: Michael Gallant [mailto:[EMAIL PROTECTED]
Sent: Friday, November 12, 2004 3:10 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] PHP / LDAP with Windows logon


I am interested if anyone has ever determined a way to do this or if
it is technically impossible.

To my knowledge, I don't know of any way to do that from a non-windows
server.


On Fri, 12 Nov 2004 08:40:03 -0500, [EMAIL PROTECTED]
<[EMAIL PROTECTED]> wrote:
> Hello, I have an issue with a PHP interface. We have many engineering
users
> who will be using a request ticket system developed in PHP here. We don't
> know in advance who will be using the system and there may be new people
in
> all the time. Currently I have to create a login for each person who needs
> to use the system, so I have to get a request for a login, create the
login,
> and fill in their contact information. Since we work with engineers on a
> 12-15 hour time difference, it might take a whole day or more to get the
> login id request filled before they can open a ticket. Plus there's the
> whole inconvenience of having to login to another website. The site is
> inside our secure intranet, so we don't really need a double layer of
> security.
> 
> Since we normally logon to a Windows network, what I would like to do is
to
> detect the user's windows login id when he accesses the PHP page, and
> automatically reference his contact information from the windows LDAP
> server, so the user can be authenticated by his  current windows login
> information, and not have to enter a separate login on the request page.
Is
> this possible, and what is an easy way to do this?
> 
> Thanks!
> 
> Chris
> 
>

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Re: [PHP] PHP / LDAP with Windows logon

[Michael Gallant]

I am interested if anyone has ever determined a way to do this or if
it is technically impossible.

To my knowledge, I don't know of any way to do that from a non-windows server.


On Fri, 12 Nov 2004 08:40:03 -0500, [EMAIL PROTECTED]
<[EMAIL PROTECTED]> wrote:
> Hello, I have an issue with a PHP interface. We have many engineering users
> who will be using a request ticket system developed in PHP here. We don't
> know in advance who will be using the system and there may be new people in
> all the time. Currently I have to create a login for each person who needs
> to use the system, so I have to get a request for a login, create the login,
> and fill in their contact information. Since we work with engineers on a
> 12-15 hour time difference, it might take a whole day or more to get the
> login id request filled before they can open a ticket. Plus there's the
> whole inconvenience of having to login to another website. The site is
> inside our secure intranet, so we don't really need a double layer of
> security.
> 
> Since we normally logon to a Windows network, what I would like to do is to
> detect the user's windows login id when he accesses the PHP page, and
> automatically reference his contact information from the windows LDAP
> server, so the user can be authenticated by his  current windows login
> information, and not have to enter a separate login on the request page. Is
> this possible, and what is an easy way to do this?
> 
> Thanks!
> 
> Chris
> 
>

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Re: [PHP] Re: Which PHP for MySQL 4.1

[John Nichel]

Mario Bittencourt wrote:
I could not compile php 5.0.2 with the latest mysql 4.1.7.
I've installed the rpms (server,max,client,devel,shared) from mysql.com.
./configure --with-mnogosearch --with-xml  --with-mysql=/usr
--with-mysqli=/usr/bin/mysql_config --with-apxs2 --enable-soap
When I compile I get tons of messages like this
/usr/lib/mysql/libmysqlclient.a(net.o)(.text+0x250): first defined here
/usr/lib/mysql/libmysqlclient.a(net.o)(.text+0x330): In function
`net_write_command':
I have even tried only with mysqli or mysql and got the same result.
Any ideias ?
I'm betting you have mnogosearch compiled with MySQL support, right?  I 
had this problem last week.  Remove mnogosearch, recompile it without 
MySQL support, then configure/make/make install php.  After that's done, 
you can redo mnogosearch with MySQL support.

--
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ÜberGeek
KegWorks.com
716.856.9675
[EMAIL PROTECTED]
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Re: [PHP] Re: Which PHP for MySQL 4.1

[Mario Bittencourt]

I could not compile php 5.0.2 with the latest mysql 4.1.7.

I've installed the rpms (server,max,client,devel,shared) from mysql.com.

./configure --with-mnogosearch --with-xml  --with-mysql=/usr
--with-mysqli=/usr/bin/mysql_config --with-apxs2 --enable-soap

When I compile I get tons of messages like this

/usr/lib/mysql/libmysqlclient.a(net.o)(.text+0x250): first defined here
/usr/lib/mysql/libmysqlclient.a(net.o)(.text+0x330): In function
`net_write_command':

I have even tried only with mysqli or mysql and got the same result.

Any ideias ?

Fedora Core 3 Machine

On Fri, 12 Nov 2004 11:03:23 +0100, Sebastian Mendel
<[EMAIL PROTECTED]> wrote:
> 
> 
> C.F. Scheidecker Antunes wrote:
> > Hello,
> >
> > I would like to migrate my MySQL servers from 4.0 to 4.1.
> >
> > As I use PHP as well as Java with these servers I wonder what PHP 4
> > version would be compatible with MySQL 4.1.
> >
> > Has anyone used MySQL 4.1 with PHP yet?
> >
> > I appreciate your thoughts.
> >
> > Thanks.
> 
> i run 4.1.x for a while, without problems,
> 
> after upgrading you have to rebuild you php to use the new mysql_librarys
> 
> and you have to run mysql_fix_privilege_tables on the linux/unix shell
> 
> 4.1. uses a new display-format for timestamps!
> 4.1. uses a new encryption method for password(), with this function are
> all mysql_passwords stored in the db, thats why you have to run
> mysql_fix_privilege_tables
> 
> read carefully through all 4.1. changelogs!
> 
> --
> Sebastian Mendel
> 
> www.sebastianmendel.de www.warzonez.de www.tekkno4u.de www.nofetish.com
> www.sf.net/projects/phpdatetimewww.sf.net/projects/phptimesheet
> 
> 
> 
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> To unsubscribe, visit: http://www.php.net/unsub.php
> 
>

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Re: [PHP] Question for the PHP consultants out there.

[Daniel Lahey]

What web based software project management tool do you use to keep 
track of projects, project tasks, customer requests, and bug reports?
You might try Ace Project:  http://www.aceproject.com/
"An error is the more dangerous in proportion to the degree of truth 
which it contains." - Henri Frederic Amiel

[PHP] Re: session.use_trans_sid

[Ben Ramsey]

Jon Hill wrote:
I have a site that has session.use_trans_sid = 1.
It seems that the first time I visit a page when I open up my browser, URLs 
are getting rewritten even though a cookie IS being set. If I refresh or move 
on to another page, the problem goes away, i.e. no more session ids appended 
to URLs.

I don't want to turn off trans_sid for this site because I want people to able 
to use it without cookies being set.
When you first hit a page that creates a cookie, the cookie is not 
accessible to the application until the page is refreshed or you browse 
to another page in the same domain. This is why the SID is showing up in 
the URL when you first hit the site. Though the cookie is being saved to 
the browser, the application cannot yet access it until you browse to 
another page.

Read up on it here: 
In particular: "Cookies will not become visible until the next loading 
of a page that the cookie should be visible for."

--
Ben Ramsey
Zend Certified Engineer
http://benramsey.com
---
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The Southeast's premier PHP community.
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[PHP] session.use_trans_sid

[Jon Hill]

Hello

I have a site that has session.use_trans_sid = 1.
It seems that the first time I visit a page when I open up my browser, URLs 
are getting rewritten even though a cookie IS being set. If I refresh or move 
on to another page, the problem goes away, i.e. no more session ids appended 
to URLs.

I don't want to turn off trans_sid for this site because I want people to able 
to use it without cookies being set.

For example





link




The first time I request the page, a cookie gets set, AND the URL gets 
rewritten. After that, no more URL rewrites.

Can anyone point to where I might be going wrong, or this just an odd 
behaviour of session.use_trans_sid = 1

Cyril

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[PHP] Re: Current URL?

[pete M]

$_SERVER['REQUEST_URI'];
Matthew Weier O'Phinney wrote:
* Jason Paschal <[EMAIL PROTECTED]>:
Trying to get the current viewed page's URL (query string intact).
this works, but infrequently:
$url = $_SERVER['URI']; 

and this ignores the query string:
$url = $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'];
I'm certain there's a way,  that is browser-independent,  to get your
script to grab the current URL (even if the script is an include).
i'm just trying to get a log of users currently online, and which page
they are viewing, and while the $_SERVER['REMOTE_ADDR'] will
invariably grab the IP, $_SERVER['URI'] is often empty.

Try:
$url = $_SERVER['PHP_SELF'] . '?' . $_SERVER['QUERY_STRING'];
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[PHP] Re: Unsetting vars when not needed?

[pete M]

Unsetting class objects does take time and is really of no benefit 
unless there are memory problems

as for freeing resuslts - the same applies
pete
Jordi Canals wrote:
Hi all,
I was working now in a new site developed with PHP 5.0.2 and a wonder
came to me:
Is usefull and recommended to unset a class instance when not needed?
Specially when the class was instantiated inside a function and the
function ends. In this case, the system should  automatically destroy
the instance (as it is a local var inside a function).
If we manually unset the instance at the end of the function, does
this affect the PHP performance? I mean, will PHP have to do an extra
job unsetting the var?
Also, the same question arises with database results. Is it worth to
call mysql_free_result at the end of a function that uses it? Must
take into consideration that there are lots of functions that use lots
of MySQL results.
Thanks for any comment
Jordi.
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Re: [PHP] Session file not written, session variables messed up.

[Rodolfo Gonzalez]

Hi Klaus,

On Fri, 12 Nov 2004, Klaus Reimer wrote:
> > The weirdness comes when in one frame the script will print "Agent Smith"
> > while in the other frame of the same frameset the script which loads on it
> > will print "Thomas Anderson"...
>
> Are both frames loaded at the same time? It's not possible to have two
> concurrently running scripts access the same session at the same time


Yes, both are loaded at the same time, I mean, in the same frameset. I
don't use trans_sid, and I don't pass the SID constant nor the
session_name()=session_id() as a GET to the frame src's referred from the
frameset, so I relay on cookies. Both scripts also do a check against a
database to see if the session id stored on it is the same as the session
id which the login script stored in the $_SESSION array, for that
username, so it is supposed that every username logged on the scripts
would have one unique session id...


> always use session_start() in the PHP code. Maybe the auto_start session
>   behaves differently. Maybe you can try disabling auto_start and start
> the session manually. I don't think it make a difference, but who knows.


I should try it anyway, indeed. Also, do you think that with using another
session handler (mm perhaps) instead of files the execution could speed up
or avoid file problems?. The load of the servers is not that high anyway.

I forgot to mention, I'm also using Turck MMCache as cache and
optimizer... I don't know if this could cause something weird (wouldn't
sound logical, but...). Turck MMCache version is 2.4.6.


> On the other hand: Have you checked that your disk has enough room for
> more sessions? Maybe you are working on the bleeding edge of your


Yes, I thought it too, but it still has some Gb of free space. I also
checked for problems with available file handlers/excesive opened files on
the OS side, but everything seems normal.

Thank you,
Rodolfo.

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Re: [PHP] Syslog Parser

[Greg Donald]

On Fri, 12 Nov 2004 09:21:45 -, Nunners <[EMAIL PROTECTED]> wrote:
> I've successfully got the syslog server to write to a mysql table, but I now
> want to find something that will give me graphs, breakdowns etc for the
> syslog.

Perl has all kinds of log parsing modules, and you might also try freshmeat.

http://cpan.perl.org/
http://freshmeat.net/

For graphing in PHP I use JPGraph:

http://www.aditus.nu/jpgraph/index.php


-- 
Greg Donald
Zend Certified Engineer
http://gdconsultants.com/
http://destiney.com/

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Re: [PHP] Unsetting vars when not needed?

[Brent Baisley]

I use mysql_free_result when I'm done with the particular query, but I 
don't really bother unsetting things unless I'm doing something that is 
using a lot of memory. PHP will clear everything at the end of the run 
anyway. I guess technically it's garbage collection, but PHP is wiping 
everything, so it doesn't have the overhead of checking what's been 
used, still in use or expired. It's just a wipe.
Unsetting is a good coding habit to get into, but I'm not sure of the 
performance benefits. There are lots of others areas I would focus on 
first to get better performance, like minimizing the number of 
connections you need to make to mysql, optimizing your queries, output 
buffering, etc.

On Nov 12, 2004, at 8:53 AM, Jordi Canals wrote:
Hi all,
I was working now in a new site developed with PHP 5.0.2 and a wonder
came to me:
Is usefull and recommended to unset a class instance when not needed?
Specially when the class was instantiated inside a function and the
function ends. In this case, the system should  automatically destroy
the instance (as it is a local var inside a function).
If we manually unset the instance at the end of the function, does
this affect the PHP performance? I mean, will PHP have to do an extra
job unsetting the var?
Also, the same question arises with database results. Is it worth to
call mysql_free_result at the end of a function that uses it? Must
take into consideration that there are lots of functions that use lots
of MySQL results.
Thanks for any comment
Jordi.
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--
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Systems Architect
Landover Associates, Inc.
Search & Advisory Services for Advanced Technology Environments
p: 212.759.6400/800.759.0577
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RE: [PHP] Re: Help: Database Search

[Graham Cossey]

What I meant was that the $sql variable should contain
a where clause of "WHERE vendorjobs.Industry IN (2,3,5)"
if you had a multi-element array or "WHERE vendorjobs.Industry 
= 2" if you had a single-element array.

The IN statement is easier to construct than multiple ORs and
tends to run faster as well.

Graham

> -Original Message-
> From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
> Sent: 12 November 2004 14:13
> To: Graham Cossey; Sebastian Mendel; [EMAIL PROTECTED]
> Subject: RE: [PHP] Re: Help: Database Search 
> 
> 
> 
> --- Graham Cossey <[EMAIL PROTECTED]> wrote:
> 
> > This should result in:
> > 
> > WHERE vendorjobs.Industry IN (2,3,5)
> > 
> > OR
> > 
> > WHERE vendorjobs.Industry = 2
> > 
> > HTH
> > Graham
> 
> Not sure what you mean by the above ?
> 
> Stuart
> 
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> 
> 

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RE: [PHP] Re: Help: Database Search

[Stuart Felenstein]

--- Graham Cossey <[EMAIL PROTECTED]> wrote:

> This should result in:
> 
> WHERE vendorjobs.Industry IN (2,3,5)
> 
> OR
> 
> WHERE vendorjobs.Industry = 2
> 
> HTH
> Graham

Not sure what you mean by the above ?

Stuart

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[PHP] Re: Current URL?

[Matthew Weier O'Phinney]

* Jason Paschal <[EMAIL PROTECTED]>:
> Trying to get the current viewed page's URL (query string intact).
>
> this works, but infrequently:
>
> $url = $_SERVER['URI']; 
>
> and this ignores the query string:
>
> $url = $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'];
>
> I'm certain there's a way,  that is browser-independent,  to get your
> script to grab the current URL (even if the script is an include).
>
> i'm just trying to get a log of users currently online, and which page
> they are viewing, and while the $_SERVER['REMOTE_ADDR'] will
> invariably grab the IP, $_SERVER['URI'] is often empty.

Try:

$url = $_SERVER['PHP_SELF'] . '?' . $_SERVER['QUERY_STRING'];

-- 
Matthew Weier O'Phinney   | mailto:[EMAIL PROTECTED]
Webmaster and IT Specialist   | http://www.garden.org
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RE: [PHP] Re: Help: Database Search

[Graham Cossey]

I think you're implode example is pretty close.

 1)
  {
$IndStr = implode("','", $Ind);
$where[] = "vendorjobs.Industry IN($IndStr)";
  }else{
$where[] = "vendorjobs.Industry = {$Ind[0]}";
}else{
  // Is there an error if not an array?
}

$sql = 'SELECT ...
 FROM vendorjobs
 WHERE ' . implode( ' AND ', $where );
?>

Not sure if you need the {} above, I think you do as it's an array reference
in a string.

This should result in:

WHERE vendorjobs.Industry IN (2,3,5)

OR

WHERE vendorjobs.Industry = 2

HTH
Graham



> -Original Message-
> From: Stuart Felenstein [mailto:[EMAIL PROTECTED]
> Sent: 12 November 2004 12:42
> To: Sebastian Mendel; [EMAIL PROTECTED]
> Subject: Re: [PHP] Re: Help: Database Search
>
>
>
> --- Sebastian Mendel <[EMAIL PROTECTED]> wrote:
> >
> > $where = array();
> >
> > if ( isset($_POST['Ind']) ) {
> >  $where[] = 'vendorjobs.Industry = ' . (int)
> > $_POST['Ind'];
> > }
> > if ( isset($_POST['Days']) ) {
> >  $where[] = 'Date_Sub(Curdate(), interval ' .
> > (int) $_POST['Days'] .
> > ' day) <= PostStart';
> > }
> >
> > $sql = '
> >   SELECT ...
> > FROM vendorjobs
> >WHERE ' . implode( ' AND ', $where );
> >
>
> Sebastian, I meant to thank you for this code the
> other day.
> What I'm trying to figure out is some of my elements
> are arrays themselves.  So for example I have this :
>
> $Ind = "";
> $Ind = $HTTP_POST_VARS['Ind'];
> if (count($Ind) > 0 AND is_array($Ind)) {
>  $Ind = "'".implode("','", $Ind)."'";
> }
>
> So how would this code , or array get into what you
> stated as:
>
> > $where = array();
> >
> > if ( isset($_POST['Ind']) ) {
> >  $where[] = 'vendorjobs.Industry = ' . (int)
> > $_POST['Ind'];
> > }
>
> I guess that is putting an array into an array ?
> Not quite sure how the loop would go.
>
> Thank you,
> Stuart
>
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>
>

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[PHP] Unsetting vars when not needed?

[Jordi Canals]

Hi all,

I was working now in a new site developed with PHP 5.0.2 and a wonder
came to me:

Is usefull and recommended to unset a class instance when not needed?

Specially when the class was instantiated inside a function and the
function ends. In this case, the system should  automatically destroy
the instance (as it is a local var inside a function).

If we manually unset the instance at the end of the function, does
this affect the PHP performance? I mean, will PHP have to do an extra
job unsetting the var?

Also, the same question arises with database results. Is it worth to
call mysql_free_result at the end of a function that uses it? Must
take into consideration that there are lots of functions that use lots
of MySQL results.

Thanks for any comment
Jordi.

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[PHP] PHP / LDAP with Windows logon

[Christopher . Wood]

Hello, I have an issue with a PHP interface. We have many engineering users
who will be using a request ticket system developed in PHP here. We don't
know in advance who will be using the system and there may be new people in
all the time. Currently I have to create a login for each person who needs
to use the system, so I have to get a request for a login, create the login,
and fill in their contact information. Since we work with engineers on a
12-15 hour time difference, it might take a whole day or more to get the
login id request filled before they can open a ticket. Plus there's the
whole inconvenience of having to login to another website. The site is
inside our secure intranet, so we don't really need a double layer of
security. 

Since we normally logon to a Windows network, what I would like to do is to
detect the user's windows login id when he accesses the PHP page, and
automatically reference his contact information from the windows LDAP
server, so the user can be authenticated by his  current windows login
information, and not have to enter a separate login on the request page. Is
this possible, and what is an easy way to do this?

Thanks!

Chris

Re: [PHP] Re: Help: Database Search

[Stuart Felenstein]

--- Sebastian Mendel <[EMAIL PROTECTED]> wrote:
> 
> $where = array();
> 
> if ( isset($_POST['Ind']) ) {
>  $where[] = 'vendorjobs.Industry = ' . (int)
> $_POST['Ind'];
> }
> if ( isset($_POST['Days']) ) {
>  $where[] = 'Date_Sub(Curdate(), interval ' .
> (int) $_POST['Days'] . 
> ' day) <= PostStart';
> }
> 
> $sql = '
>   SELECT ...
> FROM vendorjobs
>WHERE ' . implode( ' AND ', $where );
> 
 
Sebastian, I meant to thank you for this code the
other day.  
What I'm trying to figure out is some of my elements
are arrays themselves.  So for example I have this :

$Ind = "";
$Ind = $HTTP_POST_VARS['Ind'];
if (count($Ind) > 0 AND is_array($Ind)) {
 $Ind = "'".implode("','", $Ind)."'";
}

So how would this code , or array get into what you
stated as:

> $where = array();
> 
> if ( isset($_POST['Ind']) ) {
>  $where[] = 'vendorjobs.Industry = ' . (int)
> $_POST['Ind'];
> }

I guess that is putting an array into an array ?
Not quite sure how the loop would go.

Thank you,
Stuart

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[PHP] Re: parsing /'s in urls

[Sebastian Mendel]

[EMAIL PROTECTED] wrote:
My host recently upgraded PHP.  I had a script, download.php, that would
work like this
http://www.myhost.com/download.php/30/file.torrent
the download.php script would take the 30, look up the real filename in the
database, and readfile() it back.  this was a great setup because the
browser just thought it was accessing a direct link to a file.
But now download.php/30/file.torrent results in a 404.
Is this something I can change back?
this is an apache related thing
http://httpd.apache.org/docs-2.0/mod/core.html#acceptpathinfo
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[PHP] Re: Which PHP for MySQL 4.1

[Sebastian Mendel]

C.F. Scheidecker Antunes wrote:
Hello,
I would like to migrate my MySQL servers from 4.0 to 4.1.
As I use PHP as well as Java with these servers I wonder what PHP 4 
version would be compatible with MySQL 4.1.

Has anyone used MySQL 4.1 with PHP yet?
I appreciate your thoughts.
Thanks.
i run 4.1.x for a while, without problems,
after upgrading you have to rebuild you php to use the new mysql_librarys
and you have to run mysql_fix_privilege_tables on the linux/unix shell
4.1. uses a new display-format for timestamps!
4.1. uses a new encryption method for password(), with this function are 
all mysql_passwords stored in the db, thats why you have to run 
mysql_fix_privilege_tables

read carefully through all 4.1. changelogs!
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Re: [PHP] calling function from function?

[Sebastian Mendel]

Jason wrote:
Rick Fletcher wrote:
function db( $host, $user, $pass, $dbnam ) {
 $db = @mysql_pconnect( $host, $user, $pass )or die( mysql_error( $db 
));
   @mysql_select_db( $dbnam )or die( mysql_error( $db ) );
 return $db;
}

function logs() {
 global $defined;
 db( $defined[9], $defined[1], $defined[2], $defined[3] );
 ... do some processing ...
}
what am i missing here? i get errors if i try to pass $db to logs. 
i.e. logs( $db );

What's missing?  The error message.  Include it, and the offending 
line(s) of code, and ask again.

--Rick
There isnt an error at all.  According to the die() functions at the end 
of the mysql() functions it should give it there, instead I get blank as 
if the function has not successfully completed.  The reason I say this 
is if you try to access the mysql resource pointer ( $db, in this case ) 
I get nothing, a return code of 0.  Example in point...

function db( $host, $user, $pass, $dbnam ) {
 $db = @mysql_pconnect( $host, $user, $pass )or die( "phpDHCPAdmin currently not active, is under repair or 
is not configured correctly.Error Number: " .  mysql_errno( 
$db ) . "Error Message: " . mysql_error( $db ) . "Email 
Administrator: mailto:$defined[5]\";>$defined[5]" );
   @mysql_select_db( $dbnam )or die( "Could 
not connect to database: $defined[3]Error Message: " . 
@mysql_error( $db ) . "" . "Error Number: " . @mysql_errno( $db ) . 
"Email Administrator: mailto:$defined[5]\";>$defined[5]" );
 return $db;
}

function logs() {
 global $defined;
 db( $defined[9], $defined[1], $defined[2], $defined[3] );
 $pagecount = "1";
 $tble = "logs";
 $sql = @mysql_query( "SELECT * FROM $tble WHERE session = 
\"$_SESSION[hash]\"", $db )
$db is not defined,
$db is not required,
at least if you want to use $db you have to ctach the return from db() 
in $db:

$db = db( $defined[9], $defined[1], $defined[2], $defined[3] );
as i assume, logs() does nothing more than update one row with session 
data in the DB?

if you have a primary key on `session` you can just user REPLACE instead of
"if SELECT INSERT ELSE UPDATE"
logs()
{
db( $defined[9], $defined[1], $defined[2], $defined[3] );
$sql = 'REPLACE INTO logs VALUES ( ... )';
mysql_query( $sql ) or die( '...' );
}
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Sebastian Mendel
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Re: [PHP] Creating a directory

[Danny Brow]

On Fri, 2004-11-12 at 17:12 +, Jason Wong wrote:
> On Friday 12 November 2004 08:54, Danny Brow wrote:
> > What's the best way to create a directory with PHP, I tried using:
> >
> > if (array_exists('dir',$_POST)) {
> >  $dir_name = test123;
> 
> I'm 99% sure you mean 'test123'.

I meant $dir_name = $_POST['dir']; This works with out the single quote.
but all my variables have single or double quotes around them.

> 
> >  shell_exec('mkdir $dir_name');
> 
> I'm 100% sure you meant to use " instead of '.

this is how I normally do this when declaring variables, but that maybe
the difference here. 

> 
> > } else {
> > print "Get get some coffee!";
> 
> I'm 50% sure that should be print "RTFM".

RTFM > /dev/null :)


I'm 25-50% sure that this was a complete waste of a reply to a question.


> 
> -- 
> Jason Wong -> Gremlins Associates -> www.gremlins.biz
> Open Source Software Systems Integrators
> * Web Design & Hosting * Internet & Intranet Applications Development *
> --
> Search the list archives before you post
> http://marc.theaimsgroup.com/?l=php-general
> --
> /*
> I like your SNOOPY POSTER!!
> */
> 

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[PHP] Syslog Parser

[Nunners]

Does anyone know of a good syslog parser?

 

I've successfully got the syslog server to write to a mysql table, but I now
want to find something that will give me graphs, breakdowns etc for the
syslog.

 

Cheers

James

RE: [PHP] parsing /'s in urls

[Dennis Seavers]

The link offers a CGI error, which is admittedly an uninteresting result. 
I think you'll need to indicate what your previous results were and, if
different, what your desired results are.

Dennis


> [Original Message]
> From: <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Date: 11/11/2004 11:58:10 PM
> Subject: [PHP] parsing /'s in urls
>
> My host recently upgraded PHP.  I had a script, download.php, that would
> work like this
>
> http://www.myhost.com/download.php/30/file.torrent
>
> the download.php script would take the 30, look up the real filename in
the
> database, and readfile() it back.  this was a great setup because the
> browser just thought it was accessing a direct link to a file.
>
> But now download.php/30/file.torrent results in a 404.
>
> Is this something I can change back?
>
> Dan
>
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Re: [PHP] Creating a directory

[Danny Brow]

Thanks, I should have looked that up. 4am, time for bed.

Thanks again,
Dan.

On Fri, 2004-11-12 at 18:01 +0900, Pluance wrote:
> Use mkdir in PHP Functions.
> See Also: http://www.php.net/manual/en/function.mkdir.php
> 
> On Fri, 12 Nov 2004 03:54:52 -0500, Danny Brow <[EMAIL PROTECTED]> wrote:
> > What's the best way to create a directory with PHP, I tried using:
> > 
> > if (array_exists('dir',$_POST)) {
> >$dir_name = test123;
> >shell_exec('mkdir $dir_name');
> > 
> > I don't want to have to declare a variable, I would like to do this all
> > on one line. Like:
> >shell_exec('mkdir $_POST['dir']'); // but it don't work
> > } else {
> >print "Get get some coffee!";
> > }
> > 
> > I'll be putting some error checking in later :)
> > 
> > Thanks,
> > Dan.
> > 
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> > To unsubscribe, visit: http://www.php.net/unsub.php
> > 
> >
> 

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Re: [PHP] Creating a directory

[Jason Wong]

On Friday 12 November 2004 08:54, Danny Brow wrote:
> What's the best way to create a directory with PHP, I tried using:
>
> if (array_exists('dir',$_POST)) {
>  $dir_name = test123;

I'm 99% sure you mean 'test123'.

>  shell_exec('mkdir $dir_name');

I'm 100% sure you meant to use " instead of '.

> } else {
> print "Get get some coffee!";

I'm 50% sure that should be print "RTFM".

-- 
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
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Re: [PHP] Creating a directory

[Pluance]

Use mkdir in PHP Functions.
See Also: http://www.php.net/manual/en/function.mkdir.php

On Fri, 12 Nov 2004 03:54:52 -0500, Danny Brow <[EMAIL PROTECTED]> wrote:
> What's the best way to create a directory with PHP, I tried using:
> 
> if (array_exists('dir',$_POST)) {
>$dir_name = test123;
>shell_exec('mkdir $dir_name');
> 
> I don't want to have to declare a variable, I would like to do this all
> on one line. Like:
>shell_exec('mkdir $_POST['dir']'); // but it don't work
> } else {
>print "Get get some coffee!";
> }
> 
> I'll be putting some error checking in later :)
> 
> Thanks,
> Dan.
> 
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> 
>

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Re: [PHP] Simple XML

[John Holmes]

Octavian Rasnita wrote:
Does anyone know if PHP has a library for getting the content of an XML file
like XML::Simple in perl?
In that perl library I can get the whole content of an XML file in a
reference to an array of arrays of arrays... with only 3 lines of code.
Is there such a simple method in PHP?
Uhmm... SimpleXML?
http://us2.php.net/simplexml
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Re: [PHP] Current URL?

[John Holmes]

Jason Paschal wrote:
Trying to get the current viewed page's URL (query string intact).
this works, but infrequently:
$url = $_SERVER['URI']; 
How about $_SERVER['REQUEST_URI']
and this ignores the query string:
$url = $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'];
or you could add/check for $_SERVER['QUERY_STRING'] here.
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[PHP] Creating a directory

[Danny Brow]

What's the best way to create a directory with PHP, I tried using:

if (array_exists('dir',$_POST)) {
$dir_name = test123;  
shell_exec('mkdir $dir_name'); 

I don't want to have to declare a variable, I would like to do this all
on one line. Like:
shell_exec('mkdir $_POST['dir']'); // but it don't work
} else {
print "Get get some coffee!";
}

I'll be putting some error checking in later :)

Thanks,
Dan.

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[PHP] Current URL?

[Jason Paschal]

Trying to get the current viewed page's URL (query string intact).

this works, but infrequently:

$url = $_SERVER['URI']; 

and this ignores the query string:

$url = $_SERVER['HTTP_HOST'] . $_SERVER['PHP_SELF'];

I'm certain there's a way,  that is browser-independent,  to get your
script to grab the current URL (even if the script is an include).

i'm just trying to get a log of users currently online, and which page
they are viewing, and while the $_SERVER['REMOTE_ADDR'] will
invariably grab the IP, $_SERVER['URI'] is often empty.

i welcome any and all suggestions.

thank you,
~jmp

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Re: [PHP] Session file not written, session variables messed up.

[Klaus Reimer]

Rodolfo wrote:
The weirdness comes when in one frame the script will print "Agent Smith"
while in the other frame of the same frameset the script which loads on it
will print "Thomas Anderson"... 
Are both frames loaded at the same time? It's not possible to have two 
concurrently running scripts access the same session at the same time 
(At least when using files as backend). But normally that only means 
that one script execution is delayed until the other script completes or 
closes the session manually. But I never used session.auto_start, I 
always use session_start() in the PHP code. Maybe the auto_start session 
 behaves differently. Maybe you can try disabling auto_start and start 
the session manually. I don't think it make a difference, but who knows. 
 ;-)

On the other hand: Have you checked that your disk has enough room for 
more sessions? Maybe you are working on the bleeding edge of your 
harddisk capacity.

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