Re: [PHP] setting function variables
Ooops. Can't believe I overlooked that. Thanks everyone for your input.
Its up and running now.
- Original Message -
From: Mark [EMAIL PROTECTED]
To: Micah Montoy [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Thursday, August 07, 2003 2:36 PM
Subject: Re: [PHP] setting function variables
--- Micah Montoy [EMAIL PROTECTED] wrote:
Tried this and it returns errors of type:
Warning: Wrong parameter count for mssql_result() in
c:\inetpub\wwwroot\webpage10\example\utilities\dsp_del_images.php
on line 78
Warning: mssql_result(): supplied argument is not a valid MS
SQL-result
resource in
c:\inetpub\wwwroot\webpage10\example\utilities\dsp_del_images.php
on line 79
Warning: Wrong parameter count for mssql_result() in
c:\inetpub\wwwroot\webpage10\example\utilities\dsp_del_images.php
on line 78
Warning: mssql_result(): supplied argument is not a valid MS
SQL-result
resource in
c:\inetpub\wwwroot\webpage10\example\utilities\dsp_del_images.php
on line 79
Lines 78 and 79 read like this:
$img_numbers = $qryResults(SELECT COUNT(img_id) AS TotalImages
This should be $runQuery(), not $qryResults()
FROM images
WHERE category_id = '$row[0]');
$img_count = $qryResults($img_numbers,0,TotalImages)
The variables are specified as
$runQuery = 'mssql_query';
$qryResults = 'mssql_result';
Any ideas of why it would be doing this? Everything works fine
when I don't
try to use the variables.
thanks
Cpt John W. Holmes [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
From: Mark [EMAIL PROTECTED]
--- Micah Montoy [EMAIL PROTECTED] wrote:
I am trying to specify a single php file to contain all the
variables and I
just call this file where necessary. What I am running into
is
that I want
to do this for all the built in functions (i.e. mssql_query)
as
well. I've
tried numerous attempts but can't get it to operate without
wanting
to run
the functions or return an error. Something like this:
$runQuery = @mssql_query;
$qryResults = @mssql_result;
$getRow = @mssql_fetch_row;
$getRowNums = @mssql_num_rows;
Use a database abstraction class (ADODB, Pear, or something
from
phpclasses.org). You're trying to assign a variable to a
function's
actions, when you can only assign the variable to teh ooutput
of the
function.
A good suggestion, since this is what your creating, basically.
Anyhow, if you really want to do it your way, it'd be like this:
$runQuery = 'mssql_query';
$getRow = 'mssql_fetch_row';
Then you'd use them like this:
$result = $runQuery(select ... );
while($row = $getRow($result))
{
...
}
---John Holmes...
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Mark Weinstock
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Re: [PHP] preg_replace - understanding
You where right. That's what it was doing but now its not reversing the direction. It at least is a single \. Have an idea for reversing it. I played with it a bit but still no go on this. thanks - Original Message - From: Jennifer Goodie [EMAIL PROTECTED] To: Micah Montoy [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Tuesday, July 08, 2003 5:43 PM Subject: RE: [PHP] preg_replace - understanding $filevalue = str_replace(\\, /, $filevalue); it is reversing the \\ to // but not replacing them with just a single /. I think you need to escape your \ so each \ is \\ so your string should be -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] preg_replace - understanding
Never mind. Its working. thanks - Original Message - From: Jennifer Goodie [EMAIL PROTECTED] To: Micah Montoy [EMAIL PROTECTED]; [EMAIL PROTECTED] Sent: Tuesday, July 08, 2003 5:43 PM Subject: RE: [PHP] preg_replace - understanding $filevalue = str_replace(\\, /, $filevalue); it is reversing the \\ to // but not replacing them with just a single /. I think you need to escape your \ so each \ is \\ so your string should be -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] looping through values from a field? Need hellp.
I think that will do it. thanks, - Original Message - From: Lars Torben Wilson [EMAIL PROTECTED] To: Micah Montoy [EMAIL PROTECTED] Cc: [EMAIL PROTECTED] Sent: Saturday, July 05, 2003 4:59 PM Subject: Re: [PHP] looping through values from a field? Need hellp. On Sat, 2003-07-05 at 15:55, Micah Montoy wrote: I have this javascript that enables browsing and selecting of a file. This file location and name are then transferred further down in the form as an option. Multiple files may be chosen as they are just added one below the other. Anyway, when the form is submitted it is only retrieving the last file name from the form. How can I get PHP to return all the values from the select part. Basically this is what is happening: 1. Choose a file input type=file name=viewing onchange=loadImg(); 2. File location and name are displayed in the select name=imgList style=width:350; size=6 multiple/select as option value=c:\images\filename.gifc:\images\filename.gif/option The javascript creates the option and a new option is added and appended when a new file is chosen. 3. Submit form to php script to send location and stuff to database. Anyone have any ideas of how I can get PHP to loop through and pull out each option value? They are separated by a comma. Right now, it only grabs the last file even though all files are highlighted before submission. thanks http://ca2.php.net/manual/en/faq.html.php#faq.html.select-multiple Hope this helps, Torben -- Torben Wilson [EMAIL PROTECTED]+1.604.709.0506 http://www.thebuttlesschaps.com http://www.inflatableeye.com http://www.hybrid17.com http://www.themainonmain.com - Boycott Starbucks! http://www.haidabuckscafe.com - -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] looping through values from a field? Need hellp.
Ok. I gave it a shot but have run into one other question that I wasn't
able to find that was addressed by the article.
My select statement looks like this:
select name=imgList[] style=width:350; size=6 multiple/select
When I create the php file, I am trying something like below but it isn't
working and I am receiving an error. What am I not doing?
$filename = $_POST[imgList];
for each ($filename as $value) {
echo $value;
}
thanks
- Original Message -
From: Lars Torben Wilson [EMAIL PROTECTED]
To: Micah Montoy [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Saturday, July 05, 2003 4:59 PM
Subject: Re: [PHP] looping through values from a field? Need hellp.
On Sat, 2003-07-05 at 15:55, Micah Montoy wrote:
I have this javascript that enables browsing and selecting of a file.
This
file location and name are then transferred further down in the form as
an
option. Multiple files may be chosen as they are just added one below
the
other. Anyway, when the form is submitted it is only retrieving the
last
file name from the form. How can I get PHP to return all the values
from
the select part. Basically this is what is happening:
1. Choose a file input type=file name=viewing
onchange=loadImg();
2. File location and name are displayed in the
select name=imgList style=width:350; size=6 multiple/select as
option value=c:\images\filename.gifc:\images\filename.gif/option
The javascript creates the option and a new option is added and appended
when a new file is chosen.
3. Submit form to php script to send location and stuff to database.
Anyone have any ideas of how I can get PHP to loop through and pull out
each
option value? They are separated by a comma. Right now, it only grabs
the
last file even though all files are highlighted before submission.
thanks
http://ca2.php.net/manual/en/faq.html.php#faq.html.select-multiple
Hope this helps,
Torben
--
Torben Wilson [EMAIL PROTECTED]+1.604.709.0506
http://www.thebuttlesschaps.com http://www.inflatableeye.com
http://www.hybrid17.com http://www.themainonmain.com
- Boycott Starbucks! http://www.haidabuckscafe.com -
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Re: [PHP] looping through values from a field? Need hellp.
That was the trick. Just the space was messing things up. Thanks.
- Original Message -
From: Lars Torben Wilson [EMAIL PROTECTED]
To: Micah Montoya [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Saturday, July 05, 2003 6:18 PM
Subject: Re: [PHP] looping through values from a field? Need hellp.
On Sat, 2003-07-05 at 17:13, Micah Montoya wrote:
Ok. I gave it a shot but have run into one other question that I wasn't
able to find that was addressed by the article.
My select statement looks like this:
select name=imgList[] style=width:350; size=6 multiple/select
When I create the php file, I am trying something like below but it
isn't
working and I am receiving an error. What am I not doing?
$filename = $_POST[imgList];
for each ($filename as $value) {
echo $value;
}
thanks
Impossible to say without know what the error says. :) Anyway, if that
code is cut-and-pasted, then 'foreach' should have no space in it. That
would cause a parse error. Otherwise, you could be getting a Notice
if you're actually passing something in via method=GET but checking
the $_POST array instead.
--
Torben Wilson [EMAIL PROTECTED]+1.604.709.0506
http://www.thebuttlesschaps.com http://www.inflatableeye.com
http://www.hybrid17.com http://www.themainonmain.com
- Boycott Starbucks! http://www.haidabuckscafe.com -
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