Re: [PHP] Creating ZIP-File with password
Hmmm... its not possible to use this function, because i can't use the command line. now, i will try to crypt my data bevor i insert them into the zip file. but this needs more performance. i will wait for other comments. I will report my solution. regards "Per Jessen" <[EMAIL PROTECTED]> schrieb im Newsbeitrag news:[EMAIL PROTECTED] Sebastian Hopfe wrote: Now, the ZIP-files must be protect. There a important files included. Each site and forum seems to have no solution about this problem. Now, I need a solution or a workarround. Are the some people, who have some ideas? You could just use the zip command line utility and the '-P' option. However, the zip password mechanism does not really provide much in terms of protection - if you really need the encryption, I would look elsewhere. (PGP, X509). /Per Jessen, Zürich -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Creating ZIP-File with password
Dear PHP-Friends,
normaly its my job to find solutions about problems around PHP. Now, i have
a problem, that seems to be unsolved in PHP.
Actually i create some zip-files and this works fine.
$zip = new ZipArchive();
$zip->open("./foo.zip", ZIPARCHIVE::CREATE);
$dir = scandir ("doc/");
foreach($dir as $filename)
{
if($filename != "." || $filename != "..")
{
$zip->addFile("doc/".$filename, "doc/".$filename);
}
}
$zip->close();
Now, the ZIP-files must be protect. There a important files included. Each
site and forum seems to have no solution about this problem. Now, I need a
solution or a workarround. Are the some people, who have some ideas?
Regards
Sebastian
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[PHP] Re: enhanced_list_box, 2 tables from a database
Dear kNish,
first of all i have formated your PHP Code it looks better now.
\n";
echo " \n";
echo " Artist\n";
$options = mysql_query("SELECT artist_name FROM artist");
$options=mysql_fetch_array($options);
echo '';
enhanced_list_box(array(
'table' => 'artist',
'value_field' => 'artist_name'));
function enhanced_list_box($options)
{
$sql = "select " . $options['value_field'];
$sql .= " from " . $options['table'];
$result = mysql_query($sql)or die("error in SQL");
echo '';
while ($row = mysql_fetch_array($result, MYSQL_NUM))
echo '' . $row[0] . '';
echo '';
}
echo ' ';
echo "\n";
echo "\n";
echo " \n";
echo " Project\n";
$options = mysql_query("SELECT project_name FROM project");
$options=mysql_fetch_array($options);
echo '';
enhanced_list_box(array(
'table' => 'project',
'value_field' => 'project_name'));
function enhanced_list_box($options)
{
$sql = "select " . $options['value_field'];
$sql .= " from " . $options['table'];
$result = mysql_query($sql)or die("error in SQL");
echo '';
while ($row = mysql_fetch_array($result, MYSQL_NUM))
echo '' . $row[0] . '';
echo '';
}
echo '';
?>
After i had check your code, my php interpreter shows me an fatal error on
the browser.
"kNish" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
news:[EMAIL PROTECTED]
Hi,
A newbie question. I have more than one table to access from a database.
When I use the code as below, it gives no response on the web page.
What may I do to run more than one table from the same database into the
script.
BRgds,
kNish
.
.
.
.
Artist
';
enhanced_list_box(array(
'table' => 'artist',
'value_field' => 'artist_name'));
function enhanced_list_box($options){
$sql = "select " . $options['value_field'];
$sql .= " from " . $options['table'];
$result = mysql_query($sql)or die("error in SQL");
echo '';
while ($row = mysql_fetch_array($result, MYSQL_NUM))
echo '' . $row[0] . '';
echo '';
}
echo '';
?>
Project
';
enhanced_list_box(array(
'table' => 'project',
'value_field' => 'project_name'));
function enhanced_list_box($options){
$sql = "select " . $options['value_field'];
$sql .= " from " . $options['table'];
$result = mysql_query($sql)or die("error in SQL");
echo '';
while ($row = mysql_fetch_array($result, MYSQL_NUM))
echo '' . $row[0] . '';
echo '';
}
echo '';
?>
.
.
.
.
.
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[PHP] Re: Sessionvariable
Dear Ronald, I would like to ask you, want kind of session you use in you application. regards Sebastian "Ronald Wiplinger" <[EMAIL PROTECTED]> schrieb im Newsbeitrag news:[EMAIL PROTECTED] I use at the first page a session variable to set a flag. After a few pages, or if somebody wait too long, the pages have another flag. I noticed that there are often more than one session file exist. How can I avoid that? How can I make sure that for one user is only one session file? bye Ronald -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: back-up mysql database using PHP
Dear Vanessa You can use the "SELECT ... INTO OUTFILE 'file_name' " with mysql_query($vAnf, $dbconn); For the syntax you can have a look at http://dev.mysql.com/doc/refman/5.0/en/select.html Should you be allowed to send system-queries to the Server, than you should have a look to http://dev.mysql.com/doc/refman/5.0/en/backup.html There are many ways to backup the Database. I thought this will help you. Regards Sebastian ""Vanessa Vega"" <[EMAIL PROTECTED]> schrieb im Newsbeitrag news:[EMAIL PROTECTED] hello thereis there a way to create a back-up database through PHP?...i would like to create a file maybe an sql file that would served as back up of my database. Im using mysql database. I know i could use phpmyadmin to do this but i just like to have a function that would do this without going to phpmyadmin.any help? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Function variables in classes
I think you should log it, because it seems to be, and you found this error. Regard Sebastian "Paul van Haren" <[EMAIL PROTECTED]> schrieb im Newsbeitrag news:[EMAIL PROTECTED] Thanks, this helps. The code now works. In case this is truely a bug in PHP, where should I log it? Anything that I should do to make sure that it gets followed up? Regards, Paul -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Function variables in classes
It seems to be a PHP Bug, because normaly it should very well. but you can solve this problem, by a workarround. using "eval($a."();");" instead of "$a();" in the class. Best regards Sebastian "Paul van Haren" <[EMAIL PROTECTED]> schrieb im Newsbeitrag news:[EMAIL PROTECTED] Hi there, I'm trying to execute function variables. This works fine outside class code, but gives a fatal error when run within a class. The demo code is here: foo2(); ?> The error message reads: Fatal error: Call to undefined function foobar::bar2() in /home/paul/demo/demo.php on line 25 Is there anyone out there who can explain what's wrong in this code? Thanks, Paul -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re: Help with OOPHP
Dear Andrew,
I think normaly it isn't possible to use another class in a class, without
using extends. But you should use your array as a container. After you use
as a container, you can make new instance into a array field.
Now you can use the content of the container to administrate the instances
of the complete class. I just changed some things at your example. Please
have a look and ask if you have any questions.
fruits[] = new fruit($newFruit);
}
public function makeAllApples()
{
foreach($this->fruits AS $fruit)
{
$fruit->changeName("apple");
}
}
public function showAllFruits()
{
foreach($this->fruits AS $fruit)
{
echo $fruit->showFruit()."";
}
}
}
class fruit
{
private $name;
public function __construct($name)
{
$this->name = $name;
}
public function changeName($newName)
{
$this->name = $newName;
}
public function showFruit()
{
return $this->name;
}
}
$Cls = new fruitBasket();
$Cls->addFruit("test1");
$Cls->addFruit("test2");
$Cls->addFruit("test3");
$Cls->addFruit("test4");
$Cls->addFruit("test5");
$Cls->addFruit("test6");
$Cls->makeAllApples();
$Cls->showAllFruits();
?>
"Andrew Peterson" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
news:[EMAIL PROTECTED]
I'm hoping you guys can help me out.
I'm not sure if you can do this, but i'm trying to create a class that is
build of another class. I also want to be able to do functions on the
class1 from within class2.
example:
class fruitBasket{
private $fuit = array(); //this is a class
public function addFruit($newFruit)
{
$this->fruitBasket[] = $newFruit();
}
public makeAllApples()
{
foreach($this->fruit AS $value)
{ $value->changeName("apple");
} }
}
class fruit{
private $name;
public __construct($name)
{
$this->name = $name;
}
public changeName($newName)
{
$this->name = $newName;
}
}
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