Didier,
My guess is in your HTML, you have the input(s) named as 'file'..
Because of the way that PHP handles it's POST/GET variables, you will
want to redeclare your input names in your HTML to 'file[]'... This
basically defines that it is an array..
Hope that helps,
Jordan
Didier McGillis wrote:
I have three file fields in a form. I need it to upload those three
items or two or one. I can get it to upload one, but not all three,
habing trouble with the for loop and how I get a value of $i.
if(isset($_POST['upload'])){
if (!empty($_FILES['file']['name'])){
$formats = array('mp3','exe');
if(in_array(strtolower(substr($_FILES['file']['name'],-3)),$formats)) {
echo "Sorry! MP3's and .EXE's are disallowed!";
}else{
//mkdir("upload/" . $_POST['dir'],0777);
copy($_FILES['file']['tmp_name'], "images/" .
$_FILES['file']['name']);
unlink($_FILES['file']['tmp_name']);
echo "".$i." File(s) Uploaded Successfully to " .
$_POST['dir'] . " directory!";
}
}else{
echo "You must specify a file to upload\n";
echo "< <
back\n";
exit();
}
}
$i =$_FILES['file']['name'];
is it for ($i=1;$i<4;i++) {
run code
}
or am I way off, help please.
thanks,
_
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