Re: [PHP] 'undef' as an argument value
function foo ($arg1_required, $arg2_options = "") { if (empty($arg2_optional) { print "not passed"; } else { print "explicit"; } } Or you can go the other route. Jordan "Rodent Of Unusual Size" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > Rick Emery wrote: > > > > function foo($arg1_required, $arg2_optional="") > > if ($arg2_optional=="") { > > print "not passed"; > > } > > else { > > print "explicit"; > > } > > } > > No, I said 'undef' because I mean 'undefined'. The argument > can have *any* value; I need to know when it has *none*. That > is, there is no magic cookie to which I can set the default that > might not be a valid call value. > -- > #ken P-)} > > Ken Coar, Sanagendamgagwedweinini http://Golux.Com/coar/ > Author, developer, opinionist http://Apache-Server.Com/ > > "Millennium hand and shrimp!" -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] 'undef' as an argument value
"Johnson, Kirk" wrote: > > http://www.php.net/manual/en/function.func-num-args.php will > return the number of arguments passed to the function. Bingo! That will do the trick.. Thanks *very* much! -- #kenP-)} Ken Coar, Sanagendamgagwedweinini http://Golux.Com/coar/ Author, developer, opinionist http://Apache-Server.Com/ "Millennium hand and shrimp!" -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] 'undef' as an argument value
http://www.php.net/manual/en/function.func-num-args.php will return the number of arguments passed to the function. Kirk > -Original Message- > From: Rodent of Unusual Size [mailto:[EMAIL PROTECTED]] > Sent: Monday, March 11, 2002 2:25 PM > To: [EMAIL PROTECTED] > Subject: Re: [PHP] 'undef' as an argument value > > > Rick Emery wrote: > > > > function foo($arg1_required, $arg2_optional="") > > if ($arg2_optional=="") { > > print "not passed"; > > } > > else { > > print "explicit"; > > } > > } > > No, I said 'undef' because I mean 'undefined'. The argument > can have *any* value; I need to know when it has *none*. That > is, there is no magic cookie to which I can set the default that > might not be a valid call value. > -- > #ken P-)} > > Ken Coar, Sanagendamgagwedweinini http://Golux.Com/coar/ > Author, developer, opinionist http://Apache-Server.Com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] 'undef' as an argument value
Rick Emery wrote: > > function foo($arg1_required, $arg2_optional="") > if ($arg2_optional=="") { > print "not passed"; > } > else { > print "explicit"; > } > } No, I said 'undef' because I mean 'undefined'. The argument can have *any* value; I need to know when it has *none*. That is, there is no magic cookie to which I can set the default that might not be a valid call value. -- #kenP-)} Ken Coar, Sanagendamgagwedweinini http://Golux.Com/coar/ Author, developer, opinionist http://Apache-Server.Com/ "Millennium hand and shrimp!" -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] 'undef' as an argument value
function foo($arg1_required, $arg2_optional="") if ($arg2_optional=="") { print "not passed"; } else { print "explicit"; } } -Original Message- From: Rodent of Unusual Size [mailto:[EMAIL PROTECTED]] Sent: Monday, March 11, 2002 3:17 PM To: [EMAIL PROTECTED] Subject: [PHP] 'undef' as an argument value An odd request.. I want to have optional function arguments that *aren't* defined unless values are explicitly passed. Sorta the equivalent of function foo($arg1_required, $arg2_optional=undef) if (isset($arg2_optional)) { print "explicit"; } else { print "not passed"; } } Something like this is possible in Perl through the 'undef' construct; is anything like this available in PHP? -- #kenP-)} Ken Coar, Sanagendamgagwedweinini http://Golux.Com/coar/ Author, developer, opinionist http://Apache-Server.Com/ "Millennium hand and shrimp!" -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] 'undef' as an argument value
An odd request.. I want to have optional function arguments that *aren't* defined unless values are explicitly passed. Sorta the equivalent of function foo($arg1_required, $arg2_optional=undef) if (isset($arg2_optional)) { print "explicit"; } else { print "not passed"; } } Something like this is possible in Perl through the 'undef' construct; is anything like this available in PHP? -- #kenP-)} Ken Coar, Sanagendamgagwedweinini http://Golux.Com/coar/ Author, developer, opinionist http://Apache-Server.Com/ "Millennium hand and shrimp!" -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php