[PHP] A variable inside a variable?

[Alex Major]

Thanks for your help with my other question, heres a new one for you.

I need to nest a variable, inside another variable. For example:

$($buildingname)level

How (if at all) is this possible?

Thanks.
Alex.

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Re: [PHP] A variable inside a variable?

[Brad Bonkoski]

This might help...
http://www.php.net/manual/en/function.array.php

-B

Alex Major wrote:


Thanks for your help with my other question, heres a new one for you.

I need to nest a variable, inside another variable. For example:

$($buildingname)level

How (if at all) is this possible?

Thanks.
Alex.

 



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RE: [PHP] A variable inside a variable?

[Jim Moseby]

 
 Thanks for your help with my other question, heres a new one for you.
 
 I need to nest a variable, inside another variable. For example:
 
 $($buildingname)level
 
 How (if at all) is this possible?


http://us3.php.net/manual/en/language.variables.variable.php

JM

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Re: [PHP] A variable inside a variable?

[tg-php]

I've never found a use for it myself, but yes.. php provides for 'variable 
variables':

http://us3.php.net/manual/en/language.variables.variable.php

$a = 'varname';
$varname = 'test';

echo $$a;

 test

-TG

= = = Original message = = =

Thanks for your help with my other question, heres a new one for you.

I need to nest a variable, inside another variable. For example:

$($buildingname)level

How (if at all) is this possible?

Thanks.
Alex.


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Re: [PHP] A variable inside a variable?

[Jochem Maas]

Alex Major wrote:
 Thanks for your help with my other question, heres a new one for you.
 
 I need to nest a variable, inside another variable. For example:
 
 $($buildingname)level
 
 How (if at all) is this possible?

it's possible but probably an array is a better solution:

$someBuildinglevel = foo;
$buildingname = someBuilding;

echo ${$buildingname.level}; // outputs foo

now go lookup variable variables in the manual to for your penance ;-)

 
 Thanks.
 Alex.
 

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