[PHP] Array in a Loop Question

2002-03-26 Thread Jeff Hatcher

I have a form that gets repeated depending on number of members in a
group(1 form surrounds all members). I separate the entries by assigning
a count value to the names of the inputs (Ex. ). Does anyone know how I can pull the values
back out of the $_POST[]?

Example of ideal scenario that does not work:
case "process1":
for ($i=0;$i<$_POST[count];$i++)
{
$_POST[address$i]   
}

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Re: [PHP] Array in a Loop Question

2002-03-26 Thread Julio Nobrega Trabalhando

for ($i=0;$i<$_POST[count];$i++)
{
   echo $_POST['address' . $i] . '';
}

  Concanate array key 'address' with $i

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Julio Nobrega.

Um dia eu chego lá:
http://sourceforge.net/projects/toca

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"Jeff Hatcher" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
I have a form that gets repeated depending on number of members in a
group(1 form surrounds all members). I separate the entries by assigning
a count value to the names of the inputs (Ex. ). Does anyone know how I can pull the values
back out of the $_POST[]?

Example of ideal scenario that does not work:
case "process1":
for ($i=0;$i<$_POST[count];$i++)
{
$_POST[address$i]
}



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Re: [PHP] Array in a Loop Question

2002-03-26 Thread Erik Price


On Tuesday, March 26, 2002, at 01:18  PM, Jeff Hatcher wrote:

> I have a form that gets repeated depending on number of members in a
> group(1 form surrounds all members). I separate the entries by assigning
> a count value to the names of the inputs (Ex.  name=address$count value=>). Does anyone know how I can pull the values
> back out of the $_POST[]?
>
> Example of ideal scenario that does not work:
>   case "process1":
>   for ($i=0;$i<$_POST[count];$i++)
>   {
>   $_POST[address$i]   
>   }

The initial form:

for ($i = 1; $i <= $_POST['count']; $i++) {
   print "\n";
}
print "

What the above loop does is it makes a number of address inputs equal to 
$count... if $count is equal to 3, then you will get






I changed your $i from 0 to 1 because it makes it mentally easier to 
work with (for me at least).

Now in your next script, which is the target of the form, here is what 
you want to have:

for ($i = 1; $i <= $_POST['count']; $i++) {
   // do some code with $_POST["address{$i}"], such as
   // entering it into a database or echoing it to the user in HTML
}

Some further notes -- the hidden form field was so that you could give 
the second script the "count" variable, so it knows how many loops to do 
(this value is otherwise not available to the second script).  Also, the 
use of doublequotes in the second script ($_POST["address{$i}"]) is 
imperative because with singlequotes the variable $i will not expand to 
$_POST["address2"] or whatever.

HTH,

Erik







Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]


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Re: [PHP] Array in a Loop Question

2002-03-26 Thread Jim Lucas [php]

I think to get the results you are wanting, you might try this.


the address[]  tells the form that this element is an array and when
submitted, will be converted into an indexed array on the process page.

so you take this new array on the process page and do something like this.


foreach($address AS $k => $v)
{
echo "$k : $v";
}

Jim Lucas
www.bend.com

- Original Message -
From: "Jeff Hatcher" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, March 26, 2002 10:18 AM
Subject: [PHP] Array in a Loop Question


I have a form that gets repeated depending on number of members in a
group(1 form surrounds all members). I separate the entries by assigning
a count value to the names of the inputs (Ex. ). Does anyone know how I can pull the values
back out of the $_POST[]?

Example of ideal scenario that does not work:
case "process1":
for ($i=0;$i<$_POST[count];$i++)
{
$_POST[address$i]
}

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Re: [PHP] Array in a Loop Question

2002-03-26 Thread John Fishworld


Brilliant thanks !
I've got three of these in my form ! lol

> I think to get the results you are wanting, you might try this.
>
> 
> the address[]  tells the form that this element is an array and when
> submitted, will be converted into an indexed array on the process page.
>
> so you take this new array on the process page and do something like this.
>
>
> foreach($address AS $k => $v)
> {
> echo "$k : $v";
> }
>
> Jim Lucas
> www.bend.com
>
> - Original Message -
> From: "Jeff Hatcher" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Tuesday, March 26, 2002 10:18 AM
> Subject: [PHP] Array in a Loop Question
>
>
> I have a form that gets repeated depending on number of members in a
> group(1 form surrounds all members). I separate the entries by assigning
> a count value to the names of the inputs (Ex.  name=address$count value=>). Does anyone know how I can pull the values
> back out of the $_POST[]?
>
> Example of ideal scenario that does not work:
> case "process1":
> for ($i=0;$i<$_POST[count];$i++)
> {
> $_POST[address$i]
> }
>
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> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>



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RE: [PHP] Array in a Loop Question

2002-03-26 Thread Jeff Hatcher

for ($i=0;$i<$_POST[count];$i++)
{
   echo $_POST['address' . $i] . '';
}

  Concanate array key 'address' with $i


This works fine and I also can do the address[] but my ultimate result
is to put this in the database. 
So address='$_POST['address' . $i]' fails and
address='$_POST[address][$i]' fails.

I can reassign the values to new variables i.e. $address =
$_POST['address' . $i]; DB Update address='$address'
Or
$address  $_POST[address][$i];  DB Update address='$address'

So my question is how can I put this in the database without having to
reassign my variable name?


Current Solution:
case "process1":
for ($i=0;$i<$_POST[count];$i++)
{
$postal=$_POST[postal1][$i] . " " .
$_POST[postal2][$i];
$state=$_POST[state][$i];
$address=$_POST[address][$i];
$email=$_POST[email][$i];
$city=$_POST[city][$i];
$customerid=$_POST[customerid][$i];

mssql_query("UPDATE customer SET
postal='$postal',state='$state',address='$address',email=$_POST['email'
. $i],city='$city' WHERE id='$customerid'") or die("DATABASE ERROR:
updating customer, residentchange process 1");
}

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Re: [PHP] Array in a Loop Question

2002-03-26 Thread Erik Price


On Tuesday, March 26, 2002, at 02:12  PM, Jeff Hatcher wrote:

> So my question is how can I put this in the database without having to
> reassign my variable name?

You have to "jump out" of the quoted string that represents your SQL 
query when you echo the value of the $_POST variable.  Like this:

$sql = "SELECT a FROM b WHERE c='" . $_POST['d'] . "'";

Note that I 'jumped out' immediately after the singlequote mark (which 
you need if your value is going into a string field) by closing the 
double-quoted string, using the dot to append the value of the variable 
$_POST['d'], and then using a dot to append another double-quoted string 
(which contains nothing but a single quote in it).

Sometimes, depending on what your variable names look like, you can just 
escape your variable by using braces ('{' and '}'), but I think it's 
just easier to use the dot do appending from string to variable value to 
string again.




Erik






Erik Price
Web Developer Temp
Media Lab, H.H. Brown
[EMAIL PROTECTED]


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