Re: [PHP] Creating a javascript array from database data (Off-List)
Thanks for the clarification Sheridan - I think it must have been end of day
madness on my part :) I see what's going on now with the 'print' line.
Cheers,
Neil
Sheridan Saint-Michel wrote:
***
This message was virus checked with: SAVI 3.48
last updated 14th August 2001
***
Think in terms of output... The JavaScript is literally going to
try and run the output of the PHP (It doesn't even know PHP
exists). PHP is outputting the source code for the HTML and
JavaScript. So what you are trying to do is get PHP to take
dog,cat,cow from MySQL and output:
Script Language=JavaScript
text = new Array(dog,cat,cow)
/Script
This block of code does exactly that, with the print\$text\;
filling in dog cat and cow. I've added comments so you can
see how each line produces the above (I am using C-Style
comments as the // gets mucked up in e-mail)
The parts in [] are comments within comments to show flow
control and are not output.
else
{
/* Script Language=JavaScript */
echo Script Language=\JavaScript\\n;
/* text=new Array( */
echo text = new Array(;
while ($i $number)
$text = mysql_result($result, $i, name);
/* dog [first time] */
/* cat [second time] */
/* cow [third time] */
print \$text\;
$i++;
if ($i $number)
/* , [first time] */
/* , [second time] */
print ,;
else
/* ) [third time] */
print )\n;
}
/* /Script */
echo /Script\n;
}
So if you can follow that (just walk all the way through
the loop for each of the three passes) you can see that
no part of the code (including the print \$text\;) is
unnecessary
Hope this helps
Sheridan Saint-Michel
Website Administrator
FoxJet, an ITW Company
www.foxjet.com
- Original Message -
From: Neil Freeman [EMAIL PROTECTED]
To: Sheridan Saint-Michel [EMAIL PROTECTED]
Cc: php-general [EMAIL PROTECTED]
Sent: Wednesday, August 15, 2001 12:09 PM
Subject: Re: [PHP] Creating a javascript array from database data
Thanks a lot for your help Sheridan,
This now appears to work ok :) but if I remove the:
print \$text\;
line (as it is not required), I receive errors complaining about a syntax
error (related to what?) and that 'text' is undefined. As this line simply
outputs the value to screen why should this cause a problem if it is
removed?
Or could it be some other problem?
Neil
PS: Here is my updated code:
Snip
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Re: [PHP] Creating a javascript array from database data (Off-List)
Think in terms of output... The JavaScript is literally going to
try and run the output of the PHP (It doesn't even know PHP
exists). PHP is outputting the source code for the HTML and
JavaScript. So what you are trying to do is get PHP to take
dog,cat,cow from MySQL and output:
Script Language=JavaScript
text = new Array(dog,cat,cow)
/Script
This block of code does exactly that, with the print\$text\;
filling in dog cat and cow. I've added comments so you can
see how each line produces the above (I am using C-Style
comments as the // gets mucked up in e-mail)
The parts in [] are comments within comments to show flow
control and are not output.
else
{
/* Script Language=JavaScript */
echo Script Language=\JavaScript\\n;
/* text=new Array( */
echo text = new Array(;
while ($i $number)
$text = mysql_result($result, $i, name);
/* dog [first time] */
/* cat [second time] */
/* cow [third time] */
print \$text\;
$i++;
if ($i $number)
/* , [first time] */
/* , [second time] */
print ,;
else
/* ) [third time] */
print )\n;
}
/* /Script */
echo /Script\n;
}
So if you can follow that (just walk all the way through
the loop for each of the three passes) you can see that
no part of the code (including the print \$text\;) is
unnecessary
Hope this helps
Sheridan Saint-Michel
Website Administrator
FoxJet, an ITW Company
www.foxjet.com
- Original Message -
From: Neil Freeman [EMAIL PROTECTED]
To: Sheridan Saint-Michel [EMAIL PROTECTED]
Cc: php-general [EMAIL PROTECTED]
Sent: Wednesday, August 15, 2001 12:09 PM
Subject: Re: [PHP] Creating a javascript array from database data
Thanks a lot for your help Sheridan,
This now appears to work ok :) but if I remove the:
print \$text\;
line (as it is not required), I receive errors complaining about a syntax
error (related to what?) and that 'text' is undefined. As this line simply
outputs the value to screen why should this cause a problem if it is
removed?
Or could it be some other problem?
Neil
PS: Here is my updated code:
Snip
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For additional commands, e-mail: [EMAIL PROTECTED]
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