[PHP] Error with array and include

2006-12-05 Thread Fernando M. M. 

Hi,

I'm having a strange problem when trying to show a array after its value 
was defined on a file that was included. Something like this:


?php
   $lang = 'pt_BR';

   include('lang/'. $lang .'/login.php');

   echo $lang['Username'];
?

On the file lang/pt_BR/login.php i have this...

?php
   $lang['Username'] = 'Usuário';
?

But the result of the first script is 'S' (without quotes).

If i change lang/pt_BR/login.php to

?php
   $lang['Username'] = 'Usuário';

   echo $lang['Username'];
?

I get 'Usuário' (without quotes again).

Why does this happens?

Thanks,

Fernando.

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Re: [PHP] Error with array and include

2006-12-05 Thread T . Lensselink 
How can you use an array as string in the include statement and two lines lower 
as array?
Think it echo's 'S' because it see's $lang as a string and not an array.

On Tue, 05 Dec 2006 13:11:12 -0200, Fernando M. M. [EMAIL PROTECTED] wrote:
 Hi,
 
 I'm having a strange problem when trying to show a array after its value
 was defined on a file that was included. Something like this:
 
 ?php
 $lang = 'pt_BR';
 
 include('lang/'. $lang .'/login.php');
 
 echo $lang['Username'];
 ?
 
 On the file lang/pt_BR/login.php i have this...
 
 ?php
 $lang['Username'] = 'Usuário';
 ?
 
 But the result of the first script is 'S' (without quotes).
 
 If i change lang/pt_BR/login.php to
 
 ?php
 $lang['Username'] = 'Usuário';
 
 echo $lang['Username'];
 ?
 
 I get 'Usuário' (without quotes again).
 
 Why does this happens?
 
 Thanks,
 
 Fernando.
 
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Re: [PHP] Error with array and include

2006-12-05 Thread Fernando M. M. 

T.Lensselink,

Ok, problem solved. I didn't realized that i was using the same variable.

Thanks for the help!

T.Lensselink escreveu:

How can you use an array as string in the include statement and two lines lower 
as array?
Think it echo's 'S' because it see's $lang as a string and not an array.

On Tue, 05 Dec 2006 13:11:12 -0200, Fernando M. M. [EMAIL PROTECTED] wrote:
  

Hi,

I'm having a strange problem when trying to show a array after its value
was defined on a file that was included. Something like this:

?php
$lang = 'pt_BR';

include('lang/'. $lang .'/login.php');

echo $lang['Username'];
?

On the file lang/pt_BR/login.php i have this...

?php
$lang['Username'] = 'Usuário';
?

But the result of the first script is 'S' (without quotes).

If i change lang/pt_BR/login.php to

?php
$lang['Username'] = 'Usuário';

echo $lang['Username'];
?

I get 'Usuário' (without quotes again).

Why does this happens?

Thanks,

Fernando.

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Re: [PHP] Error with array and include

2006-12-05 Thread Richard Lynch 
On Tue, December 5, 2006 9:11 am, Fernando M. M. wrote:
 Hi,

 I'm having a strange problem when trying to show a array after its
 value
 was defined on a file that was included. Something like this:

 ?php
 $lang = 'pt_BR';

 include('lang/'. $lang .'/login.php');

 echo $lang['Username'];

You are using $lang for BOTH the language to include, and then again
as an array for content within that language.

Don't do that.

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