[PHP] HELP!!! Date time problems!!!!
Hi, My name is Bruno, From Brazil. Yes...it's me again...hehehe Look...my problem is.. I wanna make something like this: (10 november 2001) - (5 November 2001) = 5 days (10 november 2001) - (10 December 2001) = 30 days How can i do this Thanks for any help Your friend, Bruno From !
Re: [PHP] HELP!!! Date time problems!!!!
Hello,
this is a function I use on my site, you can problably find
your answer,
py
// =
// This function returns the difference between a dates
// and the current date.
// arg1: separator
// arg2: startdate date dd mm
// return number of days of differences
// ==
function diff_date( $sep, $startdate ){
// Date of file in database
$startdate = explode( "$sep", $startdate );
$startdate = mktime( 0, 0, 0, $startdate[1], $startdate[2],
$startdate[0] );
// Now
$enddate = mktime( 0, 0, 0, date("n"), date("d"), date("Y") );
// get difference in days by dividing by 24*24*60
return ( $enddate - $startdate ) / ( 86400 );
} // end function
- Original Message -
From: Bruno Freire [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, March 08, 2001 7:05 PM
Subject: [PHP] HELP!!! Date time problems
Hi, My name is Bruno, From Brazil.
Yes...it's me again...hehehe
Look...my problem is..
I wanna make something like this:
(10 november 2001) - (5 November 2001) = 5 days
(10 november 2001) - (10 December 2001) = 30 days
How can i do this
Thanks for any help
Your friend, Bruno From !
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To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
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Re: [PHP] HELP!!! Date time problems!!!!
figured out the logic,
but still cant make it run
i put this command :
echo diff_date("/", "05/03/2001") ;
to test the function. but it doest seem to work :(
any help ?
btw i believe it must be 24*60*60 inorder to 24*24*60 :)
""Pierre-Yves Lemaire"" [EMAIL PROTECTED] wrote in message
01c301c0a7e0$17f85f00$9ceee740@py">news:01c301c0a7e0$17f85f00$9ceee740@py...
Hello,
this is a function I use on my site, you can problably find
your answer,
py
// =
// This function returns the difference between a dates
// and the current date.
// arg1: separator
// arg2: startdate date dd mm
// return number of days of differences
// ==
function diff_date( $sep, $startdate ){
// Date of file in database
$startdate = explode( "$sep", $startdate );
$startdate = mktime( 0, 0, 0, $startdate[1], $startdate[2],
$startdate[0] );
// Now
$enddate = mktime( 0, 0, 0, date("n"), date("d"), date("Y") );
// get difference in days by dividing by 24*24*60
return ( $enddate - $startdate ) / ( 86400 );
} // end function
- Original Message -
From: Bruno Freire [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, March 08, 2001 7:05 PM
Subject: [PHP] HELP!!! Date time problems
Hi, My name is Bruno, From Brazil.
Yes...it's me again...hehehe
Look...my problem is..
I wanna make something like this:
(10 november 2001) - (5 November 2001) = 5 days
(10 november 2001) - (10 December 2001) = 30 days
How can i do this
Thanks for any help
Your friend, Bruno From !
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] HELP!!! Date time problems!!!!
ok here is the right one working : smt was wrong with the arrays i beleive :
?php
// =
// This function returns the difference between a dates
// and the current date.
// arg1: separator
// arg2: startdate date dd mm
// return number of days of differences
// ==
function diff_date( $sep, $startdate ){
// Date of file in database
$startdate = explode( "$sep", $startdate );
$startdate = mktime( 0, 0, 0, $startdate[1], $startdate[0],
$startdate[2] );
// Now
$enddate = mktime( 0, 0, 0, date("n"), date("d"), date("Y") );
// get difference in days by dividing by 24*60*60
return ( $enddate - $startdate ) / ( 86400 );
} // end function
echo diff_date("/", "05/3/2001") ;
?
this one works :)
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Re: [PHP] HELP!!! Date time problems!!!!
Yes, there was a little bug, it was set to handle date in /mm/dd and
not dd/mm/yyy.
Now this works ok.
py
function diff_date( $sep, $startdate ){
// Date of file in database
$startdate = explode( $sep, $startdate );
$startdate = mktime( 0, 0, 0, $startdate[1], $startdate[0],
$startdate[2] );
// Now
$enddate = mktime( 0, 0, 0, date("n"), date("d"), date("Y") );
// get difference in days by dividing by 24*24*60
return ( $enddate - $startdate ) / ( 86400 );
} // end function
echo diff_date("/", "05/03/2001" ) ;
- Original Message -
From: karakedi [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, March 08, 2001 11:01 PM
Subject: Re: [PHP] HELP!!! Date time problems
figured out the logic,
but still cant make it run
i put this command :
echo diff_date("/", "05/03/2001") ;
to test the function. but it doest seem to work :(
any help ?
btw i believe it must be 24*60*60 inorder to 24*24*60 :)
""Pierre-Yves Lemaire"" [EMAIL PROTECTED] wrote in message
01c301c0a7e0$17f85f00$9ceee740@py">news:01c301c0a7e0$17f85f00$9ceee740@py...
Hello,
this is a function I use on my site, you can problably find
your answer,
py
// =
// This function returns the difference between a dates
// and the current date.
// arg1: separator
// arg2: startdate date dd mm
// return number of days of differences
// ==
function diff_date( $sep, $startdate ){
// Date of file in database
$startdate = explode( "$sep", $startdate );
$startdate = mktime( 0, 0, 0, $startdate[1], $startdate[2],
$startdate[0] );
// Now
$enddate = mktime( 0, 0, 0, date("n"), date("d"), date("Y") );
// get difference in days by dividing by 24*24*60
return ( $enddate - $startdate ) / ( 86400 );
} // end function
- Original Message -----
From: Bruno Freire [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, March 08, 2001 7:05 PM
Subject: [PHP] HELP!!! Date time problems
Hi, My name is Bruno, From Brazil.
Yes...it's me again...hehehe
Look...my problem is..
I wanna make something like this:
(10 november 2001) - (5 November 2001) = 5 days
(10 november 2001) - (10 December 2001) = 30 days
How can i do this
Thanks for any help
Your friend, Bruno From !
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PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
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PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
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Re: [PHP] HELP!!! Date time problems!!!!
upss sorry couldnt see your latest post.
thx anywy :))
""karakedi"" [EMAIL PROTECTED] wrote in message
98942f$qcd$[EMAIL PROTECTED]">news:98942f$qcd$[EMAIL PROTECTED]...
ok here is the right one working : smt was wrong with the arrays i beleive
:
?php
// =
// This function returns the difference between a dates
// and the current date.
// arg1: separator
// arg2: startdate date dd mm
// return number of days of differences
// ==
function diff_date( $sep, $startdate ){
// Date of file in database
$startdate = explode( "$sep", $startdate );
$startdate = mktime( 0, 0, 0, $startdate[1], $startdate[0],
$startdate[2] );
// Now
$enddate = mktime( 0, 0, 0, date("n"), date("d"), date("Y") );
// get difference in days by dividing by 24*60*60
return ( $enddate - $startdate ) / ( 86400 );
} // end function
echo diff_date("/", "05/3/2001") ;
?
this one works :)
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