Your code makes no sense and the error message is telling you exactly what
you did wrong. opendir() returns a directory handle to be passed to
readdir(). Calling chdir() on a directory handle makes no sense. You
want to chdir to the same string that you passed to opendir()
-Rasmus
On Wed, 2 Oct 2002, Nokar wrote:
I get this error from php when i execute this code can you help me ;)
Warning: chdir() expects parameter 1 to be string, resource given in
C:\\read.php on line 146
145 echo centerAttachment :;
146 $rep = opendir(C:\\xxx\\Attach\\$id\\);
147 chdir($rep);
148 while ($zone = readdir($rep))
149 {
150 if (!is_dir($zone)) echo a
href=\../Attach/$id/$zone\$zone/abr;
151 }
152 echo /center;
153 }
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