[PHP] PHP/Perl/CGI Question

2001-03-20 Thread Clayton Dukes 



Howdy,

I have a search cgi form that has the following 
function:

sub 
header{ print "Content-type: 
text/html\n\n"; print "?php 
include(\"mainfile.php\")\;?\n"; 
print "?php 
include(\"header.php\")\;?\n"; 
print "titleSearch/title\n";}

When I use the function though, the web page 
(source) comes up as:
?php include("mainfile.php");??php 
include("header.php");?titleSearch/title...data?include("footer.php");?

What am I doing wrong? Why is it printing the php 
tags instead of executing them?

Clayton 
Dukes-Download 
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Re: [PHP] PHP/Perl/CGI Question

2001-03-20 Thread Clayton Dukes 

I was afraid you were going to say that...
Anyone care to show me how to write that?

Clayton Dukes
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- Original Message -
From: "Andrew Rush" [EMAIL PROTECTED]
To: "Clayton Dukes" [EMAIL PROTECTED]
Sent: Tuesday, March 20, 2001 2:33 PM
Subject: Re: [PHP] PHP/Perl/CGI Question


 on 3/20/01 02:21 PM, [EMAIL PROTECTED] splat open and thusly melted:

  What am I doing wrong? Why is it printing the php tags instead of
executing
  them?

 because the output of a CGI cannot then be run through the PHP parser. you
 could possibly write the PHP out to a new file (with the proper extension
 for the parser) and then send a location header() that sends the user to
 execute that page. i've never done this, so i can't vouch for it's
 workability, but there's nothing wrong with the idea in concept- at least
so
 far as i can see

 --
 :: Andrew Rush :: Lead Systems Developer :: MaineToday.com ::
 **
 "Crippled but free, blind all the time, i was learning to see"

 - J. Garcia / R. Hunter
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