[PHP] PHP bug within multi. dimensional arrays?
Hi there,
I am outputting an multidim. array. That works fine, except one thing. The first
letter of the value inside dimension 1 always gets printed.
For example:
I fill the arrays:
while ($row = mysql_fetch_object($result)){
$cat[$row-main_id][name]= $row-main_name;
$cat[$row-main_id][$row-sub_id][name] = $row-sub_name;
}
Then I output them:
foreach ($cat AS $maincat){
echo $maincat[name].':';
foreach($maincat AS $subcat){
echo $subcat[name].$br;
}
echo $br;
}
Which does result in:
Europe:E
Germany
UK
North America:N
US
CA
As you can see I get the extra letters N and E. Is this an php error or did I do
something wrong?
Thanx for any hint,
Merlin
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Re: [PHP] PHP bug within multi. dimensional arrays?
Hello Merlin,
Monday, June 6, 2005, 2:51:39 PM, you wrote:
M while ($row = mysql_fetch_object($result)){
M $cat[$row-main_id][name] = $row-main_name;
M $cat[$row-main_id][$row-sub_id][name] =
M $row-sub_name;
M }
Quote array keys.. ALWAYS quote them:
$cat[$blah]['name'] = $whatever
Otherwise PHP will think [name] is trying to use a constant and
substitute a value accordingly.
M foreach ($cat AS $maincat){
M echo $maincat[name].':';
M foreach($maincat AS $subcat){
M echo $subcat[name].$br;
M }
M echo $br;
M }
M As you can see I get the extra letters N and E. Is this an php
M error or did I do something wrong?
You did something wrong ;) If you don't quote the array keys it'll
assume a constant, which in turn would assume a 1 which will give you
the first character of the string.
Best regards,
Richard Davey
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Re: [PHP] PHP bug within multi. dimensional arrays?
Richard Davey wrote:
Hello Merlin,
Monday, June 6, 2005, 2:51:39 PM, you wrote:
M while ($row = mysql_fetch_object($result)){
M $cat[$row-main_id][name] = $row-main_name;
M $cat[$row-main_id][$row-sub_id][name] =
M $row-sub_name;
M }
Quote array keys.. ALWAYS quote them:
$cat[$blah]['name'] = $whatever
Otherwise PHP will think [name] is trying to use a constant and
substitute a value accordingly.
M foreach ($cat AS $maincat){
M echo $maincat[name].':';
M foreach($maincat AS $subcat){
M echo $subcat[name].$br;
M }
M echo $br;
M }
M As you can see I get the extra letters N and E. Is this an php
M error or did I do something wrong?
You did something wrong ;) If you don't quote the array keys it'll
assume a constant, which in turn would assume a 1 which will give you
the first character of the string.
Best regards,
Richard Davey
Hi Richard,
that sounds absolutly plausible and I now qoted it the way you recommended.
However I do get the same result. Still the first letter.
Any other ideas?
Thank you in advance,
Merlin
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Re: [PHP] PHP bug within multi. dimensional arrays?
On Mon, June 6, 2005 6:51 am, Merlin said:
I am outputting an multidim. array. That works fine, except one thing. The
first
letter of the value inside dimension 1 always gets printed.
For example:
I fill the arrays:
while ($row = mysql_fetch_object($result)){
$cat[$row-main_id][name] = $row-main_name;
For the record, name does not turn into 0, 1, nor TRUE here, but simply
becomes 'name' which is what you should have typed in the first place.
Set error_reporting(E_ALL) to get more details.
$cat[$row-main_id][$row-sub_id][name] = $row-sub_name;
}
Then I output them:
foreach ($cat AS $maincat){
echo $maincat[name].':';
echo maincat is: '$maincat'br /\n;
foreach($maincat AS $subcat){
echo subcat is: '$subcat'br /\n;
echo $subcat[name].$br;
}
echo $br;
}
Which does result in:
Europe:E
You are passing 'Europe' as $subcat, and then trying to treat it like an
array when you do $subcat['name'].
PHP will let you treat a string as an array of characters, if you insist.
At this point, PHP *does* turn 'name' into the index 0 because you can
only index strings as character arrays using integer indices.
$subcat['name'] = 'Europe'['name'] = 'Europe'[0] = 'E'
Germany
UK
North America:N
US
CA
As you can see I get the extra letters N and E. Is this an php error or
did I do
something wrong?
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