Re: [PHP] Re: Error: Can't redeclare already declared function (PHP 3.0.15)
On Fri, 26 Oct 2001 20:54:00 -0400 impersonator of [EMAIL PROTECTED]
(Gerard Onorato) planted I saw in php.general:
Hi,
Another solution I have used when I have to do conditional includes which
may cause the same page to be included twice
Unfortunately, you can't include FUNCTION() conditionaly (well, you can,
but then you can't use it out of this if():). Why only such dumn
restriction, PHP developers?
At the top of the code to be included (the separate file) put something
like:
if ($theFileAlreadyInclude != 1) {
Right. That what i do too, but you include _code_ (whithout functions:()
in that case..
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i
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Re: [PHP] Re: Error: Can't redeclare already declared function (PHP 3.0.15)
I include files in each other all the time, and some of them might call the
same functions (like database functions).
I just use a string in all function declaration with the name of the
functions or set of functions in the file.
if(!$function_test)
{
$function_test=1;
function test()
{
dfg
fdggfdg
fdg
}
}
This way you can include the same functions many times without error.
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Re: [PHP] Re: Error: Can't redeclare already declared function (PHP 3.0.15)
Unfortunately, you can't include FUNCTION() conditionaly (well, you can, but then you can't use it out of this if():). Why only such dumn restriction, PHP developers? I think it's only true for php3 I use many many class definitions in php4 that are inluded conditionally in another classes' functions, and of course it works fine. Arpi -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Re: Error: Can't redeclare already declared function (PHP 3.0.15)
On Sat, 27 Oct 2001 13:21:58 +0200 impersonator of [EMAIL PROTECTED] (Tamas Arpad) planted I saw in php.general: Unfortunately, you can't include FUNCTION() conditionaly (well, you can, but then you can't use it out of this if():). Why only such dumn restriction, PHP developers? I think it's only true for php3 I use many many class definitions in php4 that are inluded conditionally in another classes' functions, and of course it works fine. Arpi Hmm. Thats becoming interesting. Are you using 4.06 ? Becouse, i have this version, and it doesn't give me such a chance. I thought it should, but when tryed it proved otherwise.. Pss. I double-checked now on a simple example, and it worked as you say, it should.. But i re-member well that then i too checked several times.. Weird. (i must have missed s/t then or..) Anyway, 'll have in mind, that it should work, for the futer. Sorry 4 missleding TnX. i. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] Re: Error: Can't redeclare already declared function (PHP 3.0.15)
I had the same type of problem. ( i think)
I had one main page (say index.php) that had a bare bones html page. No
functions or anything.
Then i had separate pages that would be included only if i was using them
(like, say, a category.php for displaying categories, then products.php for
showing products.)
I had a function called printlist(); that would create a drop down menu
with categories/subcategories; this was in both category.php and
products.php. Niether of those files were included at the same time though,
and it'd give me the redeclare error... what i did was rename the function
in each file (like for category.php, rename it to printlist1(); and then in
products.php rename it to printlist2();... this is a quick fix). Let me
know if this was any help :)
--
Jason Wood
Chief Technology Officer
Expressive Tek, Inc.
407 Kehrs Mill Road
Ballwin, MO 63011
Phone 636.256.1362
www.expressivetek.com
Patrick Dunford [EMAIL PROTECTED] wrote in message
001501c15e27$1a738b80$bd84a7cb@patricks">news:001501c15e27$1a738b80$bd84a7cb@patricks...
I have a script (let's call it a.php3) that brings in another script
b.php3
with the include or require call.
In script b.php3 there is an include or require call to bring in script
c.php3.
Script a.php3 after making one and only one include (the include is not
repeated anywhere in a.php3) then calls a function x which is defined in
script b.php3.
The first time the function is called it executes without any problems.
The
second time in which it is called, in exactly the same way, with the same
parameters, it errors with the message
Can't redeclare already declared function in c.php3 at line the last line
of the first function declaration in c.php3
The function is not actually named in the error message. This is the code
block in c.php3 which the error occurs:
top of file
?php
function getDirNames($sourceDir,$includeBase)
{
global $pathList;
function findAllDirsInDir($sourceDir)
{
global $pathList;
$dirHandle=opendir($sourceDir);
while (($subDir=readdir($dirHandle))!=false)
{
if (is_dir($sourceDir./.$subDir))
{
if ($subDir != . $subDir != ..)
{
$dirList[] = $sourceDir./.$subDir;
$pathList[] = $sourceDir./.$subDir;
}
}
}
closedir($dirHandle);
return $dirList;
}; error occurs here
function buildDirList($sourceDir,$recurse)
{
$subDirList=findAllDirsInDir($sourceDir);
if (count($subDirList) != 0)
$recurse=true;
else
$recurse=false;
for($i=0; $icount($subDirList);$i++)
{
$currentSubDir=$subDirList[$i];
if ($recurse==true)
buildDirList($currentSubDir,$recurse);
}
}
buildDirList($sourceDir,true);
if ($includeBase == TRUE)
$pathList[] = $sourceDir;
return $pathList;
}
There are no multiple calls to include or require:
* a.php3 which is the script that calls the function several times to
output
data, contains only one call to include() that is not inside any kind of
loop. It is called once just before the first function call.
*b.php3 which is the script that is included by a.php3. It includes c.php3
ONCE ONLY, NOT IN A LOOP.
*c.php3 which is the script in which the error is occurring.
Debugging b.php3 shows that the error message is thrown when execution
reaches the line in which the function from c.php3 is called. Therefore I
surmise that the error message is ambiguous.
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RE: [PHP] Re: Error: Can't redeclare already declared function (PHP 3.0.15)
Hi,
Another solution I have used when I have to do conditional includes which
may cause the same page to be included twice
At the top of the code to be included (the separate file) put something
like:
if ($theFileAlreadyInclude != 1) {
and at the bottom you may put:
}
$theFileAlreadyIncluded =1;
depending on the way your coding you may need make the variable global.
Hope this helps.
Gerard
-Original Message-
From: Jason Wood [mailto:[EMAIL PROTECTED]]
Sent: Friday, October 26, 2001 3:43 PM
To: [EMAIL PROTECTED]
Subject: [PHP] Re: Error: Can't redeclare already declared function (PHP
3.0.15)
I had the same type of problem. ( i think)
I had one main page (say index.php) that had a bare bones html page. No
functions or anything.
Then i had separate pages that would be included only if i was using them
(like, say, a category.php for displaying categories, then products.php for
showing products.)
I had a function called printlist(); that would create a drop down menu
with categories/subcategories; this was in both category.php and
products.php. Niether of those files were included at the same time though,
and it'd give me the redeclare error... what i did was rename the function
in each file (like for category.php, rename it to printlist1(); and then in
products.php rename it to printlist2();... this is a quick fix). Let me
know if this was any help :)
--
Jason Wood
Chief Technology Officer
Expressive Tek, Inc.
407 Kehrs Mill Road
Ballwin, MO 63011
Phone 636.256.1362
www.expressivetek.com
Patrick Dunford [EMAIL PROTECTED] wrote in message
001501c15e27$1a738b80$bd84a7cb@patricks">news:001501c15e27$1a738b80$bd84a7cb@patricks...
I have a script (let's call it a.php3) that brings in another script
b.php3
with the include or require call.
In script b.php3 there is an include or require call to bring in script
c.php3.
Script a.php3 after making one and only one include (the include is not
repeated anywhere in a.php3) then calls a function x which is defined in
script b.php3.
The first time the function is called it executes without any problems.
The
second time in which it is called, in exactly the same way, with the same
parameters, it errors with the message
Can't redeclare already declared function in c.php3 at line the last line
of the first function declaration in c.php3
The function is not actually named in the error message. This is the code
block in c.php3 which the error occurs:
top of file
?php
function getDirNames($sourceDir,$includeBase)
{
global $pathList;
function findAllDirsInDir($sourceDir)
{
global $pathList;
$dirHandle=opendir($sourceDir);
while (($subDir=readdir($dirHandle))!=false)
{
if (is_dir($sourceDir./.$subDir))
{
if ($subDir != . $subDir != ..)
{
$dirList[] = $sourceDir./.$subDir;
$pathList[] = $sourceDir./.$subDir;
}
}
}
closedir($dirHandle);
return $dirList;
}; error occurs here
function buildDirList($sourceDir,$recurse)
{
$subDirList=findAllDirsInDir($sourceDir);
if (count($subDirList) != 0)
$recurse=true;
else
$recurse=false;
for($i=0; $icount($subDirList);$i++)
{
$currentSubDir=$subDirList[$i];
if ($recurse==true)
buildDirList($currentSubDir,$recurse);
}
}
buildDirList($sourceDir,true);
if ($includeBase == TRUE)
$pathList[] = $sourceDir;
return $pathList;
}
There are no multiple calls to include or require:
* a.php3 which is the script that calls the function several times to
output
data, contains only one call to include() that is not inside any kind of
loop. It is called once just before the first function call.
*b.php3 which is the script that is included by a.php3. It includes c.php3
ONCE ONLY, NOT IN A LOOP.
*c.php3 which is the script in which the error is occurring.
Debugging b.php3 shows that the error message is thrown when execution
reaches the line in which the function from c.php3 is called. Therefore I
surmise that the error message is ambiguous.
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