[PHP] Re: Newbie ' If Statement' Question

2008-03-19 Thread Dan
heredoc is probably the best way to go.  There's no way you can mess up your 
quotes, and you don't have to worry about escaping.  Altough I wonder what 
would happen if you put ? in a heredoc, would it stop processing the php, 
thinking that it was the end of the php file, or would it just treat it as a 
string still?


- Dan

Al [EMAIL PROTECTED] wrote in message 
news:[EMAIL PROTECTED]

Here's how I'd do it.

?php
$row= $emp_row-getRecordId();//Or, you can put this inside the heredoc 
with {}


//heredoc
$str= txt
form name=edit method=post action=emp_edit_result2.php
input type=hidden name=Status value=Active /
input type=hidden name=The_Date value= /
input type=hidden name=-recid value=$row /
input type=submit name=edit_submit value=Activate /
/form
txt;

if (!empty($emp_row-getField('testfield')) print $str;
else print Non Print;
?


[EMAIL PROTECTED] wrote:

Hello Folks,

I would like to be able to wrap a 'form' inside a php 'if statement' - 
so

that the form will appear if the 'if condition' is met.

-  most likely I cannot have a ?php tag inside another one - and am sure
I'm doing other things wrong also...
- now I get the error - Parse error: syntax error, unexpected T_STRING 
in...


Q:  What is the best way to accomplish this goal?


---

?php if ($emp_row-getField('testfield') !=) {
print form name=edit method=post action=emp_edit_result2.php
input type=hidden name=Status value=Active/
input type=hidden name=The_Date value=/
input type=hidden name=-recid value=?php echo
$emp_row-getRecordId(); ?
input type=submit name=edit_submit value=Activate
/form
;}else {print Non Print;} ?
--
Thanks - RevDave
Cool7 @ hosting4days . com
[db-lists]




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[PHP] Re: Newbie ' If Statement' Question

2008-03-16 Thread Al

Here's how I'd do it.

?php
$row= $emp_row-getRecordId();//Or, you can put this inside the heredoc with {}

//heredoc
$str= txt
form name=edit method=post action=emp_edit_result2.php
input type=hidden name=Status value=Active /
input type=hidden name=The_Date value= /
input type=hidden name=-recid value=$row /
input type=submit name=edit_submit value=Activate /
/form
txt;

if (!empty($emp_row-getField('testfield')) print $str;
else print Non Print;
?


[EMAIL PROTECTED] wrote:

Hello Folks,

I would like to be able to wrap a 'form' inside a php 'if statement' -  so
that the form will appear if the 'if condition' is met.

-  most likely I cannot have a ?php tag inside another one - and am sure
I'm doing other things wrong also...
- now I get the error - Parse error: syntax error, unexpected T_STRING in...

Q:  What is the best way to accomplish this goal?


---

?php if ($emp_row-getField('testfield') !=) {
print form name=edit method=post action=emp_edit_result2.php
input type=hidden name=Status value=Active/
input type=hidden name=The_Date value=/
input type=hidden name=-recid value=?php echo
$emp_row-getRecordId(); ?
input type=submit name=edit_submit value=Activate
/form

;}else {print Non Print;} ?




--
Thanks - RevDave
Cool7 @ hosting4days . com
[db-lists]





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