[PHP] Re: Variables in Variables?
Marquez Design said the following on 11/18/2005 04:54 PM:
Greetings.
Does anyone know how to do this?
I have,
$var
$var2
In a field called two_vars in a MySQL db.
I am calling the variables inside PHP document.
In that document I am saying:
$var = time
$var2 = clock
!-- I do the query in MySQL here --
echo $two_vars;
But the what prints out is
$var
$var2
not time and clock. I know that is what is in the database, but I want
it to replace the variables when printed in the PHP file.
Does this make sense to anyone? Does anyone know how to do this?
If I understand your question properly I'd explode $two_vars with
whatever seperator you have between them and then you'll need to use
eval to get your results. Maybe something like...
$dbVars=explode(',',$two_vars); // Assuming comma seperator
foreach($dbVars AS $key = $value) {
$eval=\$temp=.$value.;;
eval($eval);
echo $temp;
}
- Ben
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Re: [PHP] Re: Variables in Variables?
Ben wrote:
If I understand your question properly I'd explode $two_vars with
whatever seperator you have between them and then you'll need to use
eval to get your results. Maybe something like...
$dbVars=explode(',',$two_vars); // Assuming comma seperator
foreach($dbVars AS $key = $value) {
$eval=\$temp=.$value.;;
eval($eval);
echo $temp;
}
WTF do you need eval() for?!
$dbVars = explode( ',', $two_vars );
foreach( $dbVars as $value ) {
echo $value;
}
... does exactly the same thing.
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Re: [PHP] Re: Variables in Variables?
Jasper Bryant-Greene wrote:
Ben wrote:
$dbVars=explode(',',$two_vars); // Assuming comma seperator
foreach($dbVars AS $key = $value) {
$eval=\$temp=.$value.;;
eval($eval);
echo $temp;
}
WTF do you need eval() for?!
$dbVars = explode( ',', $two_vars );
foreach( $dbVars as $value ) {
echo $value;
}
Ah, sorry, I see what I missed now... Still, I'm sure there's a way to
do this without resorting to eval()...
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