[PHP] Re: include from another URL

2004-05-12 Thread AcZ
Nik wrote:
Hi there,
I'm new to these groups so forgive me if I'm asking at the wrong place (tell me where 
then :)
Ok,
I'm not PHP guru but I need to create a simple script that would do this:
Include a content from another URL into the current output. I have done something like
this:
-- code start
http://myotherurl.com:8080';
?>
-- code end
and it seems to work with one exception: it produces a warning message saying 
something like
 "Warning: main(): stream does not support seeking in .../web-root/index.php on line 9"
where line #9 is: include 'http://myotherurl.com:8080'; from above code.
It then shows a message from 'http://myotherurl.com:8080'
Thanks!!!
Nik
Nik,

try fopen instead of include..

http://br.php.net/manual/en/function.fopen.php
look at comments...
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[PHP] Re: Include from another URL?

2004-05-06 Thread Kim Steinhaug
You could always use this :

 $text = "";
 $fd=fopen($url,"r");
 while ($line=fgets($fd,1000)) { $text.=$line; } fclose ($fd);
 echo $text;

-- 
-- 
Kim Steinhaug
--
There are 10 types of people when it comes to binary numbers:
those who understand them, and those who don't.
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www.steinhaug.com - www.easywebshop.no - www.webkitpro.com
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"Nik" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi there,
> I'm new to these groups so forgive me if I'm asking at the wrong place
(tell
> me where then :)
>
> Ok,
> I'm not PHP guru but I need to create a simple script that would do this:
>
> Include a content from another URL into the current output. I have done
> something like
> this:
>
> -- code start
>   include 'http://myotherurl.com:8080';
> ?>
> -- code end
>
> and it seems to work with one exception: it produces a warning message
> saying something like
>  "Warning: main(): stream does not support seeking in
.../web-root/index.php
> on line 9"
> where line #9 is: include 'http://myotherurl.com:8080'; from above code.
> It then shows a message from 'http://myotherurl.com:8080'
>
> Thanks!!!
> Nik

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