[PHP] Regexp help second

[Uro Gruber]

Hi!
Last help about regexp solve my problem, but I have another one.
I've made some regexp but it does not work always
Let say I have some strings
1) this is some domain.com test
2) domain.com
I can make this work either for first example of fo second, but not for 
both. What I want is replace of domain.com to get

this is dome domain.com domain com test so replace should be
\1 \2 \3
so for second example I did /((.+)\.{1}(.+))/
How can I extend this to work in both.
regards
Uros
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Re: [PHP] Regexp help second

[Richard Lynch]

You could maybe cheat and add an X at the beginning and end of the string
before your Regex, then you will have:

X\1 \2 \3X

and you can strip off the initial X from \1 and the trailing X from \3

There's probably some fancy Regexp way to do it though.

Uroš Gruber wrote:
 Hi!

 Last help about regexp solve my problem, but I have another one.

 I've made some regexp but it does not work always

 Let say I have some strings

 1) this is some domain.com test
 2) domain.com

 I can make this work either for first example of fo second, but not for
 both. What I want is replace of domain.com to get

 this is dome domain.com domain com test so replace should be
 \1 \2 \3

 so for second example I did /((.+)\.{1}(.+))/

 How can I extend this to work in both.

 regards

 Uros

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Re: [PHP] Regexp help second

[Andrew Kreps]

On Thu, 06 Jan 2005 13:50:58 +0100, Uro Gruber [EMAIL PROTECTED] wrote:
 
 1) this is some domain.com test
 2) domain.com
 
 I can make this work either for first example of fo second, but not for
 both. What I want is replace of domain.com to get
 
 this is dome domain.com domain com test so replace should be
 \1 \2 \3
 
 so for second example I did /((.+)\.{1}(.+))/
 
 How can I extend this to work in both.
 

Can you explain in a little more detail what you're trying to replace
domain.com with?  I'm having trouble understanding your intentions.  A
regular expression like: /([\w-]+)\.([\w-]+)/ should be able to grab
strings like domain.com in any type of string (I'm using the
preg_replace function).

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