Re: [PHP] SUBSCRIPTION
On 5/31/05, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > I am changing my e-mail address and I tried to suscribe to this list through > the php.net automated subscription service. It didn't work. Suggestions? Try emailing [EMAIL PROTECTED] from the new address that you want to subscribe with (a blank message will do). I had problems signing up with the web based list manager as well. Paul -- Rogue Tory http://www.roguetory.org.uk -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] SUBSCRIPTION
I am changing my e-mail address and I tried to suscribe to this list through the php.net automated subscription service. It didn't work. Suggestions? Tony -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Subscription Request
On Nov 16, 2004, at 10:55 PM, sujis sakethram wrote: Hello sir, Previously i was subscribed to this list with email id [EMAIL PROTECTED] but it is geniune account that receives all important mails i mean from companies and personal. So, please subscribe me to this mail-id. Thanking you sir, yours sincerely, Rajesh.B ___ _ Yahoo! India Matrimony: Find your life partner online Go to: http://yahoo.shaadi.com/india-matrimony -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Subscription Request
Hello sir, Previously i was subscribed to this list with email id [EMAIL PROTECTED] but it is geniune account that receives all important mails i mean from companies and personal. So, please subscribe me to this mail-id. Thanking you sir, yours sincerely, Rajesh.B Yahoo! India Matrimony: Find your life partner online Go to: http://yahoo.shaadi.com/india-matrimony -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] subscription problem
On Tue, 11 Jun 2002, Doug DeVries wrote: > Why am I getting all the messages from this newsgroup delivered to my > mailbox? > > I subscribed to the newsgroup -- or at least that is all I wanted. > >> To unsubscribe, visit: http://www.php.net/unsub.php The above link would be a good start. You don't really "subscribe" to a newsgroup, since reading them is an entirely passive activity. miguel -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] subscription problem
Why am I getting all the messages from this newsgroup delivered to my mailbox? I subscribed to the newsgroup -- or at least that is all I wanted. Thanks. -Doug - Original Message - From: "Jason Soza" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Cc: <[EMAIL PROTECTED]> Sent: Tuesday, June 11, 2002 9:36 AM Subject: Re: [PHP] Different Problem [Re: Passing a Variable to PHP Via the URL] > Rather than just setting globals on in php.ini, try this: > > Your printf() line is: > printf("Variables: %s\n", $HTTP_GET_VARS["id"]); > > And your if() statement is: > if($id) {} > > Where is $id set? It's probably not. $HTTP_GET_VARS["id"] doesn't set > $id. If you want the "id" variable in your if(), you need: > if($HTTP_GET_VARS["id"]) {} > > Or alternately do: > $id = $HTTP_GET_VARS["id"] > if($id) {} > > Although that's not necessary. Also, try using $_GET["id"], as > $HTTP_GET_VARS[] has been deprecated in newer versions. > > HTH, > > Jason Soza > > - Original Message - > From: <[EMAIL PROTECTED]> > Date: Tuesday, June 11, 2002 8:16 am > Subject: [PHP] Different Problem [Re: Passing a Variable to PHP Via the > URL] > > > I found out that in fact PHP is creating a variable with the name > > and value I'm passing through a URL from the querystring. But > > it's still not working as planned. > > > > The url server/test.php?id=1 creates the following results in my code: > > > > printf("Variables: %s\n", $HTTP_GET_VARS["id"]); > > > > This line works - there IS a variable named 'id' in my page and it > > has the correct value, 1. > > > > if ($id) {} > > > > This fails. If I test 'id' instead of '$id' then it works but my > > page doesn't seem to equate 'id=1' with the presence of $id. > > > > $result = mysql_query("SELECT * FROM employees WHERE id=$id",$db); > > > > This doesn't work - again it seems $id isn't being treated > > properly. I get this error: > > > > Warning: mysql_fetch_array(): supplied argument is not a valid > > MySQL result resource > > > > If I hardwire my page with the line '$id=1;' before the if > > statement and the query everything works. > > > > So why isn't the variable from my URL being treated properly? > > > > Jesse > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php