[PHP] SUBSCRIPTION

[sbwi]

I am changing my e-mail address and I tried to suscribe to this list through 
the php.net automated subscription service.  It didn't work.  Suggestions?

Tony

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Re: [PHP] SUBSCRIPTION

[Paul Waring]

On 5/31/05, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
 I am changing my e-mail address and I tried to suscribe to this list through 
 the php.net automated subscription service.  It didn't work.  Suggestions?

Try emailing [EMAIL PROTECTED] from the new address
that you want to subscribe with (a blank message will do). I had
problems signing up with the web based list manager as well.

Paul

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Re: [PHP] Subscription Request

[Philip Thompson]

On Nov 16, 2004, at 10:55 PM, sujis sakethram wrote:
Hello sir,
 Previously i was subscribed to this list with
email id [EMAIL PROTECTED] but it is geniune account
that receives all important mails i mean from
companies and personal.
So, please subscribe me to this mail-id.
Thanking you sir,
  yours sincerely,
   Rajesh.B
___ 
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Yahoo! India Matrimony: Find your life partner online
Go to: http://yahoo.shaadi.com/india-matrimony

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[PHP] Subscription Request

[sujis sakethram]

Hello sir,

 Previously i was subscribed to this list with
email id [EMAIL PROTECTED] but it is geniune account
that receives all important mails i mean from
companies and personal.

So, please subscribe me to this mail-id.

Thanking you sir,

  yours sincerely,
   Rajesh.B


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Go to: http://yahoo.shaadi.com/india-matrimony

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[PHP] subscription problem

[Doug DeVries]

Why am I getting all the messages from this newsgroup delivered to my
mailbox?

I subscribed to the newsgroup -- or at least that is all I wanted.

Thanks.

-Doug

- Original Message -
From: Jason Soza [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Tuesday, June 11, 2002 9:36 AM
Subject: Re: [PHP] Different Problem [Re: Passing a Variable to PHP Via the
URL]


 Rather than just setting globals on in php.ini, try this:

 Your printf() line is:
 printf(Variables:  %s\nbr, $HTTP_GET_VARS[id]);

 And your if() statement is:
 if($id) {}

 Where is $id set? It's probably not. $HTTP_GET_VARS[id] doesn't set
 $id. If you want the id variable in your if(), you need:
 if($HTTP_GET_VARS[id]) {}

 Or alternately do:
 $id = $HTTP_GET_VARS[id]
 if($id) {}

 Although that's not necessary. Also, try using $_GET[id], as
 $HTTP_GET_VARS[] has been deprecated in newer versions.

 HTH,

 Jason Soza

 - Original Message -
 From: [EMAIL PROTECTED]
 Date: Tuesday, June 11, 2002 8:16 am
 Subject: [PHP] Different Problem [Re: Passing a Variable to PHP Via the
 URL]

  I found out that in fact PHP is creating a variable with the name
  and value I'm passing through a URL from the querystring.  But
  it's still not working as planned.
 
  The url server/test.php?id=1 creates the following results in my code:
 
  printf(Variables:  %s\nbr, $HTTP_GET_VARS[id]);
 
  This line works - there IS a variable named 'id' in my page and it
  has the correct value, 1.
 
  if ($id) {}
 
  This fails.  If I test 'id' instead of '$id' then it works but my
  page doesn't seem to equate 'id=1' with the presence of $id.
 
  $result = mysql_query(SELECT * FROM employees WHERE id=$id,$db);
 
  This doesn't work - again it seems $id isn't being treated
  properly.  I get this error:
 
  Warning: mysql_fetch_array(): supplied argument is not a valid
  MySQL result resource
 
  If I hardwire my page with the line '$id=1;' before the if
  statement and the query everything works.
 
  So why isn't the variable from my URL being treated properly?
 
  Jesse
 


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Re: [PHP] subscription problem

[Miguel Cruz]

On Tue, 11 Jun 2002, Doug DeVries wrote:
 Why am I getting all the messages from this newsgroup delivered to my
 mailbox?
 
 I subscribed to the newsgroup -- or at least that is all I wanted.

 To unsubscribe, visit: http://www.php.net/unsub.php

The above link would be a good start.

You don't really subscribe to a newsgroup, since reading them is an 
entirely passive activity.

miguel


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