On Mon, 19 Feb 2001 06:57, Claudia wrote:
> I am looking for code that explains how to sum a value in a database
> based on a current field retrieved from the database.
>
> Example:
>
> query = "select course_name, course_build, milestone, testcase,
> time_tested, issue_status, comment,
>bug_number, tested_by, date_tested from testissues where
> test_issue_id = $viewid";
> $result = mysql_query( $query );
>
> 1 - retrieve needed fields from database based on the id the user links
> from ($viewid)
> 2 - assign the course_name value from the query statement to a variable
> to be used on html page
>
> Assign: $course_name = mysql_result( $result, 0, "course_name" );
>
> Use variable:print " #00>$course_name\n";
>
>
> Now I would like to sum ALL the time_tested values in my database WHERE
> the course_name =
> $course_name (the variable retrieved for the record)
>
> query = "select sum(time_tested) where course_name = $course_name";
> $result = mysql_query( $query );
> $total_time = mysql_result( $result, 0, "sum(time_tested)");
>
> First issue -- php does not seem to recognize the value of $course_name
Do you mean here:
query = "select sum(time_tested) where course_name = $course_name";
because in that query $course_name should be enclosed in single quotes if
it is a char type field.
> Second issue -- will the $total_time value be calculated correctly
> based on the above syntax?
What type of field is time_tested?
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