[PHP] This is happening why?

2005-06-06 Thread Chris Boget
Run this code:

?
if( 0 == 'NULL' ) {
  echo 'NULL' == 0br;
} else {
  echo 'NULL' != 0br;
}
?

Is this just a case of PHP converting variable types for comparison?

thnx,
Chris

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Re: [PHP] This is happening why?

2005-06-06 Thread tg-php
Yeah.. you're comparing a string, 'NULL' with an integer 0.  You're not 
comparing NULL with anything, you're comparing a string that contains the word 
'NULL'.

You can use === to do an exact comparison without conversion.

echo intval('NULL');

intval('NULL') === 0



= = = Original message = = =

Run this code:

?
if( 0 == 'NULL' ) 
  echo 'NULL' == 0br;
 else 
  echo 'NULL' != 0br;

?

Is this just a case of PHP converting variable types for comparison?

thnx,
Chris

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RE: [PHP] This is happening why?

2005-06-06 Thread Jay Blanchard
[snip]
?
if( 0 == 'NULL' ) {
  echo 'NULL' == 0br;
} else {
  echo 'NULL' != 0br;
}
?
[/snip]

Interesting, to be sure. I even flipped the test
if('NULL' == 0)

Of course, once I made 0 a string '0' the test evaluated FALSE. So 0
(integer) is TRUE and 'NULL' is TRUE, which means that you asked if(TRUE
== TRUE), which is, of course, TRUE.

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