[PHP] __FILE__ and __LINE__ of calling scripts?
Hi,
I want to find out if it is possible to get the file name and the line
number of a calling script (__FILE__, __LINE_) from a calling class
automatically.
Let me explain:
I have a db class which gets called in other classes. Now, when an sql error
occurs I would like to find out which file and on which line it was.
E.g.:
[snip]
class DB {
function doQuery( $inq ) {
...
if( !this_result ) {
$this-drawError(**want the __FILE_ and __LINE__ of
the calling script here** ..);
...
}
}
}
class Caller {
function sql_doQuery() {
$SQL-doQuery('SELECT me FROM WHERE id=0');
}
}
[/snip]
The drawError function outputs the error report to the browser and halts the
script (developer debug).
Currently I get the __FILE__ and __LINE__ of the DB class, i.e. where the
query error happened (as in doQuery()).
Instead I would like to get something like caller.fileName,
caller.lineNumber (pseudo code).
Is that at all possible without having to pass the file name and the line
number into the query function manually?
Thanks
Thomas
SPIRAL EYE STUDIOS
P.O. Box 37907, Faerie Glen, 0043
Tel: +27 12 362 3486
Fax: +27 12 362 3493
Mobile: +27 82 442 9228
Email: [EMAIL PROTECTED]
Web: www.spiraleye.co.za
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Re: [PHP] __FILE__ and __LINE__ of calling scripts?
I want to find out if it is possible to get the file name and the line number of a calling script (__FILE__, __LINE_) from a calling class automatically. debug_backtrace contains that info. http://www.php.net/debug_backtrace -- Scott Noyes [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] __FILE__ and __LINE__ of calling scripts?
Thomas wrote:
Hi,
I want to find out if it is possible to get the file name and the line
number of a calling script (__FILE__, __LINE_) from a calling class
automatically.
Let me explain:
I have a db class which gets called in other classes. Now, when an sql error
occurs I would like to find out which file and on which line it was.
E.g.:
[snip]
class DB {
function doQuery( $inq ) {
...
if( !this_result ) {
$this-drawError(**want the __FILE_ and __LINE__ of
the calling script here** ..);
...
}
}
}
class Caller {
function sql_doQuery() {
$SQL-doQuery('SELECT me FROM WHERE id=0');
}
}
[/snip]
The drawError function outputs the error report to the browser and halts the
script (developer debug).
Currently I get the __FILE__ and __LINE__ of the DB class, i.e. where the
query error happened (as in doQuery()).
Instead I would like to get something like caller.fileName,
caller.lineNumber (pseudo code).
Is that at all possible without having to pass the file name and the line
number into the query function manually?
Thanks
Thomas
SPIRAL EYE STUDIOS
P.O. Box 37907, Faerie Glen, 0043
Tel: +27 12 362 3486
Fax: +27 12 362 3493
Mobile: +27 82 442 9228
Email: [EMAIL PROTECTED]
Web: www.spiraleye.co.za
Have you tried looking up debug_backtrace() in the manual?
HTH,
Mikey
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Re: [PHP] __FILE__ and __LINE__ of calling scripts?
Thomas wrote:
Hi,
I want to find out if it is possible to get the file name and the line
number of a calling script (__FILE__, __LINE_) from a calling class
automatically.
Let me explain:
I have a db class which gets called in other classes. Now, when an sql error
occurs I would like to find out which file and on which line it was.
E.g.:
[snip]
class DB {
function doQuery( $inq ) {
...
if( !this_result ) {
$this-drawError(**want the __FILE_ and __LINE__ of
the calling script here** ..);
...
}
}
}
class Caller {
function sql_doQuery() {
$SQL-doQuery('SELECT me FROM WHERE id=0');
}
}
[/snip]
The drawError function outputs the error report to the browser and halts the
script (developer debug).
Currently I get the __FILE__ and __LINE__ of the DB class, i.e. where the
query error happened (as in doQuery()).
Instead I would like to get something like caller.fileName,
caller.lineNumber (pseudo code).
Is that at all possible without having to pass the file name and the line
number into the query function manually?
Thanks
Thomas
SPIRAL EYE STUDIOS
P.O. Box 37907, Faerie Glen, 0043
Tel: +27 12 362 3486
Fax: +27 12 362 3493
Mobile: +27 82 442 9228
Email: [EMAIL PROTECTED]
Web: www.spiraleye.co.za
How about having sql_doQuery() return false if it fails, then run
drawError() from the calling script and you'd have the __FILE__ and
__LINE__ there without doing a debug_backtrace() parse?
Just a thought.
Ed
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RE: [PHP] __FILE__ and __LINE__ of calling scripts?
Hi,
I know I should not top post, but here it goes anyway:
just wanted to say thanks and let others know that it is SOLVED.
Cool thing this function! Gotta love PHP (thank heavens I don't need to use
jsp right now ...)
T
-Original Message-
From: Mikey [mailto:[EMAIL PROTECTED]
Sent: 27 September 2005 03:20 PM
To: php-general@lists.php.net
Subject: Re: [PHP] __FILE__ and __LINE__ of calling scripts?
Thomas wrote:
Hi,
I want to find out if it is possible to get the file name and the line
number of a calling script (__FILE__, __LINE_) from a calling class
automatically.
Let me explain:
I have a db class which gets called in other classes. Now, when an sql
error
occurs I would like to find out which file and on which line it was.
E.g.:
[snip]
class DB {
function doQuery( $inq ) {
...
if( !this_result ) {
$this-drawError(**want the __FILE_ and __LINE__ of
thecalling script here** ..);
...
}
}
}
class Caller {
function sql_doQuery() {
$SQL-doQuery('SELECT me FROM WHERE id=0');
}
}
[/snip]
The drawError function outputs the error report to the browser and halts
the
script (developer debug).
Currently I get the __FILE__ and __LINE__ of the DB class, i.e. where the
query error happened (as in doQuery()).
Instead I would like to get something like caller.fileName,
caller.lineNumber (pseudo code).
Is that at all possible without having to pass the file name and the line
number into the query function manually?
Thanks
Thomas
SPIRAL EYE STUDIOS
P.O. Box 37907, Faerie Glen, 0043
Tel: +27 12 362 3486
Fax: +27 12 362 3493
Mobile: +27 82 442 9228
Email: [EMAIL PROTECTED]
Web: www.spiraleye.co.za
Have you tried looking up debug_backtrace() in the manual?
HTH,
Mikey
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