Hi,
You are really messed up with this 'if' statement.
What you want is nicely described, so I won't repeat it, just make some correction...
function array2links($cat, $arr)
{
$i = 0;
$cat = rawurlencode($cat);
while ( list( $key, $val ) = each($arr))
{
$out .= a class=\cats\ href=\products.php?Cat=$catCode=$key\
title=\$val\$val/abr;
if ( $i == 5 ) {
$out .= /tdtd valign=\top\;
$i = 1;
}
else $i++;
}
return $out;
}
- Original Message -
From: Joseph Blythe [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: 2001. május 4. 08:02
Subject: [PHP] array 2 links
Hello,
I seem to be having some difficulty understanding why the following function skips
every 5th array item,
basically the following function takes two parameters category and an array, when
placed inside a table it will generate
links based on the array items splitting the table into columns when more than 4
links have been generated.
However as mentioned every 5th array item is skipped hmm..
The solution is probably really obvious but I can't seem to see it!
function array2links($cat, $arr) {
$i = 0;
$cat = rawurlencode($cat);
while ( list( $key, $val ) = each($arr)) {
$link = a class=\cats\ href=\products.php?Cat=$catCode=$key\
title=\$val\$val/abr;
if ( $i 4 ) {
$out .= $link;
} else {
$out .= /tdtd valign=\top\;
$i = 0;
continue;
}
$i++;
}
return $out;
}
Any help/ideas would be appreciated,
Regards,
Joseph.
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
