Re: [PHP] Date Calculation Help

2007-07-02 Thread Richard Lynch
If the date is coming from a database, there might be a
function/format already for that...

And http://php.net/date may also have a format specifier for Quarter.

If not, try this:

$quarter = ((int) ($month / 4)) + 1;

On Sat, June 30, 2007 10:14 am, revDAVE wrote:
> I have segmented a year into four quarters (3 months each)
>
> nowdate = the month of the chosen date (ex: 5-30-07 = month 5)
>
> Q: What is the best way to calculate which quarter  (1-2-3 or 4) the
> chosen
> date falls on?
>
> Result - Ex: 5-30-07 = month 5 and should fall in quarter 2
>
>
>
> --
> Thanks - RevDave
> [EMAIL PROTECTED]
> [db-lists]
>
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>


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Re: [PHP] Date Calculation Help

2007-07-02 Thread Dan
Well then after or before that you have to check that the month value is 
between 1 and 12 to make sure there's no input errors, then what if you ever 
want ot change the quarters yeah anway I just wanted an excuse to tell 
people to go low tech and use a switch, it's only 12 entries, and you could 
set a default.


- Dan

"Fredrik Thunberg" <[EMAIL PROTECTED]> wrote in message 
news:[EMAIL PROTECTED]

of course ceil( month / 3 );

--
/Thunis

Don't panic.
  --The Hitchikers Guide to the Galaxy

Fredrik Thunberg skrev:

$q = ceil( month / 4 );



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Re: [PHP] Date Calculation Help

2007-07-02 Thread Fredrik Thunberg

of course ceil( month / 3 );

--
/Thunis

Don't panic.
  --The Hitchikers Guide to the Galaxy

Fredrik Thunberg skrev:

$q = ceil( month / 4 );



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Re: [PHP] Date Calculation Help

2007-07-02 Thread Fredrik Thunberg

$q = ceil( month / 4 );

--
/Thunis

The ships hung in the sky in much the same way that bricks don't.
  --The Hitchikers Guide to the Galaxy

revDAVE skrev:

I have segmented a year into four quarters (3 months each)

nowdate = the month of the chosen date (ex: 5-30-07 = month 5)

Q: What is the best way to calculate which quarter  (1-2-3 or 4) the chosen
date falls on?

Result - Ex: 5-30-07 = month 5 and should fall in quarter 2



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[EMAIL PROTECTED]
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Re: [PHP] Date Calculation Help

2007-06-30 Thread Paul Novitski

At 6/30/2007 08:14 AM, revDAVE wrote:

I have segmented a year into four quarters (3 months each)

nowdate = the month of the chosen date (ex: 5-30-07 = month 5)

Q: What is the best way to calculate which quarter  (1-2-3 or 4) the chosen
date falls on?

Result - Ex: 5-30-07 = month 5 and should fall in quarter 2



If you divide the month number by 3 you get:

1   0.3
2   0.7
3   1
4   1.3
5   1.7
6   2
7   2.3
8   2.7
9   3
10  3.3
11  3.7
12  4

The first digit is off by one, so subtract .1 from each result:

1   0.2
2   0.56667
3   0.9
4   1.2
5   1.56667
6   1.9
etc.

Now you can see from the first digit that if you take the integer 
value and add 1 you'll get:


1   1
2   1
3   1
4   2
5   2
6   2
etc.

In PHP this could be:

intval(($month - .1)/3 + 1)
or:
intval(($month + .9)/3)

I believe you can use intval() and floor() interchangeably in this 
circumstance.


Regards,

Paul
__

Paul Novitski
Juniper Webcraft Ltd.
http://juniperwebcraft.com 


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[PHP] Date Calculation Help

2007-06-30 Thread revDAVE
I have segmented a year into four quarters (3 months each)

nowdate = the month of the chosen date (ex: 5-30-07 = month 5)

Q: What is the best way to calculate which quarter  (1-2-3 or 4) the chosen
date falls on?

Result - Ex: 5-30-07 = month 5 and should fall in quarter 2



--
Thanks - RevDave
[EMAIL PROTECTED]
[db-lists]

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Re: [PHP] Date calculation

2006-10-15 Thread Travis Doherty
Ron Piggott (PHP) wrote:

>I have one more date based question.
>
>I have a month field ( $month ) and a day field ( $day ) being submitted
>by a form.
>
>I have a third field to be used as a date reminder for the information
>which was submitted as part of the form.  It is a reminder to complete a
>task for the date was which was submitted as part of the form.  
>
>How do I calculate the $reminder date based on $month and $day and have
>it output in the -MM-DD format?  $reminder is the number of days
>before $month $day  (I want to use $reminder in a date format to SELECT
>records from a mySQL table)  This is why I am wanting put $reminder into
>a date format
>
>If $month was 6 and $day was 7 and $reminder was 6 then I would want the
>output to be 2007-06-01 --- We have already passed June 1st in 2006.
>However if $month was 11 then I would want the output to use this years
>date --- 2006-11-01
>
>Any suggestions?  
>
>Ron
>
>  
>
I think it would be easier to ask the user to enter his reminder in the
standard date format of -mm-dd and use a JavaScript date picker box
to prompt for it.  Anyway, you could do something like this:

$reminderStamp = strtotime("+{$addMonths} months",time());
$reminderStamp = strtoTime("+{$addDays} days",$reminderStamp);
$date = date("Y-m-d",$reminderStamp);

$date should have a string like -mm-dd that is $addMonths and
$addDays into the future.  I didn't test this.

Travis Doherty

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[PHP] Date calculation

2006-10-15 Thread Ron Piggott (PHP)
I have one more date based question.

I have a month field ( $month ) and a day field ( $day ) being submitted
by a form.

I have a third field to be used as a date reminder for the information
which was submitted as part of the form.  It is a reminder to complete a
task for the date was which was submitted as part of the form.  

How do I calculate the $reminder date based on $month and $day and have
it output in the -MM-DD format?  $reminder is the number of days
before $month $day  (I want to use $reminder in a date format to SELECT
records from a mySQL table)  This is why I am wanting put $reminder into
a date format

If $month was 6 and $day was 7 and $reminder was 6 then I would want the
output to be 2007-06-01 --- We have already passed June 1st in 2006.
However if $month was 11 then I would want the output to use this years
date --- 2006-11-01

Any suggestions?  

Ron


Re: [PHP] Date Calculation

2004-10-29 Thread Robert Sossomon
Wouldn't just making the script get 2 time stamps be more efficient, since you 
are creating the database calls anyways?  Or am I over simplifying it?


// current time at start of script
$before = strtotime("now");
//All your DB stuff
{
 
}
// current time at end of script
$after = strtotime("now");
$timed = ($after - $before);
echo 'Time for script to execute: ' . $timed .' seconds';
?>
Robert

Mike Tuller is quoted as saying on 10/28/2004 5:19 PM:
Ok, so here is what I have. Please check to see if there is a better 
way. There are a lot of database calls to me.

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Re[2]: [PHP] Date Calculation

2004-10-28 Thread Tom Rogers
Hi,

Friday, October 29, 2004, 7:19:09 AM, you wrote:
MT> Ok, so here is what I have. Please check to see if there is a better 
MT> way. There are a lot of database calls to me.

MT>  $database_name = "CETechnology";
MT> $host = "server";
MT> $login = "username";
MT> $password = "password";

MT> $ethernet_address = "00:01:93:8e:69:50";


MT> $db_connect = mysql_connect( $host, $login, $password ) or die 
MT> (mysql_error());
MT> $db_select = mysql_select_db($database_name) or die (mysql_error());

MT> $query = "SELECT * FROM hardware_assets WHERE ethernet_address = 
MT> '$ethernet_address'";
MT> $result = mysql_query($query, $db_connect) or die (mysql_error());

MT> while ($row = mysql_fetch_array( $result ))
MT> {
MT> $timestamp = $row["script_ran"];
MT> $timequery = "SELECT SEC_TO_TIME(UNIX_TIMESTAMP() - 
MT> UNIX_TIMESTAMP('$timestamp')) as diff";
MT> $timeresult = mysql_query($timequery, $db_connect) or die 
MT> (mysql_error());
MT> $time = mysql_result($timeresult, 0, 0);

MT> $secondquery = "SELECT TIME_TO_SEC('$time')";
MT> $secondresult = mysql_query($secondquery, $db_connect) or die 
MT> (mysql_error());
MT> $seconds = mysql_result($secondresult, 0, 0);

MT> echo $seconds;
MT> }


?>>

MT> This returns the seconds since the timestamp was set for the row where 
MT> the ethernet address of the computer is equal to $ethernet_address. I 
MT> can then do the math so that I can display the hours or minutes. I can 
MT> even have it so that when the time is too long, it displays in red, or 
MT> bold, or whatever I want.

Do it in one hit :)timediff comes out in hours:minutes:seconds

$query = "
SELECT *,
UNIX_TIMESTAMP() - UNIX_TIMESTAMP(script_ran) as seconds,
SEC_TO_TIME(UNIX_TIMESTAMP() - UNIX_TIMESTAMP(script_ran)) as timediff
FROM hardware_assets 
WHERE ethernet_address = '$ethernet_address'";

$result = mysql_query($query, $db_connect) or die (mysql_error());

while ($row = mysql_fetch_array( $result )){
$seconds = $row["seconds"];
$timediff = $row["timediff"];
echo "$seconds = $timediff ";
}

-- 
regards,
Tom

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Re: [PHP] Date Calculation

2004-10-28 Thread Jennifer Goodie
-- Original message from Mike Tuller <[EMAIL PROTECTED]>: -- 

> Ok, so here is what I have. Please check to see if there is a better 
> way. There are a lot of database calls to me. 

There are.  Do it in one query.
> 
> $query = "SELECT * FROM hardware_assets WHERE ethernet_address = 
> '$ethernet_address'"; 
> $result = mysql_query($query, $db_connect) or die (mysql_error()); 
> 
> while ($row = mysql_fetch_array( $result )) 
> { 
> $timestamp = $row["script_ran"]; 
> $timequery = "SELECT SEC_TO_TIME(UNIX_TIMESTAMP() - 
> UNIX_TIMESTAMP('$timestamp')) as diff"; 
> $timeresult = mysql_query($timequery, $db_connect) or die 
> (mysql_error()); 
> $time = mysql_result($timeresult, 0, 0); 
> 
> $secondquery = "SELECT TIME_TO_SEC('$time')"; 
> $secondresult = mysql_query($secondquery, $db_connect) or die 
> (mysql_error()); 
> $seconds = mysql_result($secondresult, 0, 0); 
> 
> echo $seconds; 
> } 
> 

I don't know why you're doing both TIME_TO_SEC and SEC_TO_TIME, so I'm leaving them 
out as they are inverses.  But I'm sure you can figure out what you want.

$query = "SELECT  *, (UNIX_TIMESTAMP() - UNIX_TIMESTAMP(script_ran)) as seconds FROM 
hardware_assets WHERE ethernet_address =  '$ethernet_address'"; 

This will return all the columns from the matching rows, plus an extra field called 
seconds that is the difference in seconds between now and wehn the script ran.  

Here is the list of mysql date/time functions for refernece 
http://dev.mysql.com/doc/mysql/en/Date_and_time_functions.html#IDX1454

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Re: [PHP] Date Calculation

2004-10-28 Thread Mike Tuller
Ok, so here is what I have. Please check to see if there is a better 
way. There are a lot of database calls to me.


$ethernet_address = "00:01:93:8e:69:50";
$db_connect = mysql_connect( $host, $login, $password ) or die 
(mysql_error());
$db_select = mysql_select_db($database_name) or die (mysql_error());

$query = "SELECT * FROM hardware_assets WHERE ethernet_address = 
'$ethernet_address'";
$result = mysql_query($query, $db_connect) or die (mysql_error());

while ($row = mysql_fetch_array( $result ))
{
	$timestamp = $row["script_ran"];
	$timequery = "SELECT SEC_TO_TIME(UNIX_TIMESTAMP() - 
UNIX_TIMESTAMP('$timestamp')) as diff";
	$timeresult = mysql_query($timequery, $db_connect) or die 
(mysql_error());
	$time = mysql_result($timeresult, 0, 0);
	
	$secondquery = "SELECT TIME_TO_SEC('$time')";
	$secondresult = mysql_query($secondquery, $db_connect) or die 
(mysql_error());
	$seconds = mysql_result($secondresult, 0, 0);

echo $seconds;
}
?>
This returns the seconds since the timestamp was set for the row where 
the ethernet address of the computer is equal to $ethernet_address. I 
can then do the math so that I can display the hours or minutes. I can 
even have it so that when the time is too long, it displays in red, or 
bold, or whatever I want.


On Oct 28, 2004, at 3:14 PM, Tom Rogers wrote:
Hi,
Friday, October 29, 2004, 4:51:20 AM, you wrote:
MT> I have a shell script that inserts the unix date and time that the
MT> script ran into a MySql database. For example Thu Oct 28 13:41:33 
CDT
MT> 2004. I would like to have my web page do the math so that it 
displays
MT> the time since the script ran. How can I do the math so that the 
web
MT> page will display something like the script ran 1500 seconds ago.

MT> Thanks,
MT> mike
You can do something like this (replace date with column name no 
quotes)

$result = mysql_query("SELECT SEC_TO_TIME(UNIX_TIMESTAMP() - 
UNIX_TIMESTAMP('2004-10-01 13:45:00')) as diff");

--
regards,
Tom
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Re: [PHP] Date Calculation

2004-10-28 Thread Tom Rogers
Hi,

Friday, October 29, 2004, 4:51:20 AM, you wrote:
MT> I have a shell script that inserts the unix date and time that the 
MT> script ran into a MySql database. For example Thu Oct 28 13:41:33 CDT 
MT> 2004. I would like to have my web page do the math so that it displays 
MT> the time since the script ran. How can I do the math so that the web 
MT> page will display something like the script ran 1500 seconds ago.


MT> Thanks,

MT> mike


You can do something like this (replace date with column name no quotes)

$result = mysql_query("SELECT SEC_TO_TIME(UNIX_TIMESTAMP() - 
UNIX_TIMESTAMP('2004-10-01 13:45:00')) as diff");

-- 
regards,
Tom

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Re: [PHP] Date Calculation

2004-10-28 Thread Mike Tuller
I guess.
Are you telling me that I should take the timestamp, convert it to 
epoch time, the us the time function to get the current epoch time, 
then subtract the timestamp epoch time from the current epoch time? I 
think that is what you are saying.

I know I can get the current epoch time in php with time(). How do I 
convert the timestamp in the database to epoch time, or find the epoch 
time in bash? If I can't do it in either, then I am subtracting apples 
from oranges.

On Oct 28, 2004, at 2:32 PM, Jay Blanchard wrote:
[snip]
That's not quite what I am talking about. I looked at that already.
I can could also put the date and time that the script was ran into the
MySql database by have a TIMESTAMP field in the database.
[/snip]
You can use that to convert your time in the DB, get the current time
when seeking as epoch time, subtract one from the otherno?
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RE: [PHP] Date Calculation

2004-10-28 Thread Jay Blanchard
[snip]
I have a shell script that inserts the unix date and time that the 
script ran into a MySql database. For example Thu Oct 28 13:41:33 CDT 
2004. I would like to have my web page do the math so that it displays 
the time since the script ran. How can I do the math so that the web 
page will display something like the script ran 1500 seconds ago.
[/snip]

http://us2.php.net/manual/en/function.strtotime.php

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[PHP] Date Calculation

2004-10-28 Thread Mike Tuller
I have a shell script that inserts the unix date and time that the 
script ran into a MySql database. For example Thu Oct 28 13:41:33 CDT 
2004. I would like to have my web page do the math so that it displays 
the time since the script ran. How can I do the math so that the web 
page will display something like the script ran 1500 seconds ago.

Thanks,
mike
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RE: [PHP] Date Calculation

2004-10-28 Thread Jay Blanchard
[snip]
That's not quite what I am talking about. I looked at that already.

I can could also put the date and time that the script was ran into the 
MySql database by have a TIMESTAMP field in the database.
[/snip]

You can use that to convert your time in the DB, get the current time
when seeking as epoch time, subtract one from the otherno?

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Re: [PHP] Date Calculation

2004-10-28 Thread Mike Tuller
That's not quite what I am talking about. I looked at that already.
I can could also put the date and time that the script was ran into the 
MySql database by have a TIMESTAMP field in the database.

I would like to compare the date and time of timestamp in the database 
to the current time and come up with the difference in seconds. Then I 
could show on the web page that the script was run x many seconds ago. 
From that I could do the calculations to show that it was x minutes, 
xhours, etc.


On Oct 28, 2004, at 1:52 PM, Jay Blanchard wrote:
[snip]
I have a shell script that inserts the unix date and time that the
script ran into a MySql database. For example Thu Oct 28 13:41:33 CDT
2004. I would like to have my web page do the math so that it displays
the time since the script ran. How can I do the math so that the web
page will display something like the script ran 1500 seconds ago.
[/snip]
http://us2.php.net/manual/en/function.strtotime.php
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Re: [PHP] date calculation

2003-02-16 Thread Stephen Willcock
Yes, will be OK with all dates (though the valid range of a timestamp is
typically from Fri, 13 Dec 1901 20:45:54 GMT to Tue, 19 Jan 2038 03:14:07
GMT.)

The function you want for numeric dates is:
int mktime ( int hour, int minute, int second, int month, int day, int year)

so, in your example (1st Feb 2003):
$mydate = mktime(0,0,0,2,1,2003);

SW


"Qt" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Dear Stephen,
>
> Good clue!!
>
> Is it working allways without problem such as 29 feb?
>
> And one more hel how can I write "1 2 2003" instead of  "1 february 2003"
>
> I wrote but directly but doesn' t work
>
> thanks
>
> "Stephen Willcock" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > Try:
> >
> > $today = strtotime ("1 february 2003");
> > $enddate = strtotime ("2 february 2003");
> > $diff = $enddate - $today;
> >
> > Should give you a clue!
> >
> > SW
> >
> >
> > "Qt" <[EMAIL PROTECTED]> wrote in message
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > Dear Kevin,
> > >
> > > I used timestamp allready as following;
> > >
> > > $today = strtotime ("1 february 2003");
> > > $enddate = strtotime ("1 march 2003");
> > >
> > > $diff = $enddate - $today;
> > >
> > > But result comes as
> > >
> > > 2419200
> > >
> > > How can I convert that numbers to days
> > >
> > > Best Regards
> > >
> > >
> > >
> > > "Kevin Waterson" <[EMAIL PROTECTED]> wrote in message
> > > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > > This one time, at band camp,
> > > > "qt" <[EMAIL PROTECTED]> wrote:
> > > >
> > > > > Dear Sirs,
> > > > >
> > > > > How can I add or subtract two date easily. Is therea any lib or
> > function
> > > > > about this. I can not find any easy way in the manual
> > > >
> > > > if the dates are timestamps, simply
> > > >
> > > > $new = $timestamp2 - $timestamp1;
> > > >
> > > > cheers
> > > > Kevin
> > > >
> > > > --
> > > >  __
> > > > (_ \
> > > >  _) )           
> > > > |  /  / _  ) / _  | / ___) / _  )
> > > > | |  ( (/ / ( ( | |( (___ ( (/ /
> > > > |_|   \) \_||_| \) \)
> > > > Kevin Waterson
> > > > Port Macquarie, Australia
> > >
> > >
> >
> >
>
>



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Re: [PHP] date calculation

2003-02-16 Thread qt
Dear Stephen,

Good clue!!

Is it working allways without problem such as 29 feb?

And one more hel how can I write "1 2 2003" instead of  "1 february 2003"

I wrote but directly but doesn' t work

thanks

"Stephen Willcock" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Try:
>
> $today = strtotime ("1 february 2003");
> $enddate = strtotime ("2 february 2003");
> $diff = $enddate - $today;
>
> Should give you a clue!
>
> SW
>
>
> "Qt" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > Dear Kevin,
> >
> > I used timestamp allready as following;
> >
> > $today = strtotime ("1 february 2003");
> > $enddate = strtotime ("1 march 2003");
> >
> > $diff = $enddate - $today;
> >
> > But result comes as
> >
> > 2419200
> >
> > How can I convert that numbers to days
> >
> > Best Regards
> >
> >
> >
> > "Kevin Waterson" <[EMAIL PROTECTED]> wrote in message
> > [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > > This one time, at band camp,
> > > "qt" <[EMAIL PROTECTED]> wrote:
> > >
> > > > Dear Sirs,
> > > >
> > > > How can I add or subtract two date easily. Is therea any lib or
> function
> > > > about this. I can not find any easy way in the manual
> > >
> > > if the dates are timestamps, simply
> > >
> > > $new = $timestamp2 - $timestamp1;
> > >
> > > cheers
> > > Kevin
> > >
> > > --
> > >  __
> > > (_ \
> > >  _) )           
> > > |  /  / _  ) / _  | / ___) / _  )
> > > | |  ( (/ / ( ( | |( (___ ( (/ /
> > > |_|   \) \_||_| \) \)
> > > Kevin Waterson
> > > Port Macquarie, Australia
> >
> >
>
>



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Re: [PHP] date calculation

2003-02-16 Thread Stephen Willcock
Try:

$today = strtotime ("1 february 2003");
$enddate = strtotime ("2 february 2003");
$diff = $enddate - $today;

Should give you a clue!

SW


"Qt" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> Dear Kevin,
>
> I used timestamp allready as following;
>
> $today = strtotime ("1 february 2003");
> $enddate = strtotime ("1 march 2003");
>
> $diff = $enddate - $today;
>
> But result comes as
>
> 2419200
>
> How can I convert that numbers to days
>
> Best Regards
>
>
>
> "Kevin Waterson" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > This one time, at band camp,
> > "qt" <[EMAIL PROTECTED]> wrote:
> >
> > > Dear Sirs,
> > >
> > > How can I add or subtract two date easily. Is therea any lib or
function
> > > about this. I can not find any easy way in the manual
> >
> > if the dates are timestamps, simply
> >
> > $new = $timestamp2 - $timestamp1;
> >
> > cheers
> > Kevin
> >
> > --
> >  __
> > (_ \
> >  _) )           
> > |  /  / _  ) / _  | / ___) / _  )
> > | |  ( (/ / ( ( | |( (___ ( (/ /
> > |_|   \) \_||_| \) \)
> > Kevin Waterson
> > Port Macquarie, Australia
>
>



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Re: [PHP] date calculation

2003-02-16 Thread qt
Dear Kevin,

I used timestamp allready as following;

$today = strtotime ("1 february 2003");
$enddate = strtotime ("1 march 2003");

$diff = $enddate - $today;

But result comes as

2419200

How can I convert that numbers to days

Best Regards



"Kevin Waterson" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> This one time, at band camp,
> "qt" <[EMAIL PROTECTED]> wrote:
>
> > Dear Sirs,
> >
> > How can I add or subtract two date easily. Is therea any lib or function
> > about this. I can not find any easy way in the manual
>
> if the dates are timestamps, simply
>
> $new = $timestamp2 - $timestamp1;
>
> cheers
> Kevin
>
> --
>  __
> (_ \
>  _) )           
> |  /  / _  ) / _  | / ___) / _  )
> | |  ( (/ / ( ( | |( (___ ( (/ /
> |_|   \) \_||_| \) \)
> Kevin Waterson
> Port Macquarie, Australia



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Re: [PHP] date calculation

2003-02-16 Thread Kevin Waterson
This one time, at band camp,
"qt" <[EMAIL PROTECTED]> wrote:

> Dear Sirs,
> 
> How can I add or subtract two date easily. Is therea any lib or function
> about this. I can not find any easy way in the manual

if the dates are timestamps, simply

$new = $timestamp2 - $timestamp1;

cheers
Kevin

-- 
 __  
(_ \ 
 _) )            
|  /  / _  ) / _  | / ___) / _  )
| |  ( (/ / ( ( | |( (___ ( (/ / 
|_|   \) \_||_| \) \)
Kevin Waterson
Port Macquarie, Australia

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[PHP] date calculation

2003-02-16 Thread qt
Dear Sirs,

How can I add or subtract two date easily. Is therea any lib or function
about this. I can not find any easy way in the manual

Best Regards



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Re: [PHP] date calculation

2001-05-04 Thread James Holloway

Gary,

Yes. Check the manual for mktime(); and getdate();
http://www.php.net/quickref.php

James

> Is there a way to do calculations with dates? Preferably ignoring
weekends.
>
> Thanks, Gary
>
>
>
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[PHP] date calculation

2001-05-04 Thread Gary

Is there a way to do calculations with dates? Preferably ignoring weekends.

Thanks, Gary



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