[PHP] db query not working as expected

2007-03-07 Thread Ed Curtis 

I have this code:

mysql_connect ($local_host, $local_user, $local_pass);
mysql_select_db ($local_db);

mysql_query (DELETE FROM tmphitsmag);

$result = mysql_query (SELECT DISTINCT company FROM view_log WHERE 
company != '');


if ($row = mysql_fetch_array($result)) {

do {

$magazine_path = $row['company'];
$magazine_path = explode(/, $magazine_path);

echo str_replace(_,  , $magazine_path[2]) . br;

mysql_query (INSERT INTO tmphitsmag (magazine) 
VALUES 		('$magazine_path[2]'));


} while($row = mysql_fetch_array($result));

} mysql_close();

The code dumps the first table fine, selects, manipulates, and echoes 
the string the way I expect, but fails to input the string into the 
tmphitsmag table.


Any ideas?

Thanks,

Ed

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Re: [PHP] db query not working as expected

2007-03-07 Thread Tijnema ! 

On 3/7/07, Ed Curtis [EMAIL PROTECTED] wrote:


I have this code:

mysql_connect ($local_host, $local_user, $local_pass);
mysql_select_db ($local_db);

mysql_query (DELETE FROM tmphitsmag);

$result = mysql_query (SELECT DISTINCT company FROM view_log WHERE
company != '');

if ($row = mysql_fetch_array($result)) {

do {

$magazine_path = $row['company'];
$magazine_path = explode(/, $magazine_path);

echo str_replace(_,  , $magazine_path[2]) . br;

mysql_query (INSERT INTO tmphitsmag (magazine)
VALUES  ('$magazine_path[2]'));



Not sure about it but try this:
 mysql_query (INSERT INTO tmphitsmag (magazine) VALUES
('.$magazine_path[2].'));

Tijnema

   } while($row = mysql_fetch_array($result));


} mysql_close();

The code dumps the first table fine, selects, manipulates, and echoes
the string the way I expect, but fails to input the string into the
tmphitsmag table.

Any ideas?

Thanks,

Ed

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Re: [PHP] db query not working as expected

2007-03-07 Thread Tijnema ! 

On 3/7/07, Ed Curtis [EMAIL PROTECTED] wrote:


I have this code:

mysql_connect ($local_host, $local_user, $local_pass);
mysql_select_db ($local_db);

mysql_query (DELETE FROM tmphitsmag);

$result = mysql_query (SELECT DISTINCT company FROM view_log WHERE
company != '');

if ($row = mysql_fetch_array($result)) {

do {

$magazine_path = $row['company'];
$magazine_path = explode(/, $magazine_path);

echo str_replace(_,  , $magazine_path[2]) . br;

mysql_query (INSERT INTO tmphitsmag (magazine)
VALUES  ('$magazine_path[2]'));




what about adding the usual or die?
mysql_query (INSERT INTO tmphitsmag (magazine)VALUES
('$magazine_path[2]')) or die(mysql_error());

Tijnema

   } while($row = mysql_fetch_array($result));


} mysql_close();

The code dumps the first table fine, selects, manipulates, and echoes
the string the way I expect, but fails to input the string into the
tmphitsmag table.

Any ideas?

Thanks,

Ed

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Re: [PHP] db query not working as expected

2007-03-07 Thread cajbecu 
try:

mysql_query (INSERT INTO tmphitsmag (magazine) VALUES
   ('{$magazine_path[2]}'));

cajb.

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Re: [PHP] db query not working as expected

2007-03-07 Thread Stut 

Ed Curtis wrote:
mysql_query (INSERT INTO tmphitsmag (magazine) 
VALUES ('$magazine_path[2]'));


Replace that with this...


mysql_query (INSERT INTO tmphitsmag (magazine) VALUES 


 ('.mysql_real_escape_string($magazine_path[2]).'));

-Stut

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