Define how index.php calls the login.php file. I assume you mean index.php
include() login.php, which has include() on config.php? If so, be sure that
the path to config.php as included in login.php is right. Use the fully
qualified path to ensure it works right.
Other than that, as long as the function declaration comes before you make a
call to the function (I remember someone saying that if a function is
declared in an included file it must do so before calling that function).
Then again, it would give you an error if that was the problem
...hm, I don't then see what the problem is. I don't believe what you've
showed so far is the reason. My bet is that you're getting a message that
you aren't logged on because you really aren't logged on. Something is
happening so that...AHA!
I just think I found the problem. In your function you are using two
variables, $pass and $username which are not declared as global in your
function. Add this line at the top of your function:
global $pass, $username;
See if that fixes it.
Plutarck
Greg K [EMAIL PROTECTED] wrote in message
9e0bfs$fld$[EMAIL PROTECTED]">news:9e0bfs$fld$[EMAIL PROTECTED]...
I am creating a function called login, I have a main file called index.php
.. which has my login form , it calls a login.php file, and in that
login.php there is file include statement which calls config.php and that
is
where the function lie. This is my function , now if i don't set this as a
function and just put it my login.php it works fine. But when I name the
function in put it in my config.php no matter what I do all ways giving me
the error You have entered an invalid username or password. I dont know if
this has to do with passing of variables.. or what is going on but if
something can please help me I would appreciate it ..
Thank You
function login() {
$query=Select uname from members where pass='$pass'and
uname='$username';
$result=mysql_query($query) or die(You are not authorized to be here.);
$array= @mysql_fetch_array($result);
$uname = $array[0];
if($uname==)
{
echo You have entered an invalid username or password;
}
else
{
echo You are logged in;
$remote_address = getenv(REMOTE_ADDR);
echo Your IP address is $remote_address.;
}
}
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