[PHP] help me please!
My system is windows 98 second edition im using pws i built php 4.2.2 when ý struggle to reach any .php file for example 127.0.0.1/sample.php this error occur: Security Alert! The PHP CGI cannot be accessed directly. This PHP CGI binary was compiled with force-cgi-redirect enabled. This means that a page will only be served up if the REDIRECT_STATUS CGI variable is set, e.g. via an Apache Action directive. please help me!! _ Add photos to your messages with MSN 8. Get 2 months FREE*. http://join.msn.com/?page=features/featuredemail -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] help me please
Hello, I am making a web site i just want to be able to view my php outputs On my Computer how do i do this i have downlaoded the 1mb windows php installer. and have the zipped version(4.3.0) that is 4mb I have windows xp. Can you please point me in the right direction or give me some answers on how to view my pages. Thanks Blair.
RE: [PHP] help me please
download and install the apache web server. that along with php should do the trick. if you're doing any database work you may want to pick up the windows version of that too. some decent instructions are here: http://www.thesitewizard.com/archive/php4install.shtml -Original Message- From: Blair Robinson [mailto:[EMAIL PROTECTED] Sent: Sunday, March 16, 2003 7:47 PM To: [EMAIL PROTECTED] Subject: [PHP] help me please Hello, I am making a web site i just want to be able to view my php outputs On my Computer how do i do this i have downlaoded the 1mb windows php installer. and have the zipped version(4.3.0) that is 4mb I have windows xp. Can you please point me in the right direction or give me some answers on how to view my pages. Thanks Blair. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] help me please
Hello all, I am having problems with a script. The script works great on one of my sights, however, when I transferred it to another site, it does not function. I contacted my hosting company (both sites are on the same server), they told me that I needed to check the script and that it has nothing to do with them, since they ran a test.php and it worked fine. Here is the script: ?PHP $ToEmail = [EMAIL PROTECTED]; $ToSubject = Flash Contact Form; $EmailBody = Sent By: $FirstName\nSenders Email: $Email\n\nMessage Sent:\n$ToComments\n; mail($ToName. .$ToEmail.,$ToSubject, $EmailBody, From: .$FirstName. .$Email.); ? Please if anyone knows anything about this stuff (Im a newbie to this) You help is greatly appreciated! Thanks in advance, mark johnson -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Fw: [PHP] help me please
You don't have to break up the strings: mail($ToName $ToEmail,$ToSubject, $EmailBody, From: $FirstName $Email); What are values of $ToName and $FirstName? why did you submit tghis 3 times? - Original Message - From: bionicegg [EMAIL PROTECTED] To: Sent: Tuesday, February 25, 2003 11:38 AM Subject: [PHP] help me please Hello all, I am having problems with a script. The script works great on one of my sights, however, when I transferred it to another site, it does not function. I contacted my hosting company (both sites are on the same server), they told me that I needed to check the script and that it has nothing to do with them, since they ran a test.php and it worked fine. Here is the script: ?PHP $ToEmail = [EMAIL PROTECTED]; $ToSubject = Flash Contact Form; $EmailBody = Sent By: $FirstName\nSenders Email: $Email\n\nMessage Sent:\n$ToComments\n; mail($ToName. .$ToEmail.,$ToSubject, $EmailBody, From: .$FirstName. .$Email.); ? Please if anyone knows anything about this stuff (Im a newbie to this) You help is greatly appreciated! Thanks in advance, mark johnson -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] help me please.
got a problem here people. What I want to do is upload a file and store its name in a database. For some reason I cant. I can upload the file fine but can't pass it's name to the mysql DB. Any ideas: Upload form: ? require( ../Cart.php); Brand(); DBInfo(); echo bYou can now upload a picture.../bbrbr; echo form enctype='multipart/form-data' action='uploadItem.php' method=post; echo INPUT TYPE='hidden' name='MAX_FILE_SIZE' value='25000'; echo INPUT TYPE='hidden' name='ID' value='$II'; echo INPUT name='userfile' type='file'; blueFont( Arial, Send this file: ); echo INPUT TYPE='submit' VALUE='Send File'/form; echo pbThis file MUST be a JPEG (jpg) image./b; //adminFooter($Relative); ? Process the form: ? require(../Cart.php); Root(); DBinfo(); mysql_connect($DBHost,$DBUser,$DBPass); $UploadURL = ../images/; if ($usefile==none) { echo Error: no file uploaded; exit; } //Connect to DB $mysql = mysql_connect($DBHost,$DBUser,$DBPass); if(!$mysql) { echo Cannot connect to database.; exit; } mysql_query(INSERT INTO Items (ImageName) WHERE ItemID = '$II' VALUE('test')); $upfile = $UploadURL.$userfile_name; if ( !copy($userfile, $upfile)) { echo Error: Could not move file into directory; exit; } ? Steve Jackson Web Developer Viola Systems Ltd. http://www.violasystems.com [EMAIL PROTECTED] Mobile +358 50 343 5159 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] help me please! :)
Hi, i must get the information saved in a several select list named liv_1 select name=liv_1 liv_2 select name=liv_2 liv_3 select name=liv_3 liv_n select name=liv_n To get the value i work in this way... $n = 50; for ($i=1; $i=$n;i++){ ... echo $liv_$i; in asp i do: response.write (request(liv_ + i)) ... } But i get only 1 2 3 ... 50 What can i do to get $liv_1 ... $liv_2... ??? Thank you a lot! Veronica Ghezzi -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] help me please! :)
You need to escape the dollar sign with a backslash to prevent PHP trying to interpolate the variable $liv (which presumably doesn't exist). echo \$liv_$i; HTH, - Kev -Original Message- From: Veronica Ghezzi [SMTP:[EMAIL PROTECTED]] Sent: 10 June 2002 09:24 To: Php-General Subject: [PHP] help me please! :) Hi, i must get the information saved in a several select list named liv_1 select name=liv_1 liv_2 select name=liv_2 liv_3 select name=liv_3 liv_n select name=liv_n To get the value i work in this way... $n = 50; for ($i=1; $i=$n;i++){ ... echo $liv_$i; in asp i do: response.write (request(liv_ + i)) ... } But i get only 1 2 3 ... 50 What can i do to get $liv_1 ... $liv_2... ??? Thank you a lot! Veronica Ghezzi -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php ** This email and any files transmitted with it are confidential and intended solely for the use of the individual or entity to whom they are addressed. If you have received this email in error please notify the system manager. This footnote also confirms that this email message has been swept by MIMEsweeper for the presence of computer viruses. ** -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] help me please! :)
?php $i = 1; $liv_1 = one; $liv_2 = two; $liv_3 = three; $liv_4 = four; $liv_5 = five; while ($i = 5 ) { $do = echo \$liv_{$i};; eval($do); echo br; $i ++; } ? Simply echoing the \$liv_$i will not work, need to evaluate the string after parsed as in example above... Kevin Porter wrote: You need to escape the dollar sign with a backslash to prevent PHP trying to interpolate the variable $liv (which presumably doesn't exist). echo \$liv_$i; HTH, - Kev -Original Message- From: Veronica Ghezzi [SMTP:[EMAIL PROTECTED]] Sent: 10 June 2002 09:24 To: Php-General Subject: [PHP] help me please! :) Hi, i must get the information saved in a several select list named liv_1 select name=liv_1 liv_2 select name=liv_2 liv_3 select name=liv_3 liv_n select name=liv_n To get the value i work in this way... $n = 50; for ($i=1; $i=$n;i++){ ... echo $liv_$i; in asp i do: response.write (request(liv_ + i)) ... } But i get only 1 2 3 ... 50 What can i do to get $liv_1 ... $liv_2... ??? Thank you a lot! Veronica Ghezzi -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php ** This email and any files transmitted with it are confidential and intended solely for the use of the individual or entity to whom they are addressed. If you have received this email in error please notify the system manager. This footnote also confirms that this email message has been swept by MIMEsweeper for the presence of computer viruses. ** -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] help me please! :)
Try: for ($i=1; $i=$n;i++){ ... $tmp=liv_$i; echo {$$tmp}; ... } Veronica Ghezzi wrote: Hi, i must get the information saved in a several select list named liv_1 select name=liv_1 liv_2 select name=liv_2 liv_3 select name=liv_3 liv_n select name=liv_n To get the value i work in this way... $n = 50; for ($i=1; $i=$n;i++){ ... echo $liv_$i; in asp i do: response.write (request(liv_ + i)) ... } But i get only 1 2 3 ... 50 What can i do to get $liv_1 ... $liv_2... ??? Thank you a lot! Veronica Ghezzi -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] help me please! :)
This work for me: liv_1select name=liv[1] liv_2select name=liv[2] liv_3select name=liv[3] liv_nselect name=liv[n] To get the value i work in this way... $liv= $_REQUEST['liv']; $n = 50; for ($i=1; $i=$n;i++){ ... echo $liv[$i]; Josep R. Raurell -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] Re:[PHP] HELP ME PLEASE: php not run on IIS 4.0
25/03/2002 8:27:51 PM hehehe You could start with loosing IIS, it's bad news. The port of Apache for windows is good, if not, Xitami's also quite good. http://www.apache.org/dist/httpd/binaries/win32/ http://www.xitami.com/ But, no, sorry. I can't help you. Berlina [EMAIL PROTECTED] wrote on 25/03/2002 10:19:46 AM: Hi, Im trying to install PHP 4.1.2 under Windows 2000 Server and IIS 4.0 * If I configure PHP as a MODULE, all run but SESSIONS DON'T WORK * If I configure PHP as a CGI, SESSIONS WORK but ORACLE MODULE for PHP not load Any ideas? Anybody can help me? Advanced thanks, Berli -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] HELP ME PLEASE: php not run on IIS 4.0
Hi, Im trying to install PHP 4.1.2 under Windows 2000 Server and IIS 4.0 * If I configure PHP as a MODULE, all run but SESSIONS DON'T WORK * If I configure PHP as a CGI, SESSIONS WORK but ORACLE MODULE for PHP not load Any ideas? Anybody can help me? Advanced thanks, Berli -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Help me please.(Running stand-alone php)
Tina, Thank you for the help Tina :-)) I getting a good experience working with PHP and HTML (forms). Because of my full time job and personal commitments, I haven't been able to spend as much of my free time as I could in my project (Free Gallery Management System). After October I hope to dedicate more of my free time on this project. The project will be open source and public domain. It will be developed with the help of PHP, a and PostgreSQL. More information about the project can be seen at the following web site: http://www.columbia.edu/~mv169/private/gallery_f.html Login Name: guest Password:guest If you have any comments, suggestions or if you want to participate, e-mail me at [EMAIL PROTECTED] Your input is very valuable to me. Adios, miguel --- Tina [EMAIL PROTECTED] wrote: The solution: You have to configure php with --enable-discard-path as in: ./configure --without-apache --enable-discard-path before you compile it. This is documented here: http://www.php.net/manual/en/security.php in the section: Case 4: PHP parser outside of web tree Now when you do !--#include virtual='php.cgi'-- the #!/path/to/php will not show at the top of the page. (The problem was indeed not local to windows). Tina. __ Do You Yahoo!? Make international calls for as low as $.04/minute with Yahoo! Messenger http://phonecard.yahoo.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] Help me please.(Running stand-alone php)
Unfortunately the -q parameter didn't fix the problem. Is anybody in the PHP mailing list that is familiar with this kind of problem and can tell me how to get rid of the path line in the browser output? Any help will be greatly appreciated. Thanks. --- mike cullerton [EMAIL PROTECTED] wrote: try the -q parameter. i'm guessing here, since i don't run windows nor the cgi version of php. :) on 8/7/01 8:27 AM, miguel valero at [EMAIL PROTECTED] wrote: Mike, I running the scrip from the browser (http://localhost/cgi-bin/test.html) When I comment the first line in the script (#-#!c:\php\php.exe) I get the following error message: Tue Aug 07 09:56:13 2001] [error] [client 127.0.0.1] c:/program files/apache group/apache/cgi-bin/test.php is not executable; ensure interpreted scripts have #! first line I can not run the script w/o the line #!c:\php\php.exe at the top of the script. How can I get rid of the path line on the browser output ? Thanks --- mike cullerton [EMAIL PROTECTED] wrote: i'm not sure i understand how you are running this... if it is a file you are running at the command line, try -q after the php.exe statement. if this is a web page, comment that line out. hope this helps, mike on 8/6/01 1:16 PM, miguel valero at [EMAIL PROTECTED] wrote: When I run the following script under an stand-alone php 4.0.6 and Apache 1.3 (Win95/98), the path to PHP (#!c:\php\php.exe) will show up on the first line of the browser output. #!c:\php\php.exe ?php phpinfo(); ? Is there a way to fix this? How can I get rid of the path line, on the top of the page, on the browser output? Any help will be greatly appreciated. My apologies if this has been covered before, or if this is in the manual, but I couldn't see it thanks. __ Do You Yahoo!? Make international calls for as low as $.04/minute with Yahoo! Messenger http://phonecard.yahoo.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Help me please.(Running stand-alone php)
Miguel, I see that your script has the extension .html Rename that file to .php and it normally should work. Greetz, Bjorn Van Simaeys www.bvsenterprises.com --- miguel valero [EMAIL PROTECTED] wrote: Unfortunately the -q parameter didn't fix the problem. Is anybody in the PHP mailing list that is familiar with this kind of problem and can tell me how to get rid of the path line in the browser output? Any help will be greatly appreciated. Thanks. --- mike cullerton [EMAIL PROTECTED] wrote: try the -q parameter. i'm guessing here, since i don't run windows nor the cgi version of php. :) on 8/7/01 8:27 AM, miguel valero at [EMAIL PROTECTED] wrote: Mike, I running the scrip from the browser (http://localhost/cgi-bin/test.html) When I comment the first line in the script (#-#!c:\php\php.exe) I get the following error message: Tue Aug 07 09:56:13 2001] [error] [client 127.0.0.1] c:/program files/apache group/apache/cgi-bin/test.php is not executable; ensure interpreted scripts have #! first line I can not run the script w/o the line #!c:\php\php.exe at the top of the script. How can I get rid of the path line on the browser output ? Thanks --- mike cullerton [EMAIL PROTECTED] wrote: i'm not sure i understand how you are running this... if it is a file you are running at the command line, try -q after the php.exe statement. if this is a web page, comment that line out. hope this helps, mike on 8/6/01 1:16 PM, miguel valero at [EMAIL PROTECTED] wrote: When I run the following script under an stand-alone php 4.0.6 and Apache 1.3 (Win95/98), the path to PHP (#!c:\php\php.exe) will show up on the first line of the browser output. #!c:\php\php.exe ?php phpinfo(); ? Is there a way to fix this? How can I get rid of the path line, on the top of the page, on the browser output? Any help will be greatly appreciated. My apologies if this has been covered before, or if this is in the manual, but I couldn't see it thanks. __ Do You Yahoo!? Make international calls for as low as $.04/minute with Yahoo! Messenger http://phonecard.yahoo.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED] __ Do You Yahoo!? Make international calls for as low as $.04/minute with Yahoo! Messenger http://phonecard.yahoo.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] Help me please.(Running stand-alone php)
The solution: You have to configure php with --enable-discard-path as in: ./configure --without-apache --enable-discard-path before you compile it. This is documented here: http://www.php.net/manual/en/security.php in the section: Case 4: PHP parser outside of web tree Now when you do !--#include virtual='php.cgi'-- the #!/path/to/php will not show at the top of the page. (The problem was indeed not local to windows). Tina. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] help me please :(
Hi :) Well, I have installed php on my Windows 98 machine. But i am unable to use the imap funcationality. I have the php_imap.dll in my php.ini file for which i have removed the semicolon (;extension = php_imap.dll) . But it dosent seem to work .I suppose i should have (php_imap4r2.dll ). Can anyone please send me a copy of the file if u have it please :) thanx in advance bye Nilesh -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]