Re: [PHP] imagesx(): supplied argument is not a valid Image resource (CODE)
Robert Sossomon wrote: > Chris is quoted as saying on 11/30/2004 2:53 PM: >> imagesx() requires an image resource , not a file path. so you'd need >> to use one of the imagecreatefrom* functions to create the resource. >> >> But it looks like all you want is the width and height of an image >> If so use get imagesize() ( which *does* except a pathname, not a >> resource) >> >> Chris >> >> http://www.php.net/image >> http://www.php.net/getimagesize > > I had looked at get image size, but thought the other would be quicker... > ARGH. imagesx() is probably quicker once you have loaded in the entire image to your GD resource... But assuming the image could be *HUGE* and that getimagesize only has to read the first N bytes to determine the size of the image, getimagesize will win any speed race for an otherwise un-opened image file, I should think. -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] imagesx(): supplied argument is not a valid Image resource (CODE)
Chris is quoted as saying on 11/30/2004 2:53 PM: imagesx() requires an image resource , not a file path. so you'd need to use one of the imagecreatefrom* functions to create the resource. But it looks like all you want is the width and height of an image If so use get imagesize() ( which *does* except a pathname, not a resource) Chris http://www.php.net/image http://www.php.net/getimagesize I had looked at get image size, but thought the other would be quicker... ARGH. $a=getimagesize($path); $width = $a[0]; $width = $width/2; $height = $a[1]; $height = $height/2; works!! -- Robert Sossomon, Business and Technology Application Technician 4-H Youth Development Department 200 Ricks Hall, Campus Box 7606 N.C. State University Raleigh NC 27695-7606 Phone: 919/515-8474 Fax: 919/515-7812 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] imagesx(): supplied argument is not a valid Image resource (CODE)
Robert Sossomon wrote: When I run it in the browser, I get: Fatal error: Call to undefined function: imagesx() in c:\fourh\spotlight3.php on line 31 when i run it from the command line I get: C:\fourh>php.exe spotlight3.php Content-type: text/html X-Powered-By: PHP/4.3.9 Warning: imagesx(): supplied argument is not a valid Image resource in < b>C:\fourh\spotlight3.php on line 31 Warning: imagesy(): supplied argument is not a valid Image resource in < b>C:\fourh\spotlight3.php on line 32 Doh, my bad. imagesx() requires the image resource, and not the path. As for the difference in browser vs. command line, it looks as if you've got multiple php.ini files. Do a phpinfo() in a browser, and it will show you where it's looking for the php.ini file. -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] imagesx(): supplied argument is not a valid Image resource (CODE)
imagesx() requires an image resource , not a file path. so you'd need
to use one of the imagecreatefrom* functions to create the resource.
But it looks like all you want is the width and height of an image
If so use get imagesize() ( which *does* except a pathname, not a resource)
Chris
http://www.php.net/image
http://www.php.net/getimagesize
Robert Sossomon wrote:
Here's the code for the page...
while ($file = readdir($handle))
{
for ($i = 0; $i < count($extensoes); $i++)
{
if (eregi("\.". $extensoes[$i] ."$", $file))
{
$array[] = $file;
}
}
}
closedir($handle);
sort($array);
reset($array);
// takes the objects in the array and randomizes them
$arrayobj = array_rand($array);
$random = $array[$arrayobj];
// this creates the path name to the random file
// $path becomes the path name (duh) for the file
$path = $dir . $random;
$width = imagesx($random)/4;
$height = imagesy($random)/4;
// this is set up as an tag and will show a random image
print "\n";
?>
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Re: [PHP] imagesx(): supplied argument is not a valid Image resource (CODE)
On Tue, 30 Nov 2004 14:43:51 -0500, Robert Sossomon <[EMAIL PROTECTED]> wrote: > Fatal error: Call to undefined function: imagesx() in c:\fourh\spotlight3.php > on > line 31 Do print_r( gd_info() ); to see if your PHP has support for working with images. -- Greg Donald Zend Certified Engineer http://gdconsultants.com/ http://destiney.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] imagesx(): supplied argument is not a valid Image resource (CODE)
John Nichel is quoted as saying on 11/30/2004 2:17 PM: $width = imagesx($path)/4; $height = imagesy($path)/4; $width = imagesx($path)/4; $height = imagesy($path)/4; When I run it in the browser, I get: Fatal error: Call to undefined function: imagesx() in c:\fourh\spotlight3.php on line 31 when i run it from the command line I get: C:\fourh>php.exe spotlight3.php Content-type: text/html X-Powered-By: PHP/4.3.9 Warning: imagesx(): supplied argument is not a valid Image resource in < b>C:\fourh\spotlight3.php on line 31 Warning: imagesy(): supplied argument is not a valid Image resource in < b>C:\fourh\spotlight3.php on line 32 -- Robert Sossomon, Business and Technology Application Technician 4-H Youth Development Department 200 Ricks Hall, Campus Box 7606 N.C. State University Raleigh NC 27695-7606 Phone: 919/515-8474 Fax: 919/515-7812 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] imagesx(): supplied argument is not a valid Image resource (CODE)
Robert Sossomon wrote: > // this is the path of your files folder. Change 'pathofile' > $dir = "images/"; I would make this the path from root, ie... $dir = "/root/path/images/"; // takes the objects in the array and randomizes them $arrayobj = array_rand($array); $random = $array[$arrayobj]; // this creates the path name to the random file // $path becomes the path name (duh) for the file $path = $dir . $random; $width = imagesx($random)/4; $height = imagesy($random)/4; You need to supply the path to the image...I'm betting you wanted to do... $width = imagesx($path)/4; $height = imagesy($path)/4; -- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 [EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP] imagesx(): supplied argument is not a valid Image resource (CODE)
Here's the code for the page...
while ($file = readdir($handle))
{
for ($i = 0; $i < count($extensoes); $i++)
{
if (eregi("\.". $extensoes[$i] ."$", $file))
{
$array[] = $file;
}
}
}
closedir($handle);
sort($array);
reset($array);
// takes the objects in the array and randomizes them
$arrayobj = array_rand($array);
$random = $array[$arrayobj];
// this creates the path name to the random file
// $path becomes the path name (duh) for the file
$path = $dir . $random;
$width = imagesx($random)/4;
$height = imagesy($random)/4;
// this is set up as an tag and will show a random image
print "\n";
?>
--
Robert Sossomon, Business and Technology Application Technician
4-H Youth Development Department
200 Ricks Hall, Campus Box 7606
N.C. State University
Raleigh NC 27695-7606
Phone: 919/515-8474
Fax: 919/515-7812
[EMAIL PROTECTED]
--
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To unsubscribe, visit: http://www.php.net/unsub.php
