Re: [PHP] printf and number_format rounding

2006-05-04 Thread Richard Lynch
On Wed, May 3, 2006 12:25 pm, Duffy, Scott E wrote:
 Are printf and number_format supposed to round?

   echo ($hcount-$lcount)/$hilow. ;
   echo number_format(($hcount-$lcount)/$hilow,2,'.','');


 0.208333 0.21
 0.145833 0.15
 0.17 0.17
 0.083 0.08
 Printf (%.2f,($hcount-$lcount)/$hilow);
 Does the same.

 It would appear to be. If there is a function to print just to the
 digit
 could you point me in the direction? So I would want 0.20  0.14   0.16
 0.08 respectively.

http://php.net/substring might do what you want.

You'll have to calculate the decimal point for yourself and work from
there.

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Re: [PHP] printf and number_format rounding

2006-05-04 Thread Barry

Richard Lynch schrieb:

On Wed, May 3, 2006 12:25 pm, Duffy, Scott E wrote:

Are printf and number_format supposed to round?

echo ($hcount-$lcount)/$hilow. ;
echo number_format(($hcount-$lcount)/$hilow,2,'.','');


0.208333 0.21
0.145833 0.15
0.17 0.17
0.083 0.08
Printf (%.2f,($hcount-$lcount)/$hilow);
Does the same.

It would appear to be. If there is a function to print just to the
digit
could you point me in the direction? So I would want 0.20  0.14   0.16
0.08 respectively.


http://php.net/substring might do what you want.

You'll have to calculate the decimal point for yourself and work from
there.


I use this function to add tax to a price.
Probably it will help you:

function addtax($price,$tax)
  {
bcscale(6);
$calc = bcmul(bcdiv($price,100,6),bcadd(100,$tax,6),6);
$output = bcadd (0,$calc,2);
$roundarray = explode (.,$calc);
if (substr($roundarray[1],2,1) = 5)
{
$output = $roundarray[0]+(substr($roundarray[1],0,2)/100)+0.01;
}
else $output = $roundarray[0]+(substr($roundarray[1],0,2)/100)+0.0;
return $output;
  }

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[PHP] printf and number_format rounding

2006-05-03 Thread Duffy, Scott E
Are printf and number_format supposed to round?

echo ($hcount-$lcount)/$hilow. ;
echo number_format(($hcount-$lcount)/$hilow,2,'.','');


0.208333 0.21 
0.145833 0.15 
0.17 0.17 
0.083 0.08
Printf (%.2f,($hcount-$lcount)/$hilow);
Does the same.

It would appear to be. If there is a function to print just to the digit
could you point me in the direction? So I would want 0.20  0.14   0.16
0.08 respectively.


Thank you,


Scott Duffy