[PHP] ptting the variable inside the input

[Hulf]

This does not work

echo $title=$row['title'];
echo trtdinput name=\title\ type=\text\ value=\$title\ //td;

Ta,

R. 

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RE: [PHP] ptting the variable inside the input

[Jay Blanchard]

[snip]
echo $title=$row['title'];
echo trtdinput name=\title\ type=\text\ value=\$title\
//td;
[/snip]

echo trtdinput name=\title\ type=\text\ value=\.$title.\
//td;

You have to concatenate the value $title into the string

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Re: [PHP] ptting the variable inside the input

[Stut]

Hulf wrote:

This does not work

echo $title=$row['title'];
echo trtdinput name=\title\ type=\text\ value=\$title\ //td;


In what way does it not work and you do realise you're outputting 
$title on its own as well as the table row and input. This will appear 
above the table in most browsers since it's not actually part of the table.


-Stut

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Re: [PHP] ptting the variable inside the input

[Stut]

Hulf wrote:

This does not work

echo $title=$row['title'];
echo trtdinput name=\title\ type=\text\ value=\$title\ //td;


In what way does it not work and you do realise you're outputting 
$title on its own as well as the table row and input. This will appear 
above the table in most browsers since it's not actually part of the table.


-Stut

--
http://stut.net/

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RE: [PHP] ptting the variable inside the input

[Jay Blanchard]

[snip]
 [snip]
echo $title=$row['title'];
echo trtdinput name=\title\ type=\text\ value=\$title\
//td;
[/snip]

echo trtdinput name=\title\ type=\text\ value=\.$title.\
//td;

You have to concatenate the value $title into the string
[/snip]

Actually don't have to do that, it was just one of the things that I
thought of right off the top of my head. What is the result of 

echo $title=$row['title'];

?

Actually, that is bad form, why do the transfer?

echo trtdinput name=\title\ type=\text\
value=\.$row['title'].\
//td;

If you must do the re-assignment;

$title = $row['title'];
echo $title;

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RE: [PHP] ptting the variable inside the input

[Instruct ICC]

From: Hulf [EMAIL PROTECTED]

This does not work

echo $title=$row['title'];
echo trtdinput name=\title\ type=\text\ value=\$title\ //td;

Ta,

R.


I'll pull a Johnny Carson divining moment and say:

Did you need the first 'echo'?  Does $title need to be set?  Try:
$title=$row['title'];

You missed a double quote after your backslash; the attempt to escape one 
after 'text' and before 'value':

echo trtdinput name=\title\ type=\text\ value=\$title\ //td;

Or perhaps use single quotes and don't set $title:
echo 'trtdinput name=title type=text value=' . $row['title'] . ' 
//td';


But I like that 4 step approach to addressing a problem and posting a 
question.


Maybe you are using a wireless keyboard which needs batteries or charging or 
needs to be placed closer to the receiver?  You also missed a character in 
your subject.  Unless you just type lazily.


_
Now you can see trouble…before he arrives 
http://newlivehotmail.com/?ocid=TXT_TAGHM_migration_HM_viral_protection_0507


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RE: [PHP] ptting the variable inside the input

[Jan Reiter]

Hi!

You don't have to end your string when placing an array value. {} will tell
the parser to interpret the text between as a variable. Try:

echo trtdinput name=\title\ type=\text\ value=\{$row['title']}\
//td;

Jan

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