RE: [PHP] Combo box selected value...

2002-06-07 Thread Bruce Karstedt 

Sounds like you are working on a windows box with a bad battery back up for
the clock!

Bruce Karstedt
President
Technology Consulting Associates, Ltd.
Tel: 847-735-9488
Fax: 847-735-9474


-Original Message-
From: Miguel Cruz [mailto:[EMAIL PROTECTED]]
Sent: Thursday, June 06, 2002 4:01 PM
To: Alexandra Aguiar
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Combo box selected value...


On Fri, 4 Jan 1980, Alexandra Aguiar wrote:
> I got the followin code to generate a combo box...

Your clock is off by about 20 years. Is it possible to fix it before
posting to the list? Thanks.

miguel


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Re: [PHP] Combo box selected value...

2002-06-06 Thread Miguel Cruz 

On Fri, 4 Jan 1980, Alexandra Aguiar wrote:
> I got the followin code to generate a combo box...

Your clock is off by about 20 years. Is it possible to fix it before 
posting to the list? Thanks.

miguel


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Re: [PHP] Combo box selected value...

2002-06-06 Thread Rick Emery 

The value is returned in whatever is stored in $nome.  So, if $nome="var", then $var 
will contain the selected value.

Second, this could not possibly operate the way you want it to, because the 
mysql_result() is called TWICE with each line.  You want it called only ONCE to 
retrieve the value for the VALUE parameter and the value displayed.

- Original Message - 
From: "Alexandra Aguiar" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, January 04, 1980 12:56 PM
Subject: [PHP] Combo box selected value...


Hi ppl...


I got the followin code to generate a combo box...

++
function comb_alfabeto( $resultado, $nome, $letra)
   {
  global $error;  
$quant = mysql_num_rows($resultado);
If ($quant == 0)
  {
   $error->erro();
  }
   Else
{
 //>> Início da combbox
$cont=0;
echo('   
'.mysql_result($resultado, $cont,$letra).'');  
   $cont++;
}
echo("\n  ");
  }
   }

+++

But, how can i return the selected item value into a variable $var ???


thnx in advance...

Alexandra

Re: [PHP] Combo box selected value...

2002-06-06 Thread Rick Emery 

the value is returned in whatever is stored in $nome.  So, if $nome="var", then $var 
will contain the selected value.

- Original Message - 
From: "Alexandra Aguiar" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, January 04, 1980 12:56 PM
Subject: [PHP] Combo box selected value...


Hi ppl...


I got the followin code to generate a combo box...

++
function comb_alfabeto( $resultado, $nome, $letra)
   {
  global $error;  
$quant = mysql_num_rows($resultado);
If ($quant == 0)
  {
   $error->erro();
  }
   Else
{
 //>> Início da combbox
$cont=0;
echo('   
'.mysql_result($resultado, $cont,$letra).'');  
   $cont++;
}
echo("\n  ");
  }
   }

+++

But, how can i return the selected item value into a variable $var ???


thnx in advance...

Alexandra

Re: [PHP] Combo box selected value...

2002-06-06 Thread Chris Knipe 

'.mysql_result($resultado,
$cont,$letra).'');
   } else {
 echo(' '.mysql_result($resultado, $cont,$letra).'');
   }


   $cont++;
}
echo("\n  ");
  }
   }

+++

> But, how can i return the selected item value into a variable $var ???

That's normally how I do it...  I'm not to sure on which values you need to
do the comparison... It depends on what data you are returning from mysql I
think


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