Re: [PHP] Like ternary but without the else.
This should do the trick:
$something ? $this=$that
-justin
On Fri, 25 Feb 2005 10:36:36 -0800, Chris W. Parker
[EMAIL PROTECTED] wrote:
Hello,
I couldn't find this anywhere on google or PHP's site but I'm pretty
sure there's an answer to it.
How can I turn the following into something that resembles the ternary
operator?
?php
if($something)
{
$this = $that;
}
?
I seem to remember it looking something like:
?php
$this = ($something) || $that;
?
Although this isn't syntactically wrong, i.e. no errors, it did not do
what I hoped it would do. (What it does is assign 1/true.)
Thanks!
Chris.
p.s. No need to respond if your suggestion is:
?php
if($something) { $this = $that; }
?
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Justin Lilly
University of South Carolina
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Re: [PHP] Like ternary but without the else.
On Fri, 2005-02-25 at 13:36, Chris W. Parker wrote:
How can I turn the following into something that resembles the ternary
operator?
?php
if($something)
{
$this = $that;
}
?
$this = (isset($something)) ? $something : $that;
The expression (expr1) ? (expr2) : (expr3) evaluates to expr2 if expr1
evaluates to TRUE, and expr3 if expr1 evaluates to FALSE.
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RE: [PHP] Like ternary but without the else.
I couldn't find this anywhere on google or PHP's site but I'm pretty sure
there's an answer to it.
How can I turn the following into something that resembles the ternary
operator?
?php
if($something)
{
$this = $that;
}
?
is this what you're after?
$this = ($something ? $that : $this)
rich
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Re: [PHP] Like ternary but without the else.
Chris W. Parker wrote:
Hello,
I couldn't find this anywhere on google or PHP's site but I'm pretty
sure there's an answer to it.
How can I turn the following into something that resembles the ternary
operator?
write an extension to the php engine? don't think it exists.
?php
if($something)
{
$this = $that;
}
just do:
if ($something) $this = $that;
..personally I don't like braceless if statements.
?
or one of these might work for you;
$this = ($something) ? $that: $this; // if $this already exists.
or
$this = ($something) ? $that: null; // if $this does not exist and your happy
to use is_null()
I seem to remember it looking something like:
?php
$this = ($something) || $that;
?
btw your not using 'this' as an actual variable name are you?
(unless its on purpose for doing bad(tm) things in php4 :-)
Although this isn't syntactically wrong, i.e. no errors, it did not do
what I hoped it would do. (What it does is assign 1/true.)
what it does is assign the result of the expression (($something) _or_
$that)
to $this.
if either of those equate to true (dont forget php autotypecasts),
then the expression is true, its a boolean 'or' so it will always make
$this a boolean, which print as:
php -r 'echo true;' // echos 1
php -r 'echo false;'// echos ''
Thanks!
Chris.
p.s. No need to respond if your suggestion is:
?php
if($something) { $this = $that; }
?
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RE: [PHP] Like ternary but without the else.
Jochem Maas mailto:[EMAIL PROTECTED]
on Friday, February 25, 2005 4:04 PM said:
just do:
if ($something) $this = $that;
Thanks!
Chris.
p.s. No need to respond if your suggestion is:
?php
if($something) { $this = $that; }
?
:)
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RE: [PHP] Like ternary but without the else.
Justin Lilly mailto:[EMAIL PROTECTED] on Friday, February 25, 2005 3:10 PM said: This should do the trick: $something ? $this=$that Actually that gives a synax error. But I've figured it out based on your suggestion. It's actually: ?php $something $this = $that; ? Chris. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Like ternary but without the else.
On Fri, 25 Feb 2005 18:39:56 -0500, Brian V Bonini [EMAIL PROTECTED] wrote:
On Fri, 2005-02-25 at 13:36, Chris W. Parker wrote:
How can I turn the following into something that resembles the ternary
operator?
?php
if($something)
{
$this = $that;
}
?
$this = (isset($something)) ? $something : $that;
The expression (expr1) ? (expr2) : (expr3) evaluates to expr2 if expr1
evaluates to TRUE, and expr3 if expr1 evaluates to FALSE.
--
s/:-[(/]/:-)/g
BrianGnuPG - KeyID: 0x04A4F0DC | Key Server: pgp.mit.edu
==
gpg --keyserver pgp.mit.edu --recv-keys 04A4F0DC
Key Info: http://gfx-design.com/keys
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What the user actually requested is the following method, fairly used
in bash scripting.
($a == $b) $a = 'asdasd';
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