RE: [PHP] Php/mysql error....why?

2003-10-24 Thread Dan Joseph 
> `%0123456789%'";

You have a ` instead a ' before the %0123.  I believe that is what is
causing your grief.

-Dan Joseph

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Re: [PHP] Php/mysql error....why?

2003-10-24 Thread Tom Rogers 
Hi,

Saturday, October 25, 2003, 2:50:46 AM, you wrote:
RA> Hi,
RA> I am running a very simple query to the database, basically select all the
RA> firms which start with 0-9,
RA> eg.
RA> 1stcompany
RA> 3isgood
RA> etc

RA> using this:
RA> $qry = "select cust_no,firm from companies where firm LIKE `%0123456789%'";

RA> It gives me this error:

RA> Error: Unknown column '0123456789%'' in 'where clause'

RA> any idea why its ignoring the LIKE statement? the funny part is LIKE is
RA> working for another program..

RA> What am i missing?

RA> Thanks,
RA> -Ryan


You have a backtick instead of a quote (`%)

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regards,
Tom

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