Re: [PHP] Str_Replace Command
On Tuesday 03 February 2004 00:14, Christopher J. Crane wrote: $StockURL = http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;; $StockResults = implode('', file($StockURL)); $Rows = split(\n, $StockResults); foreach($Rows as $Row) { echo str_replace('',,$Row).br\n; } foreach($Rows as $Row) { str_replace('',,$Row); echo $Row.br\n; } str_replace() RETURNS the replaced string. It does not alter $Row. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* Spiritual leadership should remain spiritual leadership and the temporal power should not become too important in any church. - Eleanor Roosevelt */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Str_Replace Command
Ok I got around it by the following, but now I have a new problem. I can not get the two dimensional array working. I want to later be able to output a variable like this $TickerData[IKN] and it will output the associated $Price. $StockURL = http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;; $StockResults = implode('', file($StockURL)); $Rows = split(\n, $StockResults); foreach($Rows as $Row) { list($Symbol, $Price) = split(,, $Row); $Symbol = str_replace('', , $Symbol); $TickerData = array($Symbol=$Ticker); } print_r($TickerData); echo $TickerData[IKN].br\n; Jason Wong [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] On Tuesday 03 February 2004 00:14, Christopher J. Crane wrote: $StockURL = http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;; $StockResults = implode('', file($StockURL)); $Rows = split(\n, $StockResults); foreach($Rows as $Row) { echo str_replace('',,$Row).br\n; } foreach($Rows as $Row) { str_replace('',,$Row); echo $Row.br\n; } str_replace() RETURNS the replaced string. It does not alter $Row. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* Spiritual leadership should remain spiritual leadership and the temporal power should not become too important in any church. - Eleanor Roosevelt */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Str_Replace Command
On Tuesday 03 February 2004 00:52, Christopher J. Crane wrote: Ok I got around it by the following, but now I have a new problem. I can not get the two dimensional array working. I want to later be able to output a variable like this $TickerData[IKN] and it will output the associated $Price. print_r($TickerData); So what does the above show? If it isn't what you expect, figure out *why*. Like how is $TickerData being assigned. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* We have phasers, I vote we blast 'em! -- Bailey, The Corbomite Maneuver, stardate 1514.2 */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Str_Replace Command
Well this is it and it is really got me... Echoing out the $Symbol and $Price works just fine one row about the $TickerData array assignment. Yet it outputs nothing. Array ( [] = ) is what I get. If I change the line to $TickerData = array ($Symbol = $Price); I get nothing, or the same result. If I change the line to $TickerData = array ('$Symbo'l = '$Price'); I get the following Array ( [$Symbol] = $Price ) which tells me the assignment works, but it seems like the $Symbol and $Price variable are blank when assigning to the array. I know that they are not blank since they echoed out just fine one line above.GRR $StockURL = http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;; $StockResults = implode('', file($StockURL)); $Rows = split(\n, $StockResults); foreach($Rows as $Row) { list($Symbol, $Price) = split(,, $Row); $Symbol = str_replace('', , $Symbol); echo $Symbol. - .$Price.br\n; $TickerData = array ($Symbol = $Price); } print_r($TickerData); Jason Wong [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] On Tuesday 03 February 2004 00:52, Christopher J. Crane wrote: Ok I got around it by the following, but now I have a new problem. I can not get the two dimensional array working. I want to later be able to output a variable like this $TickerData[IKN] and it will output the associated $Price. print_r($TickerData); So what does the above show? If it isn't what you expect, figure out *why*. Like how is $TickerData being assigned. -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* We have phasers, I vote we blast 'em! -- Bailey, The Corbomite Maneuver, stardate 1514.2 */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Str_Replace Command
On Tuesday 03 February 2004 01:09, Christopher J. Crane wrote: Well this is it and it is really got me... Echoing out the $Symbol and $Price works just fine one row about the $TickerData array assignment. Yet it outputs nothing. Array ( [] = ) is what I get. If I change the line to $TickerData = array ($Symbol = $Price); I get nothing, or the same result. If I change the line to $TickerData = array ('$Symbo'l = '$Price'); I get the following Array ( [$Symbol] = $Price ) which tells me the assignment works, but it seems like the $Symbol and $Price variable are blank when assigning to the array. I know that they are not blank since they echoed out just fine one line above.GRR Are you sure that the line: echo $Symbol ... is displaying something sensible for each $Row? You're overwriting $TickerData at each iteration of the foreach-loop thus if your last $Row doesn't contain something sensible neither would $TickerData. You probably want to use this assignment instead: $TickerData[$Symbol] = $Price; -- Jason Wong - Gremlins Associates - www.gremlins.biz Open Source Software Systems Integrators * Web Design Hosting * Internet Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* TANSTAAFL */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Str_Replace Command
snip $StockURL = http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;; $StockResults = implode('', file($StockURL)); $Rows = split(\n, $StockResults); foreach($Rows as $Row) { list($Symbol, $Price) = split(,, $Row); $Symbol = str_replace('', , $Symbol); echo $Symbol. - .$Price.br\n; $TickerData = array ($Symbol = $Price); } print_r($TickerData); /snip why not replace: $TickerData = array ($Symbol = $Price); that line reassigns $TickerData to a array with one element in it everytime you call it. The last time through your loop, $Symbol = '' and $Price = '', so you get Array ( [] = ) when you print_r with this: $TickerData[$Symbol] = $Price; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Str_Replace Command
Matt: This worked perfect. Thank you. I didn't realize it was reassigning, I thought it would work similar to array_push and add to the existing data. I get it now, thanks to you. Thanks again. I had been so frustrated I was losing my objectivity. Christopher J. Crane Network Manager - Infrastructure Services IKON Document Efficiency at Work -Original Message- From: Matt Matijevich [mailto:[EMAIL PROTECTED] Sent: Monday, February 02, 2004 12:25 PM To: [EMAIL PROTECTED]; [EMAIL PROTECTED] Subject: Re: [PHP] Str_Replace Command snip $StockURL = http://finance.yahoo.com/d/quotes.txt?s=xrx,ikn,dankyf=sl1e=.txt;; $StockResults = implode('', file($StockURL)); $Rows = split(\n, $StockResults); foreach($Rows as $Row) { list($Symbol, $Price) = split(,, $Row); $Symbol = str_replace('', , $Symbol); echo $Symbol. - .$Price.br\n; $TickerData = array ($Symbol = $Price); } print_r($TickerData); /snip why not replace: $TickerData = array ($Symbol = $Price); that line reassigns $TickerData to a array with one element in it everytime you call it. The last time through your loop, $Symbol = '' and $Price = '', so you get Array ( [] = ) when you print_r with this: $TickerData[$Symbol] = $Price; -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php