Re: [PHP] Strange error on mysql_fetch_array
How can the resource be invalid if I'm getting the results back? I'd
appreciate any explaination.
What results are you getting?...
$connection_id = @mysql_connect ('localhost', 'root') or die('No
connection.');
$database_id = @mysql_select_db ('cgcms', $connection_id) or die('No
connection.');
...
$result_id = @mysql_query(DESC $table_name $field_name);
I don't think DESC $table_name $field_name is valid SQL, is it?...
DESC is DESCENDING in an ORDER BY clause...
Perhaps if you used DESCRIBE?... Is that what you are doing?...
There are built-in functions for getting the table definitions and so forth.
They may work better...
$row = mysql_fetch_array($result_id); # This is line 9
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Re: [PHP] Strange error on mysql_fetch_array
In article 046401c0fee3$a6c789e0$6401a8c0@Lynchux100,
[EMAIL PROTECTED] (Richard Lynch) wrote:
$result_id = @mysql_query(DESC $table_name $field_name);
I don't think DESC $table_name $field_name is valid SQL, is it?...
DESC is DESCENDING in an ORDER BY clause...
Perhaps if you used DESCRIBE?... Is that what you are doing?...
DESC {table name} [{field name}] is a valid expression in MySQL. It's a
synonym for the DESCRIBE keyword. Though the query could still be failing
for any number of reasons (invalid table name, invalid field name, older
version of MySQL that doesn't support that syntax, etc.).
Throw in die(), mysql_error(), $php_errormsg; turn down error_reporting,
and/or turn off display_errors...anything but using the @ sign by itself (a
surefire way to never clue in to much stuff is silently going wrong).
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Re: [PHP] Strange error on mysql_fetch_array
dunno
but my it's just failing at the mysql_connect()
shouldn't you specify the password too?
[EMAIL PROTECTED] wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
The following code fragment works properly, in that I get the output I'm
expecting. However, if I don't disable error messages with @, I get an
error message from PHP saying: Warning: Supplied argument is not a valid
MySQL result resource in /var/www/htdocs/cgcm/test2.php on line 9.
How can the resource be invalid if I'm getting the results back? I'd
appreciate any explaination.
$connection_id = @mysql_connect ('localhost', 'root') or die('No
connection.');
$database_id = @mysql_select_db ('cgcms', $connection_id) or die('No
connection.');
...
$result_id = @mysql_query(DESC $table_name $field_name);
$row = mysql_fetch_array($result_id); # This is line 9
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Todd A. Jacobs
CodeGnome Consulting, LTD
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Re: [PHP] Strange error on mysql_fetch_array
On Wed, 27 Jun 2001 06:31, [EMAIL PROTECTED] wrote:
The following code fragment works properly, in that I get the output
I'm expecting. However, if I don't disable error messages with @, I get
an error message from PHP saying: Warning: Supplied argument is not a
valid MySQL result resource in /var/www/htdocs/cgcm/test2.php on line
9.
How can the resource be invalid if I'm getting the results back? I'd
appreciate any explaination.
$connection_id = @mysql_connect ('localhost', 'root') or die('No
connection.');
$database_id = @mysql_select_db ('cgcms', $connection_id) or
die('No connection.');
...
$result_id = @mysql_query(DESC $table_name $field_name);
$row = mysql_fetch_array($result_id); # This is line 9
Try using mysql_error() to see if there is some feedback from mysql. Put
it just after your mysql_query().
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CENTRE FOR INJURY STUDIES Flinders University, SOUTH AUSTRALIA
Common sense isn't...
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Re: [PHP] Strange error on mysql_fetch_array
- Original Message -
From: David Robley [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; PHP General [EMAIL PROTECTED]
Sent: Wednesday, June 27, 2001 8:47 AM
Subject: Re: [PHP] Strange error on mysql_fetch_array
On Wed, 27 Jun 2001 06:31, [EMAIL PROTECTED] wrote:
The following code fragment works properly, in that I get the output
I'm expecting. However, if I don't disable error messages with @, I get
an error message from PHP saying: Warning: Supplied argument is not a
valid MySQL result resource in /var/www/htdocs/cgcm/test2.php on line
9.
How can the resource be invalid if I'm getting the results back? I'd
appreciate any explaination.
$connection_id = @mysql_connect ('localhost', 'root') or die('No
connection.');
$database_id = @mysql_select_db ('cgcms', $connection_id) or
die('No connection.');
...
$result_id = @mysql_query(DESC $table_name $field_name);
$row = mysql_fetch_array($result_id); # This is line 9
Try using mysql_error() to see if there is some feedback from mysql. Put
it just after your mysql_query().
--
David Robley Techno-JoaT, Web Maintainer, Mail List Admin, etc
CENTRE FOR INJURY STUDIES Flinders University, SOUTH AUSTRALIA
Common sense isn't...
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Hmm, maybe the prefix '@' suppresses the returning link-identifier. Just a
suggestion!
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RE: [PHP] Strange error on mysql_fetch_array
From experience with oracle, desc only works in an sql prompt, not through
code. So use the more lengthy method
in mysql:
SHOW FIELDS FROM $table_name
in oracle:
SELECT c.column_name, c.data_type, c.data_length, c.data_precision,
c.data_scale, c.nullable FROM sys.dba_tab_columns c WHERE c.owner = '$owner'
AND c.table_name = '$table_name'
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-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 26, 2001 2:01 PM
To: PHP General
Subject: [PHP] Strange error on mysql_fetch_array
The following code fragment works properly, in that I get the output I'm
expecting. However, if I don't disable error messages with @, I get an
error message from PHP saying: Warning: Supplied argument is not a valid
MySQL result resource in /var/www/htdocs/cgcm/test2.php on line 9.
How can the resource be invalid if I'm getting the results back? I'd
appreciate any explaination.
$connection_id = @mysql_connect ('localhost', 'root') or die('No
connection.');
$database_id = @mysql_select_db ('cgcms', $connection_id) or die('No
connection.');
...
$result_id = @mysql_query(DESC $table_name $field_name);
$row = mysql_fetch_array($result_id); # This is line 9
--
Todd A. Jacobs
CodeGnome Consulting, LTD
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