RE: [PHP] Which file called the function?
On Thu, December 20, 2007 1:54 pm, George Pitcher wrote:
I have a functions file with over 400 functions (and that may be too
many -
but it works). I've been adding some error reporting in to my PEAR::DB
queries, but wanted to know which page triggered the function. I went
theough my php pages and gane each one a $pg variable at the start
containing the bare name of the file, eg 'home' rather than
'home.php'. I
then went to each function containing either a DB query (ore one which
calls
another DB-related function. I did a global search and replace for the
function name 'func(' replaced by 'func($pg,'. I use Dreamweaver so
this was
fairly straightforward.
It worked for me, but now someone is about to show me a quicker,
cleaner
way, aren't they?
FIRST LINES OF CODE:
?php
function error_handler($code, $message, $file, $line, $context){
die(ERROR: $message ($code) in $file:$line);
}
set_error_handler('error_handler');
?
Anywhere else in your code:
[examples]
$connection = mysql_connect(...) or trigger_error(No DB access.,
E_USER_ERROR);
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Re: [PHP] Which file called the function?
On Dec 20, 2007 7:06 PM, Robert Cummings [EMAIL PROTECTED] wrote:
On Thu, 2007-12-20 at 19:54 +, George Pitcher wrote:
On Thu, December 20, 2007 8:37 am, Christoph Boget wrote:
Let's say I have the following 3 files
global.php
?
function myFunc() { echo __FILE__; }
?
one.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
two.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
In each case, what is echoed out for __FILE__ is global.php. Apart
from
analyzing the debug_backtrace array, is there any way that myFunc()
would
display one.php and two.php respectively?
$_SERVER['PHP_SELF'] and other bits in $_SERVER have the main PHP
filename in them.
__FILE__ will always be exactly the file that it's in.
In between, I think you are stuck with the debug_backtrace.
NOTE:
If it's for error logging or error reporting, note that trigger_error
automatically passes in the file/line to the error handler.
I'm far from being an expert, and often see more efficient ways of doing
things (more efficient tham my own methods). Howevr, I've just been
dealing
with a similar problem.
I have a functions file with over 400 functions (and that may be too
many -
but it works). I've been adding some error reporting in to my PEAR::DB
queries, but wanted to know which page triggered the function. I went
theough my php pages and gane each one a $pg variable at the start
containing the bare name of the file, eg 'home' rather than 'home.php'.
I
then went to each function containing either a DB query (ore one which
calls
another DB-related function. I did a global search and replace for the
function name 'func(' replaced by 'func($pg,'. I use Dreamweaver so this
was
fairly straightforward.
It worked for me, but now someone is about to show me a quicker, cleaner
way, aren't they?
Yes, I am.
?php
function checkpoint()
{
$trace = debug_backtrace();
$caller = isset( $trace[0] ) ? $trace[0] : array();
$owner = isset( $trace[1] ) ? $trace[1] : array();
$file
= isset( $caller['file'] )
? $caller['file']
: null;
$class
= isset( $owner['class'] )
? $owner['class']
: null;
$function
= isset( $owner['function'] )
? $owner['function']
: null;
$line
= isset( $caller['line'] )
? $caller['line']
: null;
$type
= isset( $owner['type'] )
? $owner['type']
: null;
list( $timeSub, $time ) = explode( ' ', microtime() );
$timeSub = ereg_replace( '^[^.]\.', '', $timeSub );
$timeSub = substr( str_pad( $timeSub, 6, '0' ), 0, 6 );
echo 'Checkpoint '
.'['.date( 'Y-m-d H:i:s', $time ).'.'.$timeSub.']: '
.($file === null
? ''
: $file.' ')
.($line === null
? ''
: sprintf( '{%05d} ', $line ))
.($class === null
? ''
: $class.$type)
.($function === null
? ''
: $function.'()')
.$this-nl;
}
?
incidentally, i was looking through Pear::Log today;
i stumbled upon this and thought id share:
/**
* Using debug_backtrace(), returns the file, line, and enclosing
function
* name of the source code context from which log() was invoked.
*
* @param int $depth The initial number of frames we should step
* back into the trace.
*
* @return array Array containing three strings: the filename, the
line,
* and the function name from which log() was called.
*
* @access private
* @since Log 1.9.4
*/
function _getBacktraceVars($depth)
{
/* Start by generating a backtrace from the current call (here). */
$backtrace = debug_backtrace();
/*
* If we were ultimately invoked by the composite handler, we need
to
* increase our depth one additional level to compensate.
*/
if (strcasecmp(@$backtrace[$depth+1]['class'], 'Log_composite') ==
0) {
$depth++;
}
/*
* We're interested in the frame which invoked the log() function,
so
* we need to walk back some number of frames into the backtrace.
The
* $depth parameter tells us where to start looking. We go one
step
* further back to find the name of the encapsulating function from
* which log() was called.
*/
$file = @$backtrace[$depth]['file'];
$line = @$backtrace[$depth]['line'];
$func = @$backtrace[$depth + 1]['function'];
/*
RE: [PHP] Which file called the function?
__FILE__ == global.php
On 20/12/2007, Christoph Boget [EMAIL PROTECTED] wrote:
Let's say I have the following 3 files
global.php
?
function myFunc() { echo __FILE__; }
?
one.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
two.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
In each case, what is echoed out for __FILE__ is global.php. Apart from
analyzing the debug_backtrace array, is there any way that myFunc() would
display one.php and two.php respectively?
thnx,
Christoph
--
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Cesar D. Rodas
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http://www.thyphp.com
http://www.phpajax.org
Phone: +595-961-974165
Re: [PHP] Which file called the function?
I believe __FILE__ is resolved at compile time, not run-time which means what you're seeing is expected behavior. I'm not sure how you'd get the name of the file that a function call was made from. Could you explain why you need this information in your application, and perhaps someone might offer an alternative solution? I'm not saying it's not expected behavior. In fact, that exactly what I would expect based on what the docs say. I'm just asking if there is another way to get the script file name that's calling the function. I need it primarily for debugging purposes. I've got a single function that's called by several files. And instead of modifying all the files calling the function to add logging, it would be nice to just modify the function, adding logging only to it to also include what script called it. I know I can get the information from debug_backtrace but I figured there might be a better/easier way. thnx, Christoph Looking for last minute shopping deals? Find them fast with Yahoo! Search. http://tools.search.yahoo.com/newsearch/category.php?category=shopping -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Which file called the function?
Christoph Boget wrote: I believe __FILE__ is resolved at compile time, not run-time which means what you're seeing is expected behavior. I'm not sure how you'd get the name of the file that a function call was made from. Could you explain why you need this information in your application, and perhaps someone might offer an alternative solution? I'm not saying it's not expected behavior. In fact, that exactly what I would expect based on what the docs say. I'm just asking if there is another way to get the script file name that's calling the function. I need it primarily for debugging purposes. I've got a single function that's called by several files. And instead of modifying all the files calling the function to add logging, it would be nice to just modify the function, adding logging only to it to also include what script called it. I know I can get the information from debug_backtrace but I figured there might be a better/easier way. There isn't. The backtrace is the only thing that can get the call stack. -Stut -- http://stut.net/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Which file called the function?
Christoph Boget schreef: I believe __FILE__ is resolved at compile time, not run-time which means what you're seeing is expected behavior. I'm not sure how you'd get the name of the file that a function call was made from. Could you explain why you need this information in your application, and perhaps someone might offer an alternative solution? I'm not saying it's not expected behavior. In fact, that exactly what I would expect based on what the docs say. I'm just asking if there is another way to get the script file name that's calling the function. I need it primarily for debugging purposes. I've got a single function that's called by several files. And instead of modifying all the files calling the function to add logging, it would be nice to just modify the function, adding logging only to it to also include what script called it. I know I can get the information from debug_backtrace but I figured there might be a better/easier way. nope, debug_backtrace() is the way to go. thnx, Christoph Looking for last minute shopping deals? Find them fast with Yahoo! Search. http://tools.search.yahoo.com/newsearch/category.php?category=shopping -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Which file called the function?
On Dec 20, 2007 9:47 AM, Christoph Boget [EMAIL PROTECTED] wrote: [snip!] I need it primarily for debugging purposes. I've got a single function that's called by several files. And instead of modifying all the files calling the function to add logging, it would be nice to just modify the function, adding logging only to it to also include what script called it. I know I can get the information from debug_backtrace but I figured there might be a better/easier way. You probably want http://www.xdebug.org/. -- Daniel P. Brown [Phone Numbers Go Here!] [They're Hidden From View!] If at first you don't succeed, stick to what you know best so that you can make enough money to pay someone else to do it for you. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Which file called the function?
On 20 Dec 2007, at 14:37, Christoph Boget wrote:
Let's say I have the following 3 files
global.php
?
function myFunc() { echo __FILE__; }
?
one.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
two.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
In each case, what is echoed out for __FILE__ is global.php. Apart
from
analyzing the debug_backtrace array, is there any way that myFunc()
would
display one.php and two.php respectively?
thnx,
Christoph
Hi Christoph,
I believe __FILE__ is resolved at compile time, not run-time which
means what you're seeing is expected behavior. I'm not sure how you'd
get the name of the file that a function call was made from.
Could you explain why you need this information in your application,
and perhaps someone might offer an alternative solution?
Regards,
Nilesh
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Re: [PHP] Which file called the function?
On Thu, December 20, 2007 8:37 am, Christoph Boget wrote:
Let's say I have the following 3 files
global.php
?
function myFunc() { echo __FILE__; }
?
one.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
two.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
In each case, what is echoed out for __FILE__ is global.php. Apart
from
analyzing the debug_backtrace array, is there any way that myFunc()
would
display one.php and two.php respectively?
$_SERVER['PHP_SELF'] and other bits in $_SERVER have the main PHP
filename in them.
__FILE__ will always be exactly the file that it's in.
In between, I think you are stuck with the debug_backtrace.
NOTE:
If it's for error logging or error reporting, note that trigger_error
automatically passes in the file/line to the error handler.
--
Some people have a gift link here.
Know what I want?
I want you to buy a CD from some indie artist.
http://cdbaby.com/from/lynch
Yeah, I get a buck. So?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Which file called the function?
On Thu, December 20, 2007 8:37 am, Christoph Boget wrote:
Let's say I have the following 3 files
global.php
?
function myFunc() { echo __FILE__; }
?
one.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
two.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
In each case, what is echoed out for __FILE__ is global.php. Apart
from
analyzing the debug_backtrace array, is there any way that myFunc()
would
display one.php and two.php respectively?
$_SERVER['PHP_SELF'] and other bits in $_SERVER have the main PHP
filename in them.
__FILE__ will always be exactly the file that it's in.
In between, I think you are stuck with the debug_backtrace.
NOTE:
If it's for error logging or error reporting, note that trigger_error
automatically passes in the file/line to the error handler.
I'm far from being an expert, and often see more efficient ways of doing
things (more efficient tham my own methods). Howevr, I've just been dealing
with a similar problem.
I have a functions file with over 400 functions (and that may be too many -
but it works). I've been adding some error reporting in to my PEAR::DB
queries, but wanted to know which page triggered the function. I went
theough my php pages and gane each one a $pg variable at the start
containing the bare name of the file, eg 'home' rather than 'home.php'. I
then went to each function containing either a DB query (ore one which calls
another DB-related function. I did a global search and replace for the
function name 'func(' replaced by 'func($pg,'. I use Dreamweaver so this was
fairly straightforward.
It worked for me, but now someone is about to show me a quicker, cleaner
way, aren't they?
Cheers, and seasonal greetings from Oxford/Edinburgh
George
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RE: [PHP] Which file called the function?
On Thu, 2007-12-20 at 19:54 +, George Pitcher wrote:
On Thu, December 20, 2007 8:37 am, Christoph Boget wrote:
Let's say I have the following 3 files
global.php
?
function myFunc() { echo __FILE__; }
?
one.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
two.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
In each case, what is echoed out for __FILE__ is global.php. Apart
from
analyzing the debug_backtrace array, is there any way that myFunc()
would
display one.php and two.php respectively?
$_SERVER['PHP_SELF'] and other bits in $_SERVER have the main PHP
filename in them.
__FILE__ will always be exactly the file that it's in.
In between, I think you are stuck with the debug_backtrace.
NOTE:
If it's for error logging or error reporting, note that trigger_error
automatically passes in the file/line to the error handler.
I'm far from being an expert, and often see more efficient ways of doing
things (more efficient tham my own methods). Howevr, I've just been dealing
with a similar problem.
I have a functions file with over 400 functions (and that may be too many -
but it works). I've been adding some error reporting in to my PEAR::DB
queries, but wanted to know which page triggered the function. I went
theough my php pages and gane each one a $pg variable at the start
containing the bare name of the file, eg 'home' rather than 'home.php'. I
then went to each function containing either a DB query (ore one which calls
another DB-related function. I did a global search and replace for the
function name 'func(' replaced by 'func($pg,'. I use Dreamweaver so this was
fairly straightforward.
It worked for me, but now someone is about to show me a quicker, cleaner
way, aren't they?
Yes, I am.
?php
function checkpoint()
{
$trace = debug_backtrace();
$caller = isset( $trace[0] ) ? $trace[0] : array();
$owner = isset( $trace[1] ) ? $trace[1] : array();
$file
= isset( $caller['file'] )
? $caller['file']
: null;
$class
= isset( $owner['class'] )
? $owner['class']
: null;
$function
= isset( $owner['function'] )
? $owner['function']
: null;
$line
= isset( $caller['line'] )
? $caller['line']
: null;
$type
= isset( $owner['type'] )
? $owner['type']
: null;
list( $timeSub, $time ) = explode( ' ', microtime() );
$timeSub = ereg_replace( '^[^.]\.', '', $timeSub );
$timeSub = substr( str_pad( $timeSub, 6, '0' ), 0, 6 );
echo 'Checkpoint '
.'['.date( 'Y-m-d H:i:s', $time ).'.'.$timeSub.']: '
.($file === null
? ''
: $file.' ')
.($line === null
? ''
: sprintf( '{%05d} ', $line ))
.($class === null
? ''
: $class.$type)
.($function === null
? ''
: $function.'()')
.$this-nl;
}
?
I often use the above function when debugging code. It prints detailed
information about where it was called. I have something similar in my
error handler but it's not as concise for error related reasons.
It doesn't strike me as an issue that it's a heavy function since it's
used in a debugging context or when an error is present. In which case,
it shouldn't be called in production at least not often :)
Cheers,
Rob.
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RE: [PHP] Which file called the function?
Richard is right.
If you want to get where __FILE__ is exactly in, __FILE__ is the option.
Else, use $_SERVER['PHP_SELF']. (And this should be what you expected)
Regards,
Shelley
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Christoph Boget
Sent: Thursday, December 20, 2007 10:37 PM
To: PHP General
Subject: [PHP] Which file called the function?
Let's say I have the following 3 files
global.php
?
function myFunc() { echo __FILE__; }
?
one.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
two.php
?
include( 'global.php' );
echo 'You are in file: ';
myFunc();
?
In each case, what is echoed out for __FILE__ is global.php. Apart from
analyzing the debug_backtrace array, is there any way that myFunc() would
display one.php and two.php respectively?
thnx,
Christoph
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