Re: [PHP] Best way to split a string of numbers into segments.
preg_match should do it...
$mydate = 20031202;
$date = array();
preg_match(/(\d{4})(\d{2})(\d{2})/, $mydate, $date);
print_r($date);
substr would be much quicker though
On Tue, 2003-12-02 at 13:14, Tom wrote:
Hi.
Is there an easy, non expensive way to do the perl-equivalent of:
$date=20031202;
($year, $month, $day) = ($date =~ /(\d{4})(\d{2})(\d{2})/;
I looked through the preg_* functions online, but couldn't see anything
to help me. Am I stuck with substr() :P ?
Thanks.
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Re: [PHP] Best way to split a string of numbers into segments.
On Tue, 02 Dec 2003 13:14:20 +, you wrote:
Is there an easy, non expensive way to do the perl-equivalent of:
$date=20031202;
($year, $month, $day) = ($date =~ /(\d{4})(\d{2})(\d{2})/;
I looked through the preg_* functions online, but couldn't see anything
to help me. Am I stuck with substr() :P ?
list() springs to mind
list ($a, $b, $c) = preg_split (/* mumble mumble */);
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Re: [PHP] Best way to split a string of numbers into segments.
I agree that preg_match generates an array, but I cannot assign to it
directly,
and in your example I have 4 elements in the array, not three.
Array
(
[0] = 20031202
[1] = 2003
[2] = 12
[3] = 02
)
I suppose something like
preg_match(/(\d{4})(\d{2})(\d{2})/, $mydate, list($y,$m$d));
Is vaguely what I am gunning for.
And substr()...
$date = 20031202;
$year = substr($date,0,4);
$month = substr($date,3,2);
$day = substr($date,5,2);
That seems like a lot of lines of code, and I am believe that substr()
is expensive.
Maybe I have been doing too much perl, as it seems such a neat solution
to me :P
preg_match should do it...
$mydate = 20031202;
$date = array();
preg_match(/(\d{4})(\d{2})(\d{2})/, $mydate, $date);
print_r($date);
substr would be much quicker though
On Tue, 2003-12-02 at 13:14, Tom wrote:
Hi.
Is there an easy, non expensive way to do the perl-equivalent of:
$date=20031202;
($year, $month, $day) = ($date =~ /(\d{4})(\d{2})(\d{2})/;
I looked through the preg_* functions online, but couldn't see anything
to help me. Am I stuck with substr() :P ?
Thanks.
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Re: [PHP] Best way to split a string of numbers into segments.
David Otton wrote:
On Tue, 02 Dec 2003 13:14:20 +, you wrote:
Is there an easy, non expensive way to do the perl-equivalent of:
$date=20031202;
($year, $month, $day) = ($date =~ /(\d{4})(\d{2})(\d{2})/;
I looked through the preg_* functions online, but couldn't see anything
to help me. Am I stuck with substr() :P ?
list() springs to mind
list ($a, $b, $c) = preg_split (/* mumble mumble */);
Hi David.
Yes, list() was, initially, my starting point. But preg_split() will not
allow me split with the
full /(\d{4})(\d{2})(\d{2})/ syntax (and assign the temp vars to thos in
list().
Unless I missed something?
$date=20031202;
list ($a, $b, $c) = preg_split (/(\d{4})(\d{2})(\d{2})/);
parse error, unexpected '/', expecting ')'
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Re: [PHP] Best way to split a string of numbers into segments.
list ($a, $b, $c) = preg_split (/(\d{4})(\d{2})(\d{2})/);
note the 's
list ($a, $b, $c) = preg_split (/(\d{4})(\d{2})(\d{2})/);
parse error, unexpected '/', expecting ')'
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Re: [PHP] Best way to split a string of numbers into segments.
list(, $year, $month, $day) =
Tom wrote:
I agree that preg_match generates an array, but I cannot assign to it
directly,
and in your example I have 4 elements in the array, not three.
Array
(
[0] = 20031202
[1] = 2003
[2] = 12
[3] = 02
)
I suppose something like preg_match(/(\d{4})(\d{2})(\d{2})/,
$mydate, list($y,$m$d));
Is vaguely what I am gunning for.
And substr()...
$date = 20031202;
$year = substr($date,0,4);
$month = substr($date,3,2);
$day = substr($date,5,2);
That seems like a lot of lines of code, and I am believe that substr()
is expensive.
Maybe I have been doing too much perl, as it seems such a neat solution
to me :P
preg_match should do it...
$mydate = 20031202;
$date = array();
preg_match(/(\d{4})(\d{2})(\d{2})/, $mydate, $date);
print_r($date);
substr would be much quicker though
On Tue, 2003-12-02 at 13:14, Tom wrote:
Hi.
Is there an easy, non expensive way to do the perl-equivalent of:
$date=20031202;
($year, $month, $day) = ($date =~ /(\d{4})(\d{2})(\d{2})/;
I looked through the preg_* functions online, but couldn't see anything
to help me. Am I stuck with substr() :P ?
Thanks.
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Re: [PHP] Best way to split a string of numbers into segments.
From the manual preg_split
Returns an array containing substrings of subject split along boundaries
matched by pattern.
since you dont have any borders, this is unlikely to help you
the only was i can see to do it is a quite long way
$mydate = 20031202;
$date = array();
preg_match(/(\d{4})(\d{2})(\d{2})/, $mydate, $date);
list($x, $y, $d, $m) = $date;
echo $d. / .$m. / .$y .\n;
Mike
On Tue, 2003-12-02 at 15:15, Tom wrote:
I have noted the 's.
Could you send me a complete piece of code, please?
I cannot for the life of me get it to work, at all.
Mike wrote:
list ($a, $b, $c) = preg_split (/(\d{4})(\d{2})(\d{2})/);
note the 's
list ($a, $b, $c) = preg_split (/(\d{4})(\d{2})(\d{2})/);
parse error, unexpected '/', expecting ')'
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